The horizontal surface on which the block of mass 2.2 kg slides is frictionless. The force of 27 N acts on the block in a horizontal direction and the force of 81 N acts on the block at an angle as shown below is the magnitude of the resulting ac celeration of the block? The acceleration of gravity is 9.8 m/s ^ 2

Answers

Answer 1
Answer: To determine the magnitude of the resulting acceleration of the block, we need to resolve the forces acting on the block into their horizontal and vertical components.

The force of 27 N acts horizontally, so its horizontal component is 27 N.

The force of 81 N acting at an angle needs to be resolved into its horizontal and vertical components. The horizontal component is given by 81 N * cosθ, where θ is the angle between the force and the horizontal direction. Since the angle is not specified in the question, we cannot determine the exact value of the horizontal component without that information.

Once we have the horizontal components of the forces, we can calculate the net horizontal force acting on the block by summing up all the horizontal components. In this case, the only horizontal force is the force of 27 N, so the net horizontal force is 27 N.

Using Newton's second law, F = ma, where F is the net force and m is the mass of the block, we can solve for the acceleration.

a = F / m
a = 27 N / 2.2 kg
a ≈ 12.27 m/s^2

Therefore, the magnitude of the resulting acceleration of the block is approximately 12.27 m/s^2.

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A ray of light is projected into a glass tube that is surrounded by air. The glass has an index of refraction of 1.50 and air has an index of refraction of 1.00. At what minimum angle will light in the glass tube be totally reflected at the glass/air interface?

Answers

Answer:

θ = 41.8º

Explanation:

This is an internal total reflection exercise, the equation that describes this process is

         sin θ = n₂ / n₁

where n₂ is the index of the incident medium and n₁ the other medium must be met n₁> n₂

        θ = sin⁻¹ n₂ / n₁

let's calculate

       θ = sin⁻¹ (1.00 / 1.50)

       θ = 41.8º

on a high way a car is driven 80 km the first 1 he of travel, 50km during the next 0.5 he, and 40 km in the final 0.5 hr. What is the cars average speed for the entire trip?

Answers


Average speed = (total distance covered) / (total time to cover the distance) .

Total distance = (80 + 50 + 40) = 170 km

Total time = (1 + 0.5 + 0.5) = 2 hours

Average speed = (170 km) / (2 hrs)= 85 km/hr .
 

How many times can disposable gloves be worn before being discarded?

Answers

Final answer:

Disposable gloves are designed for single use and should be discarded after each task to prevent cross-contamination or reduced effectiveness from damage. They should not be reused.

Explanation:

In general, disposable gloves are designed to be used once and then thrown away. They should be removed and discarded after handling a task, then a new pair of gloves should be worn for a different task. This is because reusing disposable gloves can lead to cross-contamination or the gloves becoming less effective if they become damaged from continuous use. For instance, if a person wears the same gloves while treating a patient and then handling medical equipment, bacteria and other harmful substances can spread, creating a risk to health. Therefore, it is crucial to practice accurate and responsible use of disposable gloves in healthcare settings and other scenarios where gloves are required for safety and hygiene purposes.

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What is the mass of a falling rock if it produces a force of 147 n?
F=
M=
A=

Answers

F=147N;

Acceleration=9.8m/s2;

Mass=15kg

Romeo ( mass = 70 kg ) feels a gravitational attraction for Juliet ( mass = 50 kg ). If hey are 20 m apart, find the force.

Answers

What even is this question
Love? Idk lol

Describe all the forces acting on an elevator as it moves from rest upward and stops at its floor.

Answers

The force which acts on the elevator while it starts its motion are described as follows :

1. The elevator when starts from rest, moves in a direction opposite to the gravity, hence there is an upward force which acts on the elevator. It is more than the weight due to gravity of the elevator to cause the motion. This upwards force is the force produced by the strings pulling the elevator upwards.

2. The downwards force is the weight of the elevator which is being imposed due to the gravity of the Earth to pull everything towards it, and the mass of the elevator. This downward force is less than the upward force.

3. When the elevator stops, the upward force and downward force are equal but opposite in magnitude.

Final answer:

An elevator experiences tension in the supporting cable, weight of the elevator, upward force from the floor, and gravitational force as it moves upward from rest. As it accelerates, the tension in the cable is larger than the weight making the elevator and its occupants feel heavier. Conversely, as it decelerates to stop, they feel lighter due to reduced force exerted on the floor and scale.

Explanation:

When an elevator moves upward from rest to it's designated floor, it experiences several forces. The primary forces here include the tension in the supporting cable (T or I), the weight of the elevator (we), the upward force from the floor of the elevator or the normal force (N or Ñ), and the gravitational force which is usually represented by the weight of the person (w) and the weight of the scale (ws).

While the lift is still or moving at a constant speed, the tension in the cable (T or I) and the weight of the elevator are equal but opposite, so they cancel out. But, as the elevator begins to ascend, the tension in the cable must overcome the weight hence it's larger causing the elevator to accelerate upwards. When the elevator approaches the destined floor and begins to decelerate, the tension eases and becomes lesser than the weight.

In relation to the person in the elevator, when the elevator is at rest or moving at consistent speed, the person experiences their normal weight. When the elevator accelerates upwards, the person feels slightly heavier due to the increased force they exert on the floor (Fp or I) and subsequently on the scale (Fs). When the elevator decelerates to stop, the force they exert on floor and scale becomes less and, thus, they feel slightly lighter.

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