CHEMISTRY HIGH SCHOOL

What is the displacement of 40 meters?

Answers

Answer 1

Answer:

Answer:

Along with solving the question, I'll try to clear the concepts involved.

Distance: Total path actually traversed by the object.

Distance is a scalar quantity. Hence, No need to consider the direction.

Here the object…

First travelled 30 m towards East & then travelled 40 m towards North.

Distance = 30 m + 40 m = 70 m

Related Questions

How many grams are in 11.9 moles of chromium
Which of the following does not describe natural migration?Pls I really need help
What is the energy change that will occur when 25.5 grams of oxygen gas (O2) react with excess methane (CH4) according to the reaction below? CH4 + 2 O2yields CO2 + 2 H2O delta H = -889 kJ/mol Select one: a. 354 kJ of energy will be given off by the reaction b. 354 kJ of energy will be absorbed by the reaction c. 708 kJ of energy will be given off by the reaction d. 708 kJ of energy will be absorbed by the reaction
Is polythene a conductor or an insulator (eletricity)
What is a chemical change

12.42 m +421.0 m + 9.28 m -

Answers

Answer:

442.7m

Explanation:

12.42m+421.0m+9.28

442.7m

What is an oxpecker bird eats insects off the back of a rhinoceros

Answers

Actually when the oxpecker bird eats insects off the back of the rhinoceros. They are helping each other. The bird gets a nutritious snack while the rhinoceros gets those pesty and annoying bugs off of him. This is also called a Symbiotic relationship. When both organisms of different species work together to benefit the other.
hope this helps:)
and dont forget 2
MARK ME BRAINLIEST!
=)

What net ionic equation describes the reaction when these solutions are mixed?Given the equation: Na3PO4 (aq) + CaCl2(aq) →

A. 2PO43–(aq) + Cl– (aq) → Cl2(PO4)3(s)
B. 2Ca2+(aq) + Na+(aq) → NaCa2(s)
C. Na+(aq) + Cl– (aq) → NaCl(s)
D. 2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Answers

I think the correct answer from the choices listed above is option D. The net ionic equation that will describe the reaction of the reactants when mixed is expressed as:

2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Hope this answers the question. Have a nice day.

Answer:

$2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)$

Explanation:

In net ionic equation we remove the spectator ions. The ions which are present on both the side and are not forming any solid compound.

Let us write the balanced reaction first:

$2Na_(3)PO_(4)(aq)+3CaCl_(2)(aq)-->3Ca_(3)(PO_(4))_(2)+6NaCl(aq)$

The ionic reaction is:

$6Na^(+)(aq)++6Cl^(-)(aq)+2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)+6Na^(+)(aq)+6Cl^(-)(aq)$

Thus net ionic reaction is

$2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)$

Write the formula of the following chemical compounds: i. Calcium phosphate ii. Ammonium carbonate

Answers

i - Ca3(PO4)2
ii- (NH4)2CO3

How would you solve this problem??

Answers

Calculate the pOH where [OH⁻]=4.7×10⁻³M:
pOH=-log[OH⁻]
pOH=-log(4.7×10⁻³)
pOH=2.33

Calculate [OH⁻] if the pOH is 1.34:
pOH=-log[OH⁻]
10^(-pOH)=[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10^(-1.34)
[OH-]=0.0457M or [OH⁻]=4.57×10⁻²M

Calculate pH if the [OH⁻] is 1.74×10⁻²M:
[H⁺]=K(w)/[OH⁻] or pOH=-log[OH⁻]
[H⁺]=(1×10⁻¹⁴)/(1.57×10⁻²) pOH=-log(1.74×10⁻²)
[H⁺]=6.369×10⁻¹³M pOH=1.759
pH=-log[H⁺] pH=14-pOH
pH=-log(6.369×10⁻¹³) pH=14-1.759
pH=12.2 pH=12.2

I hope this helps. Let me know if anything is unclear.

if you are finding the value of a 10 g piece of metal that has a value of 5 dollars/ 1 gram what would be my final unit