CHEMISTRY HIGH SCHOOL

how many millimeters of the approximately 0.014 M copper (ll) sulfate solution are needed to prepare 100.00 milliliters of a 0.00028 M copper (ll) sulfate solution

Answers

Answer 1
Answer:

Answer:

To calculate the volume of the approximately 0.014 M copper (II) sulfate solution needed to prepare 100.00 milliliters of a 0.00028 M copper (II) sulfate solution, you can use the formula:

(Volume 1)(Concentration 1) = (Volume 2)(Concentration 2)

So, rearranging the formula, you can solve for Volume 1 (the volume of the 0.014 M solution):

Volume 1 = (Volume 2)(Concentration 2) / Concentration 1

Plugging in the values:

Volume 1 = (100.00 milliliters)(0.00028 M) / 0.014 M

Volume 1 ≈ 2.00 milliliters

Approximately 2.00 milliliters of the approximately 0.014 M copper (II) sulfate solution are needed to prepare 100.00 milliliters of a 0.00028 M copper (II) sulfate solution.

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Cold packs are used to treat minor injuries. Some cold packs contain NH4NO3(s) and a small packet of water at room temperature before activation. To activate this type of cold pack, the small packet must be broken to mix the water and NH4NO3(s). The temperature of this mixture decreases to approximately 2°C and remains at this temperature for 10 to 15 minutes.State the direction of heat flow that occurs when the activated cold pack is applied to the body.
Identify both types of bonds in the NH4NO3(s).

Answers

These types of reactions are called endothermic reactions. This is when the system absorbs the heat from the surrounding. In this case, the system is the chemical reaction and the environment is the direct vicinity of the chemical reaction. You notice that the pack becomes cold because heat from the surrounding is being absorb. 

The bonds involved in this substance includes ionic bonding and polar covalent. 

A piece of wood and a piece of steel are at the same temperature; however, the steel feels hotter. This is because the steel has _____. A- more entropy
B- greater thermal conductivity
C- greater thermal insulation
D- a higher R-value

Answers

Answer: The correct answer is "greater thermal conductivity".

Explanation:

Thermal conductivity: It is a ability to conduct heat. Heat transfers occur at a lower rate to material at higher thermal conductivity.

It is defined as the rate at which the heat is transferred through a unit thickness of the substance per area per change in the temperature.

In the given problem, A piece of wood and a piece of steel are at the same temperature. However, the steel feels hotter. The thermal conductivity of the steel is more than the thermal conductivity of the wood.

Therefore,  the correct option is "greater thermal conductivity".

B- Greater thermal conductivity

Which of these is an appropriate instrument to measure mass?balance
burette
ruler
graduated cylinder

Answers

The appropriate instrument to measure mass is through the use of a balance. This type of equipment is different from your regular weighing scale. The balance actually measures based on a known mass unlike the weighing scale which measures only the weight of an object.

Answer: Balance

Explanation: Got it right on my test

Which ion is the only negative ion produced by an Arrhenius base in water?(1) NO3– (3) OH–
(2) Cl– (4) H–

Answers

The correct answer is option 3. It is the hydroxide ions that is produced by an Arrhenius base in water. According to Arrhenius, acid-base reactions are characterized by acids which forms hydronium ions in water and bases which dissociates in aqueous solution to form hydroxide ions. 

would you select water or gasoline to try dissolving the following : table sugar, motor oil, rubber from tire marks, adhesive residue from a packing tape

Answers

To know the answer, we determine the polarities of the solvent we have. Water is polar and gasoline is nonpolar. We remember that like dissolves like. Therefore, the answers are:

table sugar = water
motor oil = gasoline
rubber from tire marks = gasoline
adhesive residue from a packing tape = gasoline

Answer:

table sugar: water

motor oil: gasoline

rubber from tire marks: gasoline

adhesive residue from a packing tape: gasoline

Explanation:

Like dissolves like so a polar compound will dissolve in a polar solvent and a non polar compound will dissolve in a non-polar solvent. The intermolecular forces of attraction are responsible for the dissolution of substances in different solvents.  

For example, polar solute exhibit hydrogen bonding and dipole interaction with polar solvents (water). Non-polar solute exhibit London dispersion forces with non-polar solvents(gasoline).

How many moles of atoms are in 6.00 g of 13C?

Answers

There are 0.462 moles of atoms in 6.00 g of carbon-13.

Further Explanation:

Moles, Atomic mass and Molecular mass  

  • 1 mole of a pure substance contains a mass that is equal to the relative atomic mass or molecular mass of the substance.
  • Therefore; molar mass is given as grams per mole of a substance  
  • Hence;

Molar mass = mass of a substance/ Number of moles

     g/mol = g /mole

  • Thus:

M = m/n; where M is the molar mass, m is the mass and n is the number of moles

  • From this relationship we can therefore, calculate mass by multiplying the number of moles by molar mass of a substance.
  • That is; Mass = moles x molar mass
  • To calculate number of moles;

We have; n = m/M

  • Number of moles = Mass of the substance/ Molar mass

In our case;

Mass = 6 g of Carbon-13

Molar mass = 13.0 g/mol

Since; Number of moles = Mass/ molar mass

Thus;

Moles = (6.0 g)/ (13.0 g/mol)

          = 0.462 moles  

Keywords: Moles, Molecular mass, relative atomic mass  

Learn more about:

Level: High school

Subject: Chemistry

Topic: Moles

Sub-topic: Moles, molecular mass and mass of a pure substance

Answer: 0.462 moles

Explanation: 13C indicates an isotope of carbon and its mass number is 13. It means the mass of 1 mol of 13C is 13 gram.

The question asks to calculate the number of atoms present in 6.00 grams of 13C.

To calculate the number of moles we divide the given grams by the mass of 1 mol of the element. The set could be shown easily using dimensional analysis as:

6.00gram((1mol)/(13gram))

= 0.462 moles

So, there will be 0.462 moles of atoms in 6.00 grams of 13C.

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