Helppp please help.
Answers
im pretty sure measure wherever the bottom of the curved line is :)
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How many moles of I2 are in 8.23 moles of NaI ?
Which compound reacts with an acid to produce water and a salt(1) CH3Cl (2) CH3COOH (3)KCl (3)KOH
Which of the following ions has a smaller size? Option 1: O2- Option 2: F- Option 3: They have the same size. Option 4: None of the above.
Answers
Answer:
Ka = 1.5 -10^-5
Explanation:
Step 1: Data given
Molarity of the solution = 0.25 M
pH = 2.71
Step 2 The equation
C3H7COOH + NaOH ⇆ C3H7COONa + H2O
Step 3: Calculate pKa
pH = (pKa-log[acid])/2
2pH = pKa -log[acid]
pKa = 2pH +log[acid]
⇒with pH = 2.71
⇒with log[acid] = -0.60
pKa=2*2.71 -0.60
pKa = 5.42 - 0.60
pKa = 4.82
Step 4: Calculate Ka
pKa = -log(Ka)
Ka = 10^-4.82
Ka = 1.5 -10^-5
Answers
c. condensation
b. sublimation
d. solidification
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The answer to your question
b. sublimation
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Here is a step-by-step explanation of the reaction:
1. Acetyl chloride (CH3COCI) is an acylating agent that reacts with the amino group (-NH2) of p-
aminophenol (C6H4NH2OH). The
acetyl chloride is a source of the acety group (CH3CO-), which will replace the amino group in p-aminophenol.
2. Pyridine (C5H5N) is used as a catalyst in this reaction. It helps in the formation of the acety group by removing the hydrogen ion (Ht) produced during the reaction, making the reaction proceed more efficiently.
3. Electrons on the amino group of p-aminophenol acts as the nucleophile and attacks the carbony carbon of the acetyl chloride.
4. The carbonyl carbon is electron-deficient, so it readily accepts the lone pair of electrons from the amino group, forming a new bond. At the same time, the chlorine atom of acetyl chloride is displaced as a leaving group.
5. The resulting product is N-acety-p-aminophenol (C6H4NHCOCH3). In
this compound, the acetyl group is attached to the nitrogen atom of p-aminophenol, replacing the amino group. The pyridine catalyst remains unchanged and is not part of the final product.
Overall, the reaction between p-aminophenol and acetyl chloride in the presence of pyridine leads to the formation of N-acety -p-aminophenol, an amide compound.
Final answer:
The reaction of p-aminophenol with one mole of acetyl chloride in the presence of pyridine results in the formation of an amide compound.
Explanation:
The reaction of p-aminophenol with one mole of acetyl chloride in the presence of pyridine leads to the formation of an amide compound. This reaction is known as acylation, where the acetyl chloride acts as the acylating agent and reacts with the amino group of p-aminophenol to form an amide bond.
Learn more about Acylation reaction here:
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Answers
Molar mass= 12.01(4) + 1.01(10)
= 58.14g/mol
Moles=14.5g / 58.14g/mol
=0.249
Therefore there are approx 0.249 moles in a 14.5g sample of C4H10