Karissa eats 400 bananas per day. using f(x)=400x•422, where x is the amount of time in days, and f(x) is the amount of potassium in karissa's bones in Mg. how much radiation has she built up over 14 days, if there is 0.1 mSv of radiation per 422 milligrams of potassium.equation: f(x)=400x•422

Answers

Answer 1

Answer:

Answer:

560 mSv of radiation

Step-by-step explanation:

To calculate how much radiation Karissa has built up over 14 days, we need to first calculate the amount of potassium in her bones after 14 days. We can do this using the function f(x):

$\sf f(x) = 400x \cdot 422$

where x is the amount of time in days, and f(x) is the amount of potassium in Karissa's bones in milligrams.

To calculate the amount of potassium in Karissa's bones after 14 days, we would simply substitute x = 14 into the function:

f(14) = 400 × 14 × 422

f(14) = 2363200 milligrams

Now that we know how much potassium is in Karissa's bones, we can calculate how much radiation she has built up.

We know that there is 0.1 mSv of radiation per 422 milligrams of potassium, so we can simply multiply the amount of potassium in Karissa's bones by 0.1 mSv/422 mg to calculate the amount of radiation she has built up:

$\begin{aligned} \textsf{Radiation amount }&= \sf 2363200 milligrams * 0.1 mSv/422 mg \n\n & = \sf 560 mSv \end{aligned}$

Therefore, Karissa has built up 560 mSv of radiation over 14 days.

Answer 2

Answer:

Step-by-step explanation:

Substituting x = 14, we have f(14) = (400)(14)(422) = 2,363,200 mg of Potassium accumulated.

This is equivalent to (2363200)(0.1/422) = 560 mSv of radiation.

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How to combine fraction

Answers

$\Large \frac { x }{ y }$ $\begin{matrix} \rightarrow numerator \n \rightarrow denominator \end{matrix}$

If two (or more) fractions have the same number as their denominator, you can just go ahead and add their numerators, without changing the denominator. For example:

$\frac { 1 }{ 2 }$ and $\frac { 4 }{ 2 }$ has the same number (2) as their denominator. So we will add their numerators, without changing the denominator.

$\frac { 1 }{ 2 } +\frac { 4 }{ 2 } \quad =\quad \frac { 1+4 }{ 2 } \quad =\quad \frac { 5 }{ 2 }$

So we added the numerators (1 + 4 = 5) and kept the denominator same (2) and we got ( $(5)/(2)$

This was the case where the fractions' denominator was same. What if it's not ?

If their denominator isn't equal, we're gonna have to equalize them ourself. How to do that ?

Let's show it with an example :

$\frac { 1 }{ 2 }$ and $\frac { 3 }{ 4 }$ do no have the same number as their denominator. To be able to add them, we have to equalize their denominators.

$\frac { 1 }{ 2 }$ 's denominator is 2 and $\frac { 3 }{ 4 }$ 's is 4

What can we do to equalize them ? Well, 4 is two times 2 ( $4 = 2\cdot 2$ ) So we cane multiply the denominator of $\frac { 1 }{ 2 }$ (which is 2) with 2 , to equal it to $\frac { 3 }{ 4 }$ 's denominator (which is 4).

But, there is a catch here. When multiplying a fraction's denominator before adding it to another, you should make sure that you're preserving its ratio. What does that mean ?

Let's take the number $\frac { 4 }{ 6 }$

(1) if we multiply only its numerator with a number (let it be 3)

$\frac { 3\cdot 4 }{ 6 } \quad =\quad \frac { 12 }{ 6 } \quad =\quad 2$

You got a new fraction with a different ratio than $(4)/(6)$ . And it is also equal to 2, but $(4)/(6)$ isn't equal to 2.

(2) if we multiply only its denominator with a number (let it be 3 again)

$\frac { 4 }{ 3\cdot 6 } \quad =\quad \frac { 4 }{ 18 }$

You got a new fraction again, with a different ration than $(4)/(6)$ .

How can we know that ? Well, if you simplify these two numbers to the simplest number, you'll get a different fraction or integer. Let's do so.

$\frac { 4 }{ 6 } \quad =\quad \frac { 2\cdot 2 }{ 2\cdot 3 } \quad =\quad \frac { 2 }{ 2 } \cdot \frac { 2 }{ 3 } \quad =\quad 1\cdot \frac { 2 }{ 3 } \quad =\quad \frac { 2 }{ 3 }$

So the simplified form of $(4)/(6)$ in the fraction form is $(2)/(3)$

$\frac { 4 }{ 18 } \quad =\quad \frac { 2\cdot 2 }{ 2\cdot 9 } \quad =\quad \frac { 2 }{ 2 } \cdot \frac { 2 }{ 9 } \quad =\quad 1\cdot \frac { 2 }{ 9 } \quad =\quad \frac { 2 }{ 9 }$

And the simplest form of $(4)/(18)$ as a fraction is $(2)/(9)$ , which is not equal to $(2)/(3)$

$\frac { 2 }{ 3 } \quad \neq \quad \frac { 2 }{ 9 }$

So what to do, to preserve the ratio ? Simle. We'll multiply also the numerator with the same number we're going to multiply the denominator with.

Let's get back to our example.

Adding $\frac { 1 }{ 2 }$ and $\frac { 3 }{ 4 }$

We were going to multiply $(1)/(2)$ 's denominator with 2. Now that we know, the ratio must not change, we'll also multiply the numerator with 2.

$\frac { 2\cdot 1 }{ 2\cdot 2 } \quad =\quad \frac { 2 }{ 4 }$

Now we've got a number which has the same denominator as $\frac { 3 }{ 4 }$

We can add them now,

$\frac { 2 }{ 4 } \quad +\quad \frac { 3 }{ 4 } \quad =\quad \frac { 2+3 }{ 4 } \quad =\quad \frac { 5 }{ 4 }$

$\boxed { \frac { 1 }{ 2 } \quad +\quad \frac { 3 }{ 4 } \quad =\quad \frac { 5 }{ 4 } }$

I hope this was clear, if not please ask and I'll try to explain.

What numbers add to one and multiply to negative twelve

Answers

4 and negative 3. is the answer

Q:What is the indicated term of the arithmetic sequence? someone help!!!!
a14 for 200,196,192...
A:
a. 148
b. 252
c. 144
d. 239

Answers

$a_1=200;\ a_2=196;\ a_3=192\n\nr=a_2-a_1\to r=126-200=-4\n\na_n=a_1+(n-1)r\n\na_n=200+(n-1)\cdot(-4)=200-4n+4=204-4n\n\na_(14)=204-4\cdot14=204-56=148\n\nAnswer:A$