Solve for x
3x+1/14=2x/8

Answers

Answer 1

Answer: 3x+(1/14)= 2x/8
24x+(4/7)=2x ( i multiplied everything by 8)
22x+4/7=0 ( i subtracted 2x to both sides)
22x= -4/7 ( i subtracted 4/7 to both sides)
x= (-4/7)/ 22
x= -2/77

Answer 2

Answer: $3x + (1)/(14) = (2x)/(8)$

First, you multiply everything by 8, so you get:
$8(3x + (1)/(14)) = 8( (2x)/(8))$

Then, you develop, and you get:
$24x + (8)/(14) = 2x$

You simplify $(8)/(14)$ by dividing by 2, and you get:
$24x + (4)/(7)$ = 2x

Then, you put known numbers apart (numbers without x), and unknown numbers apart (numbers with x), which means you move 2x to the other part (and it become -2x), and $(4)/(7)$ to the other part ( and it become $- (4)/(7)$ ), so you get:
$24x - 2x = - (4)/(7)$

you subtract and you get:
$22x = - (4)/(7)$

then, you move 22 to the other part, and since it's a multiplication, it become a division, so you get:
$x = ( - (4)/(7) )/(22)$

As you know, $22 = (22)/(1)$ , and dividing 2 fraction is equal to multiplying the first fraction by the inverse of the second fraction, so you get:
$-(4)/(7) * (1)/(22) = x$

You multiply and you get:
$- (4)/(154) = x$

4 and 154 have a common factor which is 2, so you divide each one by 2, and you get:
$-(4/2)/(154/2) = x$

you divide, and you get:
$-(2)/(77) = x$

So, $x = -(2)/(77)$

Hope this Helps! :D

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It's not a really a question but how to solve these types of questionsLet f(x) = 9x − 2 and g(x) = −x + 3. Find f(g(x)).

Let f(x) = 2x + 2. Solve f−1(x) when x = 4.

Let f(x) = x + 8 and g(x) = x2 − 6x − 7. Find f(g(2)).

Let f(x) = x2 − 8x + 5. Find f(−1).

Answers

Answer:

Part 1) $f(x) = 9x- 2$ and $g(x) = -x + 3$

Find f(g(x)).

$f(x) = 9x- 2$

Substitute value of g(x) in place of x

$f(g(x)) = 9(-x+3)- 2$

$f(g(x)) = -9x+27- 2$

$f(g(x)) = -9x+25$

So, $f(g(x)) = -9x+25$

Part 2) $f(x) = 2x + 2$

$y = 2x + 2$

Replace y with x and x with y

$x = 2y + 2$

Find y

$(x-2)/(2) = y$

So, $f^(-1)(x)=(x-2)/(2)$

Substitute x = 4

$f^(-1)(4)=(4-2)/(2)$

$f^(-1)(4)=1$

Part 3) $f(x) = x + 8$ and $g(x) = x^2- 6x-7$

$f(x) = x + 8$

Substitute value of g(x) in place of x

$f(g(x)) =x^2- 6x-7 + 8$

$f(g(x)) =x^2- 6x+1$

Substitute x = 2

$f(g(x)) =2^2- 6(2)+1$

$f(g(x)) =4- 12+1$

$f(g(x)) =-7$

Part 4) $f(x) = x^2-8x + 5$

Substitute x = -1

$f(-1) = (-1)^2-8(-1) + 5$

$f(-1) =14$

1. 9(-x+3) - 2
3.[ (2)2 - 6(2) - 7] + 8
4.(-1)2 - 8(-1) + 5

How do I do x/3-x/9=6 Pls solve with steps

Answers

Answer:

Step-by-step explanation:

Hello,

do you agree that

$(1)/(3)-(1)/(9)=(3-1)/(9)=(2)/(9)$ ?

Then,

we can simplify as below and multiply by 9 both sides and divide by 2

$(x)/(3)-(x)/(9)=(2x)/(9)=6\n\n<=> 2x = 54\n\n<=> x = 54/2= 27$

Thanks

Find all solutions to the equation.

sin x = sqrt(3)/2

Answers

Answer:

$x=(\pi)/(3) and x=(2\pi)/(3)$

Step-by-step explanation:

We are given that $sin x=(\sqrt3)/(2)$

We have to find all solutions of the given equation

We know that $sin (\pi)/(3) =sin60^(\circ)=(\sqrt3)/(2)$

sin x is positive then the value of sin x will lie in I quadrant and II quadrant.The value of sin x is negative in III and IV quadrant .

We are given that sin x is positive then the solution will lie in I and II quadrant only.Therefore, the solution of sin x will not lie in III and IV quadrant .

$sin x =sin (\pi)/(3)$ ...(I equation )and $sin x =sin(\pi-(\pi)/(3))$ ...(II equation)

In II quadrant $\theta$ change into $(\pi-\theta )$

Cancel sin on both side of equation I

Then, we get

$x=(\pi)/(3)$

$sin x =sin ((3\pi-\pi)/(3))$

$sin x =sin (2\pi)/(3)$ ...(II equation )

Cancel sin on both side of equation II

Then we get

$x=(2\pi)/(3)$

Hence, the solutions of equation are

$x=(\pi)/(3) and x=(2\pi)/(3)$

The solutions of the equation are:

x = 60 degrees

x = 120 degrees

x = 420 degrees

x = 480 degrees, and so on.

We have,

The solutions to the equation sin(x) = √3/2 are any angles where the sine of the angle is equal to √3/2.

So,

sin 60 = √3/2

sin 120 = sin (π - 60) = sin 60 = √3/2

In trigonometry 180 is written as π.

Since (π - 60) is in the secondquadrant sin 60 is positive.

sin 420 = sin (360 + 60) = sin 60 = √3/2

In trigonometry 360 is written as 2π.

Since (2π + 60) is in the Firstquadrant sin 60 is positive.

Similarly,

sin 480 = sin (2π + 120) = sin 120 = sin (π - 60) = sin 60 = √3/2

Thus,

The solutions of the equation are:

x = 60 degrees

x = 120 degrees

x = 420 degrees

x = 480 degrees, and so on.

Learn more about solutionsofequations here:

brainly.com/question/545403

#SPJ6

Given the function:f(x) = –3x^2 + 4

What is the additive inverse function of f(x)?

A. g(x) = –3x^2 – 4
B. g(x) = –4x^2 – 3
C. g(x) = 3x^2 – 4
D. g(x) = 4x^2 + 3

Answers

Answer:C

Step-by-step explanation:

Answer:c:g(x)=3x^2-4

Step-by-step explanation:

Suppose 6 is a factor of ab, where a and b are natural numbers. Make a valid argument to explain why each assertion is true or provide a counterexample to show that an assertion is falsea. 6 must be a factor of a or of b
b. 3 must be a factor of a or of b
c. 3 must be a factor of a and of b

please help and show work

Answers

example
if ab=6
and a=3
b=2

a. 6 must be factor of 3 or 2 FALSE
b. 3 must be a factor of 3 OR 2 TRUE
c. 3 must be a factor of 3 AND 2 FALSE

B is true

A graph in visual form that expresses the important characteristics of a situation and does not necessarily have numerical values is?