CHEMISTRY HIGH SCHOOL

Mass of 1 Bean = 0.328 gramsMass of ALL Jellybeans = 865 grams
To find the number of jellybeans we use unit conversion.
What belongs in the green box?
865 grams x 1 bean

Answers

Answer 1
Answer:

Explanation:

To find the number of jellybeans, you need to use unit conversion. The green box should contain the following expression:

865 grams / 0.328 grams per bean

This expression represents the total mass of all jellybeans (865 grams) divided by the mass of one jellybean (0.328 grams per bean), which gives you the number of jellybeans.

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Which of the following explains the importance of the activation energy acting as a barrier for reactants?

Answers

The energy needed for a chemical reaction is called the activation energy. This energy is to be present in order for the reaction to happen. This can be achieved by supplying or releasing heat from a system of reactants. This can achieved faster by using a catalyst.

When one compound dissolves in water, the only positive ion produced in the solution is H3O+(aq). This compound is classified as(1) a salt
(2) a hydrocarbon
(3) an Arrhenius acid
(4) an Arrhenius base

Answers

Answer : The correct option is, (3) an Arrhenius acid

Explanation :

According to the Arrhenius concept, an acid is a substance which ionizes in the water to give hydronium ion (H_3O^+) or hydrogen ion (H^+) and a base is a substance which ionizes in the water to give hydroxide ion (OH^-).

When one compound dissolves in water, then only positive ion produced in the solution is (H_3O^+). This compound is classified as an Arrhenius acid.

Hence, the correct option is, (3) an Arrhenius acid
When one compound dissolves in water, the only positive ion produced in the solution is (aq). This compound is classified as an Arrhenius acid.

How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mass solution? Show all of the work needed to solve this problem.

Answers

M1m1 = M2m2

where M1 is the concentration of the stock solution, m1 is the mass of the stock solution, M2 is the concentration of the new solution and m2 is its new mass.

M1m1 = M2m2

.925(m1) = .35(250)

m1 = 94.59 g

Answer: 94.59 grams of 92.5 % H_2SO_4 by mass solution will be needed.

Explanation:

Mass of sulfuric acid is 250 grams of 35 % by mass solution:

35=(x)/(250 g)* 100

x=87.5 g

Mass of H_2SO_4 in 250 g of 35 % solution = 87.5 g

Mass of 92.5 % H_2SO_4 needed to make 35 % by mass solution.

92.5=\frac{87.5 g}{\text{mass of the solution required}}* 100

Mass of the solution required = 94.59 g

94.59 grams of 92.5 % H_2SO_4 by mass solution will be needed.

At stp what element is a good conductor of electricity?

Answers

copper is a good conductor

How many grams of acetylene react if 1.10 mol of CO2 are produced?

Answers

 Combustion of acetylene :

molar mass acetylene ( C₂H₂ ) = 26.0 g/mol and CO₂ = 44.0 g/mol

2 C₂H₂ + 5 O₂ ---> 4 CO₂ + 2 H₂O

2 moles C₂H₂ --------> 4 moles CO₂
? moles C₂H₂ --------> 1.10 moles CO₂

moles C₂H₂ = 1.10 * 2  / 4

moles C₂H₂ = 0.55 moles of C₂H₂

Mass acetylene:

m = n * mm

m = 0.55 * 26.0

m = 14.3 g

hope this helps!

What are 3 reasons scientist found Rutherford's nuclear atomic model to be fundamentally incomplete

Answers

The three reasons that scientists found Rutherfor's nuclear atomic model to be fundamentally incomplete are as follows:
Number 1) according to Rutherford, the electrons revolve in completelycircular orbits. However, if this was true the charged electron wouldsimply fall into the nucleus after losing energy.
Number 2)According to Rutherford's model, the nucleus itself only consisted ofprotons. However, as we now know due to research in quantum mechanics,if this was true this would make the atom unstable due to the cycle ofattraction and repulsion.
Number 3) The neutrons which have alsobeen discovered since to be an important part of the atom, are notmentioned at all in Rutherford's model.

The correct answer is:

1.how electrons are organized in a cloud

2. why electrons are not attracted into the positively charged nucleus

3. variations in chem behavior between elements

Explanation:

Rutherford reversed Thomson's model in 1911 with his popular gold foil research in which he confirmed that the atom has a tiny and massive nucleus. Rutherford created an experiment to practice the alpha particles released by a radioactive element as probes to the underground world of atomic structure.
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