Mg(s) + 2HCI(aq) -> MgCl2(aq) + H2(g) a. How many grams of HCI are consumed by the reaction of 2.50 moles of magnesium? Given: Requested:

Answers

Answer 1

Answer:

Answer:2.50 moles of magnesium will consume approximately 182.30 grams of hydrochloric acid in the given reaction.

Explanation:To find out how many grams of hydrochloric acid (HCl) are consumed when 2.50 moles of magnesium (Mg) react with it, you can use stoichiometry and the balanced chemical equation:

Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)

From the balanced equation, you can see that 1 mole of magnesium (Mg) reacts with 2 moles of hydrochloric acid (HCl).

Now, let's use this information to calculate the moles of HCl required to react with 2.50 moles of Mg:

Moles of HCl = (2.50 moles Mg) * (2 moles HCl / 1 mole Mg)

Moles of HCl = 2.50 moles * 2

Moles of HCl = 5.00 moles

Now that we know we need 5.00 moles of HCl, we can calculate the grams of HCl needed using the molar mass of HCl:

The molar mass of HCl is the sum of the atomic masses of hydrogen (H) and chlorine (Cl):

Molar mass of HCl = 1.01 g/mol (for hydrogen) + 35.45 g/mol (for chlorine)

Molar mass of HCl = 36.46 g/mol

Now, calculate the grams of HCl:

Grams of HCl = (5.00 moles) * (36.46 g/mol)

Grams of HCl = 182.30 grams

So, 2.50 moles of magnesium will consume approximately 182.30 grams of hydrochloric acid in the given reaction.

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Answers

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The correct answer is

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Which word equation shows lithium oxide being formed from the reaction between oxygen and lithium?1.)oxygen + lithium oxide to lithium

2.)lithium + oxygen to lithium oxide

3.)oxygen + lithium to lithium + oxide

4.)lithium oxide to lithium + oxygen

Answers

The correct answer is the second option. The wordequation that would represent the formation of lithium oxide from lithium metal and oxygen is:

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Inchemical symbols, the balanced chemical equation is expressed as:

Li + O2 = Li2O

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Explanation :

When the lithium react with the oxygen to give lithium oxide as a product.

The balanced chemical reaction will be,

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This reaction can be represented in words as,

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Answers

Food consumption affects the rate of alcohol absorption in the bloodstream.

Explanation:

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When you consume alcohol on the associate empty abdomen, the alcohol is sometimes absorbed within the blood among fifteen minutes to two-and-a-half hours. If you have got a moderate quantity of food in your abdomen once you drink, that speed slows all the way down to thirty minutes to a few hours. If you’re drinking on a full abdomen, alcohol absorption ranges from 3 to 6 hours.

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#1: Which of the following is the abbreviation for a unit of energy? A. K / B. °C/ C. W / D. cal............... #2: A 200 g block of a substance requires 1.84 kJ of heat to raise its temperature from 25°C to 45°C. Use the table attached to identify the substance. A. iron/ B. aluminum/ C. gold/ D. copper.....................#3: In a calorimeter, the temperature of 100 g of water decreased by 10°C when 10 g of ice melted. How much heat was absorbed by the ice? A. 418 kJ / B. 100 kJ / C. 10 J / D. 4.18 kJ ..................#4: The amount of heat needed to raise the temperature of 50 g of a substance by 15°C is 1.83 kJ. What is the specific heat of the substance? A. 2.44 J/g-°C / B. 2.22 J/g-°C / C. 2.13 J/g-°C / D. 2.05 J/g-°C ................#5: In a calorimeter, 3.34 kJ of heat was absorbed when 10 g of ice melted. What is the enthalpy of fusion of the ice? A. 6.68 J/g / B. 334 J/g / C. 6.68 kJ/g/ D. 334 kJ/g

Answers

Among the choices, the unit of energy is calories. Answer in 1) is D. In 2) we are given with te mass , heat and temperature change. we just need to get the heat capacity and compare it with the following metals. The calculated heat capacity is 0.46 kJ/kg K. The answer is A. iron. In 3) we can compute the heat absorbed by the formula ΔH=mCpΔT. Cp of water is 4.18 J/g K. Answer of 3) is D. In 4) the formula used in Cp=ΔH/mΔT. Answer in 4) is A. The heat of enthalpy of fusion of ice is 80 cal/g. We convert this to J/g. Answer in 5) is B.334 J/g.

Answer:

1. D. cal......

2.A. iron

3. D

4.2.44j/g°C A

5,Lf=334J/g B

Explanation:

1: Which of the following is the abbreviation for a unit of energy? A. K / B. °C/ C. W / D. cal...............

calorie is the unit of energy

#2: A 200 g block of a substance requires 1.84 kJ of heat to raise its temperature from 25°C to 45°C. Use the table attached to identify the substance. A. iron/ B. aluminum/ C. gold/ D. copper.....................

Q=mcdt

1840=0.2*C*(45-25)

C=460J/KgK

if the specific heat capacity is the above then he substance is iron

#3: In a calorimeter, the temperature of 100 g of water decreased by 10°C when 10 g of ice melted. How much heat was absorbed by the ice? A. 418 kJ / B. 100 kJ / C. 10 J / D. 4.18 kJ .................

Q=mcdT

Q=0.1*10*4180

Q=4180j. answer D

.#4: The amount of heat needed to raise the temperature of 50 g of a substance by 15°C is 1.83 kJ. What is the specific heat of the substance? A. 2.44 J/g-°C / B. 2.22 J/g-°C / C. 2.13 J/g-°C / D. 2.05 J/g-°C ................

Q=mcdT

1830=50/1000*C*15

C=2440j/kg/k

change it to j/g°C

2.44j/g°C A

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Q=mLf

Lf=enthalpy of fusion

3340/10=Lf

Lf=334J/g B

Enthalpy of fusion quantity of heat to convert 1 unit mass of a solid to liquid without any noticeable change in temperature.

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