True or False?-If two rectangles have equal areas, then they are congruent.
-If two squares have equal perimeters, then they have equal areas.

Answers

Answer 1

Answer: #1

That is false..one could have side lengths of 9 and 1, and the other could have side lengths of 3. Both the areas would be 9, but the figures would not be congruent.

#2

That is true, they must both have the same side length to have the same perimeter, therefore they will also have the same area.

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Hayden graphed the following linear function on an (x,y) coordinat plane. g(x) = 3x -4.5 What is the y-intercept of the graph of this function? Write the numerical value.

Answers

-4.5 if you were to graph the linear function.

Identify each expression that represents the slope of a tangent to the curve y= -x^3+17x^2-x+3 at any point (x,y).

Answers

This is seriously so long I'm not sure it will even fit on a single line. The formula for the derivative using the limiting process is $\lim_(h \to 0) (f(x+h)-f(x))/(h)$ . And of course this is a problem because if h approaches 0, we would have a 0 in the denominator of that fraction and that is definitely not allowed! Every x in the function will be replaced with (x+h) to give us this: $\lim_(h \to 0) (-(x+h)^3+17(x+h)^2-(x+h)+3)/(h)$ . When we expand that we will get this very long numerator (I'm purposely leaving out the limit as h approaches 0 part to save space): $(-(x^3+2x^2h+xh^2+x^2h+2xh^2+h^3)+17x^2+34xh+17h^2-x-h+3-(-x^3+17x^2-x+3))/(h)$ . Simplifying that leaves us with this: $(-x^3-2x^2h-xh^2-x^2h-2xh^2-h^3+17x^2+34xh+17h^2-x-h+3+x^3-17x^2+x-3)/(h)$ . We have a lot of terms that cancel each other out so when we do that we are left with $\lim_(h \to 0) (-3x^2h-3xh^2-h^3+34xh+17h^2-h)/(h)$ . That is one of your choices for answers, the third one down on the left to be specific. Now we can factor out an h: $\lim_(h \to 0) (h(-3x^2-3xh-h^2+34x+17h-1))/(h)$ . That h on the top outside the parenthesis cancels with the h on the bottom. Now, as h approaches 0 we have no problems! Yay! That means when we now replace h with 0, we have this: $-3x^2-0-0+34x+0-1$ , or simplified we have $-3x^2+34x-1$ which is also a choice for your answers, top one on the right. Those are your 2 answers for that dertivative. It's much simpler when you learn the rules!

Which of the following is equiangular and equilateral?A. rhombus
B. square
C. rectangle
D. parallelogram

Answers

I think its B because squares has equal sides and angles

Square is the correct answer

write an equation in standard form for the line that passes through the points (4,5) and has a slope m= 2/3

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$standard\ form: \ Ax+By=C\n\nslope\ intercept\ form:\ny=mx+b\nm=(2)/(3)\n\ny=(2)/(3)x+b\ \ \ \ | substitute\ point\ (4,5)\n\n5=(2)/(3)*4+b\n\n5=(8)/(3)+b\ \ \ \ | subtract\ (8)/(3)\n\n5-(8)/(3)=b\n\nb=5-2(2)/(3)=2(1)/(3)\n\ny=(2)/(3)x+2(1)/(3)\ \ \ | subtract\ (2)/(3)x\n\nSolution:\ -(2)/(3)x+y=2(1)/(3)$

Which one represents translation

Answers

Answer:

The third one

Step-by-step explanation:

Translation is when it moves

Which is a counterexample for the conditional statement shown?If the numerator of a fraction is larger than the denominator of the fraction, then the fraction is greater than 1.

any fraction with a denominator of O

any fraction with a numerator of O

any fraction with a positive numerator and a negative denominator

any fraction with a negative numerator and a positive denominator