Joe owned a grocery store and wanted to raise some money. He decided to sell his land and building to an investor and leased it back to himself in order to to continue running his grocery store there. Which of the following would be a tax benefit to Joe? A. All capital gains for Joe are deferred B. Joe has a new tax base for his future depreciation of the building C. Joe's rent payments to the investor will be fully deductible for income tax purposes as a business expense D. None of the above

Answers

Answer 1
Answer:

Answer:

D none of the above. I hope it is correct


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Sams credit card balance is less than -$36. Does Sam owe more or less than $36

Answers

He owes more.

He has LESS than -36. So he getting further from zero.

So he could have -40 or something because that's less money than -36.

So because the negative number is bigger than 36, he will owe more than 36.
If his credit card balance is in the negative then he is OWED that amount by the credit card company in order to make his balance Zero.
If he owed that money to the credit card it would be a positive number. Your balance is what you owe to pay it to zero.

Find the values of x and y in the following system of two equations.7x - 3y = -16
4x + 6y = 2

Answers

Answer:

x = -5/3 and y = 13/9

Step-by-step explanation:

In a bag of marbles, you have 4 green, 3 yellow, 5 blue, and 8 red marbles. What is the probability of picking a green marble from the bag?a) 3/20
b) 1/5
c) 1/10
d) 1/4

Answers

4 + 3 + 5 + 8 = 20

4 / 20 = 1/5
A) 3/20 
add up all of the marbles and whatever is asking you for possibilities is the number of marbles is given you already. for example. i have a ticket for a raffle. so i got only 1 and there is 25 people more with a ticket. what are my chances of winning? 1 out of 25 right?(1/25) because i got 1 ticket if i had 2 it would be 2 out of 25 or (2/25) hope this helps. :)

Solve and verify each of the following of linear eequations

2X+3y=432 and 5x-2y=16

Answers

There are 3 available methods- Substitution , Elimination and Matrix. 

To solve this 
linear equations lets use Matrix's.  

\left[\begin{array}{ccc}2&3&432\n5&-2&16\n\end{array}\right] 

\left[\begin{array}{ccc}2&3&432\n0&-19/2&-1064\n\end{array}\right] 

\left[\begin{array}{ccc}2&3&432\n0&1&112\n\end{array}\right] 

\left[\begin{array}{ccc}2&0&96\n0&1&112\n\end{array}\right]  

\left[\begin{array}{ccc}1&0&48\n0&1&112\n\end{array}\right] 

x=48 

y=112
2x+3y=432 becomes y=-2/3x+144 and 5x-2y=16 which becomes y=5/2x-8

The complement of 4 heads in the toss of 4 coins is (Please explain)! Thanks!


Exactly one tail


At least one tail


All tails


Three heads

Answers

By using sample space we can say that complement of 4 heads in the toss of 4 coins is at least one tail .

What is sample space ?

set of all possible outcomes experiment is called sample space .

To find compliment of 4 heads we will first find sample space Sample space= S

= { HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH, TTTT }

Given case is 4 heads Say A= { HHHH}

Now we can calculate A complement as

A' = S-A

= { HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH,TTTT }- { HHHH}A'={ HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH,TTTT }

By using sample space we can say that complement of 4 heads in the toss of 4 coins is at least one tail .

To know more about sample space visit : brainly.com/question/5750471

Answer:

b i believe the answer is

Help please. what does x equal.

Answers

The answer would be 53