Solve by the method of your choice: 8x - 2y = 26 5x + y = 23

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Plz help fast Question 1(Multiple Choice Worth 5 points) (8.01 LC) Two lines, A and B, are represented by the equations given below: Line A: x + y = 6 Line B: x + y = 4 Which statement is true about the solution to the set of equations? There are infinitely many solutions. There is no solution. It is (6, 4). It is (4, 6).
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Round 14.235 to the nearest tenth

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it is 14.100 because you are rounding down so you round 2 down to 1

in order to meet the sample assumption associated with parametric statistics, how many subjects are needed?

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In order to meet the sample assumption associated with parametric statistics, the number of subjects needed depends on the specific statistical test being used. Generally, the rule of thumb is to have a minimum of 30 subjects in each group being compared.

However, this number may increase or decrease depending on factors such as the effect size, variability in the data, and the statistical power desired.

It is important to have enough subjects so that the data is normally distributed, and there is enough content loaded to meet the assumptions of the statistical test.

To know more about statistics refer here

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What is 49 to the negative power 1/2?

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So say you have just 49 raised to the 1/2, that is equivocal to the square root of 49, which is 7. Instead, you have 49 raised to the negative half power, so all you need to do is move that term to the denominator of its fraction. You now have 1/49^(1/2) which turns out to be 1/7

49^-1/2
=1/49^1/2
= 1/Square root of 49
=1/7

Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 6

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The given function is

f(x)= log 10 x

Taking base as 10

$y=\log_(10)10 +\log_(10)x$ →→Using the property of, log a b= log a + log b

→y = 1 + $\log_(10)x$ as, $\log_(10)10=1$

we have to approximate the value of y in the equation

→10 y = 6

→y= $(6)/(10)$

$(6)/(10)$ = 1 + $\log_(10)x$

$\log_(10)x$ = $(-4)/(10)$

x= $(10)^{(-4)/(10)}$ = $(10)^(-0.4)$ =0.398

Solving graphically,

we get , x= 0.398 for , y= $(6)/(10)$ =.6

f(x) = ㏒(10x)
f(x) = ㏒₁₀(10x)

10y = 6
10 10
y = 0.6

f(x) = ㏒₁₀(10x)
0.6 = ㏒₁₀(10x)
$10^(0.6) = 10x$
$10^{(3)/(5)} = 10x$
$\sqrt[5]{10^(3)} = 10x$
$\sqrt[5]{1000} = 10x$
$\frac{\sqrt[5]{1000}}{10} = x$
$(3.98)/(10) \approx x$
$0.398 \approx x$

Which browser feature will delete your history, cache, and cookies the moment you close the special window? 1) Incognito Mode 2) Private Browsing 3) Delete Browsing History 4) Clear Cache and Cookies

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The answer is 1) Incognito mode

The amount of postage placed on a first class letter depends on the weight of the letter .

Answers

amount is directly proportional to weight
thus
A = kw    A = amount
   k = constant ^ which is price per gram
   w = weight

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Make u the subject of the formula v^2=u^2+2as. thanks xx