Natasha and Jorge were asked to find the quotient to the decimal division problem 18.8÷1.6 . Natasha says her answer is 11.75. Jorge says his answer is 1.175. a. Who is correct? Natasha or Jorge? b. Explain how you know who is correct. Include in your explanation at least one possible error the student who was incorrect made

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What is the product and quotuent for 24.6 and 1.2

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Quotient: 20.5

Product: 29.52

0.8% as a decimal and fraction.

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Step 1: 0.8 = 8⁄10
Step 2: Simplify 8⁄10 = 4⁄5

Alexei wants to hang a mirror in his boat, and put a frame around it. The mirror and frame must have an area of 19.25 square feet. The mirror is 3 feet wide and 5 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?

Answers

Answer:

4.25 sq ft.

Step-by-step explanation:

Answer:

The answer is: 4x^2 + 16x − 4.25 = 0

Please, can you help.... I'm really confused. I need an answer really fast. Thank you

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Answer:

Mean for Labradors: 65

Step-by-step explanation:

This is how to find the M.A.D.

Step 1. Find the mean. To do that, you add all the numbers and divide that number by how many numbers you have which is 10. All the numbers together is 650. That divided by 10, is 65. That is your mean.

Step 2. Once you have that, subtract the mean from all 10 numbers.

Step 3. Find the mean of the 10 numbers which you have subtracted 65 (the mean) from. If the number you subtracted is a negative, make it a positive.

a juggler throws a ball into the air, releasing it 5 feet above ground with an initial velocity if 15 fps. she catches the ball in thr other hand 5 feet above the ground. How long was the ball in the air?

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Final answer:

The juggled ball was in the air for roughly 0.94 seconds. Using the principles of projectile motion and gravity, you calculate the time for the ball to rise to its peak and then double this value to get the total time the ball is in the air as it follows the same path back down.

Explanation:

The question is about determining the time a juggled ball stays in the air when thrown up at a particular speed and height. The principles of projectile motion and gravity apply here. The time taken for the ball to rise and fall back to the same height can be found using the physics concept of free fall. While the ball is in the air, it rises and then falls to a final position which is equal to its starting altitude. This is because the ball is thrown and caught at the same height.

From the facts we have, the initial vertical speed is 15 fps (feet per second). Since the acceleration due to gravity is -9.8 m/s² or approximately -32.2 fps² (note that it is negative as it is acting downward), we can use the following equation of motion which is derived from Newton's second law:

final velocity = initial velocity + (acceleration x time)

In this case, the final velocity when the ball reaches the peak of its flight is 0 (since it stops for a moment before falling again), and the acceleration is -32.2 fps². If we rearrange the equation to solve for time (t), we get:

t = (Final velocity - Initial velocity) / acceleration. Substituting the values we get:

t = (0 - 15) / -32.2 = 0.47 s

This is the time taken for the ball to go up. However, the ball takes the same amount of time to come down, so we multiply this by 2 to get the total time the ball is in the air:

Total time = 0.47 x 2 = 0.94 seconds, approximately.

So, the ball was in the air for roughly 0.94 seconds.

Learn more about Projectile Motion here:

brainly.com/question/29545516

#SPJ2

Problems of this sort are frequently found in physics. If you study calculus or physics you'll learn how to create the equation representing the velocity of an object in flight.

Here, you don't need to calculate velocity, but rather time. Start with this equation:

v = v0 + a t^2, where v is the velocity at time t, v0 is the initial velocity, a is the acceleration due to gravity (denoted by g instead of a), and t is the elapsed time.

You are told that v0 is 15 ft/sec. Set v = to 0, as the ball stops moving for the tiniest instant at the top of its trajectory. Use g = - 32 ft (per second squared).

Then 0 = 15 ft/sec - 32 [ft/(seconds squared)] t.

Solve this for t. This is the time required for the ball to come to a complete stop at the top of its trajectory.

Finally, multiply this time by 2, since the ball begins to fall and returns to its original height.

Tim made 5 withdrawls of $25 his bank account what was the overall change to his account

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he made 5 withdrawals of 25.......5 x 25 = 125...and since they were withdrawals, the overall change is - 125

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