Alex works at a legal firm which produces a lot of documents. Often Alex has to carry heavy stacks of documents from one office to another. On this particular day Alex, who weighs 75 kilograms, has to transport a stacks of documents which weighs 10 kilograms. He has to lift them 5 meters from the floor and then carry them to an office 100 meters down the hall, where he will drop them on the floor. Alex walks swiftly at a steady rate of 1 meter per second. What two pieces of information given in the above description will help you compute the amount of work Alex does when he lifts the papers?

Answers

Answer 1

Answer: You would need the weight of the paper and how high off the ground Alex is going to be lifting them.

Answer 2

Answer:
All you need in order to calculate the work done is the force exerted vertically ("lifting") and the vertical distance through which the force is exerted ("height").
Then Work = (force) times (distance).

Sadly, if you try to apply this simple definition of 'work' to the data you've given
for the situation, your attempt will fail ignominiously. You will say that Alex
has exerted a force of 10 kilograms to lift the documents 5 meters, and has
therefore done (10 x 5) = 50 somethings of work, which is wrong.

It's wrong because 'kilogram' is a unit of mass, not one of force.
Nothing 'weighs' 10 kilograms.

But my first paragraph is the direct answer to your question. The mass
of the stack of documents, and the height to which the stack is lifted, will
help you compute the amount of work Alex does.

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How does the magnetic force exerted by a magnet change as the distance between two magnets increases

Answers

As the distance between two magnets increases, the force between them decreases.

If the force increased along with distance, then the magnet in your hand would reach out
and grab every magnet in Australia or on Mars and pull it toward you.

How much force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m?

Answers

Answer

Force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m is 95 N .

Explanation:

By using Hookes law .

The force required to extend a spring is directly proportional to the distance you stretch it .

Thus

F = kx

Where F is force , k is spring constant and x is the extension of spring .

As given

A spring is stretch to 0.5 m .

The spring constant is 190 N/m .

x = 0.5 m

k = 190 N /m

Putting all the values in the formula

F = 190 × 0.5

= 95 N

Therefore the force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m is 95 N .

190x0.5=95N

Hope this helps :)

Given a 3.00 μF capacitor, a 7.75 μF capacitor, and a 5.00 V battery, find the charge on each capacitor if you connect them in the following ways. (a) in series across the battery 3.00 μF capacitor μC 7.75 μF capacitor μC (b) in parallel across the battery 3.00 μF capacitor μC 7.75 μF capacitor μC.

Answers

Answer:

a) Q1= Q2= 11.75×10^-6Coulombs

b) Q1 =15×10^-6coulombs

Q2 = 38.75×10^-6coulombs

Explanation:

a) For a series connected capacitors C1 and C2, their equivalent capacitance C is expressed as

1/Ct = 1/C1 + 1/C2

Given C1 = 3.00 μF C2 = 7.75μF

1/Ct = 1/3+1/7.73

1/Ct = 0.333+ 0.129

1/Ct = 0.462

Ct = 1/0.462

Ct = 2.35μF

V = 5.00Volts

To calculate the charge on each each capacitors, we use the formula Q = CtV where Cf is the total equivalent capacitance

Q = 2.35×10^-6× 5

Q = 11.75×10^-6Coulombs

Since same charge flows through a series connected capacitors, therefore Q1= Q2=

11.75×10^-6Coulombs

b) If the capacitors are connected in parallel, their equivalent capacitance will be C = C1+C2

C = 3.00 μF + 7.75 μF

C = 10.75 μF

For 3.00 μF capacitance, the charge on it will be Q1 = C1V

Q1 = 3×10^-6 × 5

Q1 =15×10^-6coulombs

For 7.75 μF capacitance, the charge on it will be Q2 = 7.75×10^-6×5

Q2 = 38.75×10^-6coulombs

Note that for a parallel connected capacitors, same voltage flows through them but different charge, hence the need to use the same value of the voltage for both capacitors.

Why cooking pans don't have have metal handles?

Answers

metals are conductors, meaning that heat travels through it better than insulators such as plastic (commonly used for pan handles)

Therefore, to avoid the heat burning hands, most pans don't have metal handles.

Probably because during cooking they will also be hot and you won't be able to handle it.

. If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circularpath were reduced, what would happen?

Answers

In this particular case, where car is moving through curvature, so it is moving in circular motion, force acting on car is centripetal force which holds car not to fly out. Centripetal force is always pointed in the middle of circle. Here frictional force has role of centripetal force. If frictional force is to weak, car would fly out of curvutare.

If you heat soup on a stove, what happens to the movement of the soup’s particles?The particles move slower.

The particles move faster.

There’s no change in the speed of particles.

The particles stop moving.

Answers

The particles of soup heat up more quickly on a burner. Option B is correct.

What is temperature?

Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

The amount of thermal energy or heat produced is directly correlated with the speed of the moving particles. As a result, the soup particle would travel more quickly as it heated.

Hence, option B is correct.

To learn more about the temperature refer to the link;

brainly.com/question/7510619

#SPJ2

We know, that thermal energy is directly proportional to kinetic energy which in turn, is directly proportional to velocity. So, as soup particle would get heated, it's particle move faster.

In short, Your Answer would be Option B

Hope this helps!

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