Simplify, using the correct order: 180 / (30 + 60) - 1

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Y'all I need help it's on Plato PLS HELPwhat's the answer ​
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I need help,, and thanks☺

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Use the law of cosines. c^2= a^2 + b^2 - (2ac*cos (C))

$25;300%increse percent change

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well and 300% increase means you multiply by 3 and then add the original number


in this case 300% of 25 is 75 and its an increase so 25+75=100

the answer is 100

Jane is 7 years older than John.If the sum of their ages is 43.How old is Jane and how old is John​

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Answer:

If

Jane= x

John = y

y+7= x

x-y=7 ---- (1)

x+y=43 --- (2)

(1) + (2),

x-y+x+y=7+43

2x=50

x= 50÷2

x= 25

substituting x= 25 in (2),

25+y=43

y= 43-25

y= 18

Jane is 25 years old and John is 18 years old.

Step-by-step explanation:

Suppose the diameter of a circle is 6. What is its circumference

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the formula for circumference is: C=pi(3.14)*d(diameter)

so multiply pi and 6 and you should get...

18.84

Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of years since the iguanas were introduced into the garden.i(x) = 12(1.9)^x


Rewrite this function in a form that reveals the monthly growth rate of the population of iguanas in the garden. Round the growth factor to the nearest thousandth.

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Answer:

i(x)=12 * (1+(0.9)/(12))^(12x) and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 * (1.9)^(x), where x is the number of years.

Since, i(x)=12 * (1.9)^(x)

i.e. i(x)=12 * (1+0.9)^(x).

Therefore, the monthly growth rate function becomes,

i.e. i(x)=12 * (1+(0.9)/(12))^(x * 12).

i.e. i(x)=12 * (1+(0.9)/(12))^(12x).

Hence, the monthly growth rate is i.e. i(x)=12 * (1+(0.9)/(12))^(12x).

Also, the growth factor is given by (0.9)/(12) = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

In the function f (x)=(x-2)^2+4, the minimum value occurs when x is... (a) -2(b) 2
(c) -4
(d) 4

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Hello,

y=a(x-h)²+k has the vertex (h,k)
If a>0 it is a minimum
if a<0 it is a maximum

Here h=2 and k=4

The minimum is 2
Answer B.