. 222/86 Rn decays by emission of an alpha particle. The product of this decay is A. 226/88 Ra B. 218/84 Po C. 218/88 Ra D. 220/86 Rn

Answers

Answer 1

Answer:

The product of an alphadecay of 222/86 Rn is 218/84 Po (option B).

What is an alpha decay?

Alphadecay is a type of radioactive disintegration in which some unstable atomic nuclei dissipate excess energy by spontaneously ejecting an alpha particle.

An alphaparticle is a positively charged nucleus of a helium-4 atom emitted as a result of radioactivity. It has a formula of 4/2 He.

This suggests that when a 222/86 Rn undergoes alphadecay, the product will have mass and atomic number as follows:

Mass no.: 222 - 4 = 218
Atomic no.: 86 - 2 = 84

The element with atomic number 84 is Polonium (Po).

Therefore, option B is correct.

Learn more about alpha decay: brainly.com/question/35140893

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1-Propanol is combusted to provide heat. The equation and the enthalpy change for the process are shown below. C₃H₇OH(l)+4.5O₂( g)→3CO₂( g)+4H₂O(l)ΔH=−2,021 kJ Below is a list of sentences that describe a chemical process. Choose all of the sentences that apply to the above rea Check all that apply. a This process is exothermic. b The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is 2,021 kJ c The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is −4,042 kJ d The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is −2,021 kJ e This chemical process transfers heat from the surroundings to the system. f The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is 4,042 kJ g This process is endothermic. h This chemical process transfers heat from the system to the surroundings.

Answers

Explanation:

Let's analyze the statements one by one:

a) This process is exothermic.

True. The negative enthalpy change (-2,021 kJ) indicates that heat is released during the reaction, making it exothermic.

b) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 2,021 kJ.

False. The balanced chemical equation and enthalpy change given are for the combustion of 1 mole of propanol, not 2 moles.

c) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -4,042 kJ.

False. This statement suggests a doubled enthalpy change value in the wrong direction. The correct direction is negative (exothermic), but the magnitude is not doubled.

d) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -2,021 kJ.

False. This statement suggests the correct direction but doubles the magnitude. The correct magnitude is -2,021 kJ for 1 mole of propanol.

e) This chemical process transfers heat from the surroundings to the system.

False. The process is exothermic, which means it releases heat from the system to the surroundings.

f) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 4,042 kJ.

False. This statement suggests the correct magnitude but in the wrong direction. The correct direction is negative (exothermic).

g) This process is endothermic.

False. The process is exothermic, as indicated by the negative enthalpy change.

h) This chemical process transfers heat from the system to the surroundings.

True. An exothermic process like this releases heat from the system to the surroundings.

So, the correct statements are:

a) This process is exothermic.

e) This chemical process transfers heat from the surroundings to the system.

h) This chemical process transfers heat from the system to the surroundings.

MethaneProteinAlcohol can be found in beer, wine and liquor.

Answers

The correct answer is alcohol. It is the common component in beer, wine and any liquor. Usually, alcohol is produced by fermentation of organic products containing glucose to produce alcohol, specifically ethanol, as the important product and the by-products water and carbon dioxide.

Answer:

What is true when two reactants combine in an exothermic reaction?

Answers

Rxn releases energy in the form of heat or light.
Which is the opposite of an endothermic rxn because endo. rxn requires energy to form the product.

Which of the following combinations will result in a reaction that is spontaneous at all temperatures?positive enthalpy change and positive entropy change
positive enthalpy change and negative entropy change
negative enthalpy change and positive entropy change
negative enthalpy change and negative entropy change

Answers

The right answer for the question that is being asked and shown above is that: "negative enthalpy change and negative entropy change." The combination that will result in a reaction that is spontaneous at all temperatures is negative enthalpy change and negative entropy change

Answer:

Spontaneous at ALL Temperatures: Negative enthalpy change and positive entropy change

I promise this is 100% correct. I just took the Honors Entropy quiz and I got the question correct.

The other answer provided by the verified user Hagrid is incorrect.

In a very violent reaction called a thermite reaction, aluminum metal reacts with iron (III) oxide to form iron metal and aluminum oxide according to the following equation:

Answers

Here's the equation:
Fe2 O3 + 2Al → 2Fe + Al2 O3

Here's the question.
What mass of Al will react with 150g of Fe2 O3?

In every 2 moles Al you need 1 mole Fe2O3

moles = mass / molar mass
moles Fe2O3 = 150 g / 159.69 g/mol
= 0.9393 moles

moles Al needed = 2 x moles Fe2O3
= 2 x 0.9393 mol
= 1.879 moles Al needed

mass = molar mass x moles
mass Al = 26.98 g/mol x 1.879 mol
= 50.69 g
= 51 g (2 sig figs)

So the mass of Al that will react with 150g of Fe2 O3 is 51 grams.

How is geometrical symmetry related to the polarity of a molecule?

Answers

A symmetric shape means the bonds' polarities are exactly equal then it means the polarities cancel each other, resulting to a nonpolar molecule. This is because there will be no available polarity for other substance to attach.

Explanation :

As we know that the geometrical symmetry of the molecule and the polarity of the bonds both are equally important for determining the polarity of the molecule.

The molecule that has zero dipole moment that means it is a geometrical symmetric molecule and the molecule that has some dipole moment that means it is a geometrical asymmetric molecule.

As the molecule is symmetric, the dipole moment will be zero and the molecule will be non-polar.

As the molecule is asymmetric, the dipole moment will not be zero and the molecule will be polar.

Thus, we can say that the a symmetry molecule is non-polar in nature and an asymmetry molecule is a polar molecule.

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