QUESTION 6 6.1 The following marks out of 50 were scored by learners in a Mathematics test. 41 33 26 14 45 23 24 27 13 33 12 6.1.1 Write down the range. 6.1.2 What is the modal mark? 6.1.3 Calculate the mean of the marks correct to two decimal places. 6.1.4 Determine the median mark.​

Answers

Answer 1
Answer:

Answer:

The range of a set of numbers is the difference between the highest and lowest values. In this case, the highest mark is 45 and the lowest mark is 6.1.1 Therefore, the range is 45 - 6.1.1 = 38.9.

Step-by-step explanation:

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Two triangles that have the same side lengths will always be congruent.A. True
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Answers

True, this is in accordance to the side-side-side postulate.

A sign in a store window has the shape of a regular nonagon (9-sided figure). The sign has an apothem length of 40 cm and a side length of 29 cm.What is its area?

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Answers

Area = A
Side length = L = 29 cm
number of sides = n = 9
Apothen = a = 40 cm

A = nLa / 2 = 9*29cm*40cm / 2 = 5,220 cm^2

Answer: 5,220 cm^2

Answer:

5220 cm

Step-by-step explanation:

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Simplify the expression z2-z(z+3)+3z

Answers

z^2-z(z+3)+3z=\n z^2-z^2-3z+3z=\n 0

Write the standard equation of the circle with the given center that passes through the given point. Center (-2,6); point (-2,10)

Answers

The general form of the equation of a circle is given by:
(x-a)²+(y-b)²=r²
where:
(a,b) is the center
r is the radius
Given that the circle with center (-2,6) and cuts point (-2,10), the equation of the circle will be found as follows:
the radius of the circle will be:
r=√[(x-a)²+(y-b)²]
r=√[(-2-(-2))²+(10-6)²]
r=√[(-2+2)²+4²]
r=√[0+4²]
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hence plugging the values to obtain the equation we get:
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simplifying we get:
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Answers

Answer:

Rs 12

Step-by-step explanation:

According to what I have understood;

13/100*4000= Rs Rs 512

So, Rs 4000 plus its VAT is

4000+ 512= Rs 4512

Then we need to find the difference, That is

Rs 4512 - Rs 4000= Rs 12

Answer:13/100x×4000=4500

13x×40=4500

480x=4500

x=4500/480

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Answers

It is not a circle but you can find the equation of the ellipse.
To do this we need to work out the major and minor radii and the centre
The centre is at (9, 7)
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