i) 737 K = 463.85 °C
ii) -265 °F = -165 °C
Converting 737 K into °C :
As we know Absolute zero (0K) is equivalent to -273. 15 °C. Hence,
K = °C + 273.15
Or,
°C = K - 273.15
Putting value of K,
°C = 737 - 273.15
°C = 463.85 °C
Converting -265 °F into °C :
As,
°F = °C × 1.8 + 32
So,
°C = °F - 32 ÷ 1.8
Putting value of °F,
°C = -265 - 32 ÷ 1.8
°C = -165 °C
Answer: the first ionization energy decreases.
Justification:
1) The group 15 is formed by N, P, As, Sb, Bi, and Mc.
2) The first ionization energy is defined as the energy needed to remove an electron from the neutral atom in the gas state.
3) The elements of the group 15 have the following general electron configuration for the valence shell: ns² np³. Where n is the principal quantum number (the same number of the row in which the element is).
4) As you go down in the group, n increases, and the valence electrons are further away of the nucleous, meaning that those electrons are lessen attracted to the nucleous.
Consequently, as you go down in the group, the electrons will be removed more easily, i.e less energy will be required to get them removed.
5) That permits you to predict this order in the first ionization energies: N > P > As > Sb > Bi > Mc.
And that agrees with the data that you can find in a table of first ionization energies.
As atomic number increases, first ionization energy in Group 15 elements initially rises due to increasing nuclear charge, then decreases because of larger atomic radius, and finally increases again due to stronger attraction between cations and remaining electrons.
The first ionization energy refers to the energy necessary to remove an electron from a neutral atom. As we consider the first five elements in Group 15 in order of increasing atomic number, there's a trend that emerges regarding first ionization energy. Initially, the ionization energy increases. This is due to an increasing effective nuclear charge that tightens the hold on the electrons, making it more energy-consuming to remove them.
Then, there's a decrease in ionization energy. This is caused by the additional energy level of electrons, which increases atomic radius and reduces the impact of nuclear charge - it's easier to remove an electron from a larger, higher-energy orbital. Following this, the ionization energy starts increasing again. This is because unrelated to size, it becomes increasingly difficult to remove additional electrons which have a greater electrostatic attraction to the cation that's formed.
#SPJ11
0.02
0.002
0.2
0.0002
Answer : The correct option is, 0.02
Explanation :
The scientific notation is a way of the representation of the very small or very large number.
The given scientific notation is,
That means,
Hence, the scientific notation of has 0.02 value.
Answer:
B
Explanation:
The final position of the curve is higher than the original height of the curve, meaning the products have more energy than the reactants.
Hence energy was added for the reactants to become the products. This is why the reaction is endothermic, because the products retained some of the supplied energy.
Part of the energy supplied was used to overcome the activation energy (the peak of the curve). However, this extra energy is recuperated as heat once the product is formed.
Answer:
B-
Heat was added to create the product
Explanation:
Just did the quiz on edg
Answer:
Explanation:
A physical property is a property that can be observed without changing the composition.
Some examples of physical properties are:
Now, let's examine our answer choices.
Choice A: Sugar is white in color
Choice B: Iron is more dense than aluminum
Choice C: Diamond is harder than graphite.
Since all three choices depict physical properties, the best choice is D. All of the above.
Answer:
D
Explanation:
All explain physical no chemical examples were given
Answer:
Less than
Explanation:
The process of dissolution occurs as a kind of "tug of war". On one side are the solute-solute and solvent-solvent interaction forces, while on the other side are the solute-solvent forces.
Only when the solute-solvent forces are strong enough to overcome the pre-mixing forces do they overcome the "tug of war", and thus dissolution occurs.
Thus, it is concluded that the interaction forces between solute particles and solvent particles before they are combined are less than the interaction forces after dissolution.
For the dissolution of the soluteparticles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.
In a solution the forces act between the solute molecules, solvent molecules, and solute-solvent molecules. For the dissociation to take place the bond between the solute and solvent has to be formed. The resultant will result in the dissolution of the solute in the solvent mixture. The strong solute-solute and solvent-solvent bond will result in difficulty in the formation of the solute-solvent bond, and the dissolution will not take place.
Thus for the dissolution of the solute particles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.
For more information about dissolution, refer to the link:
For the whole set of problems, always remember the Avogadro’s number is 6.023*10^23 units per mole of a substance. Units could be atoms, molecules or formula units.
The first question asks for the number of molecules of NaNO3. The molar mass of NaNO3 is 85 grams per mole. So,
150g NaNO3(1mole NaNO3/85 grams NaNO3)(6.023*10^23 molecules/1mole NaNO3)=1.063*10^24 molecules of NaNO3
5.7*10^46 molecules of NaNO3(1mole NaNO3/6.023*10^23 molecules)(85 grams NaNO3/1mole NaNO3) = 8.044*10^24 grams NaNO3
For the molar mass of water, we have 18.02grams per mole.
301 moles H2O(18.02 grams H2O/1 mole H2O) = 5424.02 grams H2O
For the molar mass of sulfuric acid, we have 98.08 grams per mole.
25g H2SO4(I mole H2SO4/98.08g H2SO4) = 0.2549 mole H2SO4
For the molar mass of Ca(OH)2, we have 74.1 grams per mole.
252gCa(OH)2(1mol/74.1g)(6.023*10^23/1mol) = 2.048*10^24 molecules of Ca(OH)2
For the molar mass of calcium, we have 40 grams of Ca per mole.
6.7*10^35 atoms Ca(1 mole Ca/6.023*10^23 atoms)(40g Ca/1mol Ca) = 4.45*10^13 grams Ca