72 raisin cookies sold of Ratio 9:1 to oatmeal cookies sold. How many cookies combined sold

Answers

Answer 1
Answer: •Find the amount of oatmeal cookies sold
Since the Ratio is 9:1
9=72 raisin cookies sold
1=? oatmeal cookies sold
Using cross multiplication
?=(72x1)/9=8
Hence, 8 oatmeal cookies were sold.
•Find the amount of combined cookies sold
72+8=80
So, a total of 80 cookies were sold.

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PLEASE HELP ASAP 15 BRAINLY POINTS1) (multiple answers pick two) Does the equation represent a direct variation? If so, identify the constant of variation.17y = 85xA) YesB) No C) 5D) 1/5 2) Determine whether the relationship is a direct variation. X : 3, -1 , -4Y : -6, 2, 8 A) yes B) No 3) Is the relationship shown a direct variation? (it's not absolute value is a table chart) | X  | Y || -2 | 5  || 1  | 3  || 4  | 1  |A) yes B) No 4) Determine whether the relationship is a direct variation.------------------------------| X |   6    |   9    |   17  |-------------------------------| Y | 13.2 | 19.8 | 37.4 | -------------------------------A) yes B) no5) Determine which equation does NOT represent a direct variation.A) 6x - y = 0 B) y = 4x + 1 C) y = -2x D) y = 1/3x6) (multiple answer pick 2) Tell whether the equation represents a direct variation. If so identify the constant of variation. y + 3x = 0A) Yes B) No C) -3D) 1/3 E) 3
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When rolling two standard cubes (6-sided die), what is the probability that you roll sum of 11? Convert your answer to decimal form, then round to 3 decimal places

Answers

Answer:

Step-by-step explanation:

There are only two ways to roll a sum of 11 (5,6),(6,5) out of 36 possible outcomes so

P(11)=2/36=1/18

as a rounded decimal 0.056

Multiplying polynomials
find the product
(5n+6)(5n-5)

Answers

(5n+6)(5n-5) =5n\cdot 5n -5n\cdot 5+6\cdot 5n-6\cdot 5=\n \n=25n^2-25n+30n-30 =25n^2+5n-30


The solution of expression after multiplying is,

⇒ 25n² + 5n - 30

We have to given that,

To multiplying polynomials is,

⇒ (5n + 6) (5n - 5)

Now, We can multiply as,

⇒ (5n + 6) (5n - 5)

⇒ 5n × 5n + 5n × - 5 + 6 × 5n + 6 × - 5

⇒ 25n² - 25n + 30n - 30

⇒ 25n² + 5n - 30

Therefore, The solution is,

⇒ 25n² + 5n - 30

Learn more about the multiplication visit:

brainly.com/question/10873737

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Jane worked 32 hours in one week. If she worked the same number of hours each day for 4 days, how many hours a day did she work? A. 8
B. 6
C. 10
D. 4

Answers

4x=32⇒ x=32/4⇒ x=8

the answer is A. 8
You need to divide, so 32/4=8, so your answer is A.8

Can someone help me with this? PLs i'm so confused!

Answers

1. E. sine\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (5)/(13)

2. L. cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (12)/(13)

3. tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (5)/(12)

4. Y. sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (5)/(13)

5. W. cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (12)/(13)

6. tan\ B = (b)/(a) = (adjacent)/(opposite) = (AC)/(BC) = (12)/(5) = 2(2)/(5)

7. sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(2)

8. W. cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (√(3))/(2)

9. I. tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(√(3)) = (1)/(√(3)) * (√(3))/(√(3)) = (√(3))/(3)

10. sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(2)

11. E. cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (√(3))/(1) = √(3)

12. I. tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(√(3)) = (1)/(√(3)) * (√(3))/(√(3)) = (√(3))/(3)

13. U. sin\ A = (a)/(c) = (hypotenuse)/(opposite) = (BC)/(AB) = (12)/(15) = (4)/(5)

14. I. cos\A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (9)/(15) = (3)/(5)

15. tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (12)/(9) = (4)/(3) = 1(1)/(3)

16. R. sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (4)/(√(65)) = (4)/(√(65)) * (√(65))/(√(65)) = (4√(65))/(65)

17. M. cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (7)/(4) = 1(3)/(4)

18. N. tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (4)/(7)

19. L. sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (16)/(34) = (8)/(17)

20. H. cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = \fac{AC}{AB} = (30)/(34) = (15)/(17)

21. tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (16)/(30) = (8)/(15)

22. O. sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(√(2)) = (1)/(√(2)) * (√(2))/(√(2)) = (√(2))/(2)

23. O. cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (1)/(√(2)) = (1)/(√(2)) * (√(2))/(√(2)) = (√(2))/(2)

24. N. tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(1) = 1

Write the equation in slope-intercept form. What are the slope and y-intercept? -11x + 9y = -12

Answers

-11x + 9y = -12
9y = -12 + 11x
y = -12/9 + 11/9x

y = (11/9)x - 4/3

Y-intercept is -4/3
Slope or m is 11/9

jared bought a package of pens containing 20 pens.  If 3/4 of the pens had black ink, how do you determine the number of pens with black ink?

Answers

well 1/4 of the pens would be 5 (20/4=5)
so 3/4 would be 5x3= 15
15 of the pens have black ink

wouldn't you take .75 multiplied by 20? .75 is 3/4 obviously.