A 24 kg box is being pulled across a floor by a horizontal rope. What is the Normal force?

Answers

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(01.01 LC)Two objects of the same mass are in a room. At which of the
following distances will the greatest gravitational force be exerted
by one object on another?
O 2 m
O 4 m
O 6 m
O 8 m

Answers

Answer:

Explanation:

The closer the objects are, the more gravitational force there is

Answer:

Explanation:

its the shortest distance so its corect

PLS VOTE THANK YOU

A bicyclist bikes the 56 mi to a city averaging a certain speed. The return trip is made at a speed that is 6 mph slower. Total time for the round trip is 11 hr. Find the bicyclist's average speed on each part of the trip.

Answers

Answer:

Speed of the bicyclist when going to city = 14 miles per hour.

Speed while return trip = 8 miles per hour.

Explanation:

Let the speed of the bicyclist when going to city = x miles per hour.

Speed while return trip = x - 6 miles per hour.

Total time taken = 11 hrs = Time for the trip to city + time taken for return trip.

Also, Time = Distance / Time.

So,

56 / x + 56 / ( x -6) = 11

11x² -178x + 336 = 0

Solving for x we get:

Acceptable x = 14 miles per hour.

Speed while return trip = x - 6 miles per hour = 8 miles per hour.

Final answer:

To find the average speed on each part of the trip, use the formula Average speed = Total distance/Total time and set up an equation to solve for the unknown speeds.

Explanation:

To find the average speed on each part of the trip, we can use the formula Average speed = Total distance/Total time. Let's assume the average speed on the first part of the trip (56 miles) is x mph. Since the return trip is made at a speed that is 6 mph slower, the average speed on the second part of the trip is (x - 6) mph. We know that the total time for the round trip is 11 hours. So, we can set up the equation:

56/x + 56/(x - 6) = 11

Now, we can solve this equation to find the value of x, which represents the average speed on the first part of the trip. Once we have x, we can find the average speed on the second part of the trip by subtracting 6 from x.

Learn more about Average speed here:

brainly.com/question/12322912

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I will mark brainliest if you get it right.

Answers

Answer:

Satellite D

Explanation:

It has more mass

A student throws a 5.0-newton ball straight up.What is the net force on the ball at its maximum
height?
(1) 0.0 N (3) 5.0 N, down
(2) 5.0 N, up (4) 9.8 N, down

Answers

If the ball weighs 5 newtons, then that's the force of gravity that
attracts it to the center of the Earth. The force only depends on
the mass of the ball and its distance from the center of the Earth.
The force of gravity doesn't care whether the ball is moving or at
rest. It doesn't change significantly until the ball moves to some
significant distance off the Earth's surface, which isn't happening
if it's tossed by a human being.

So we have a downward force of 5 newtons on the ball at all times.
In order to find the net force on it, we have to identify any other
forces besides gravity that are also acting on it.

If the ball were moving through the air, then there would be a force
of air resistance on it, acting opposite to its motion. But when it's
at its maximum height, in the process of turning around from rising
to falling, there's an instant when it's not moving through the air at all,
so gravity is the only force acting on it. At that moment, the net force
on the ball is 5.0 newtons downward.

A box is being pulled to the right on flat ground with a force of 112 N at an angle of 42° to the horizontal. What is the x-component of the force of tension?

Answers

The x-component is related with the Force through the trigonometric function cosine.

cos(42°) = x-component / F ⇒ x-component = Fcos(42°) = 112N*0.743 = 83.2 N

A man pushes on a box at an angle of 30.0° with a force of 20.0 N and the box moves across the floor. Which of the following component of the force do you use to calculate work?

Answers

Not sure what the given options are, but the answer is the horizontal component. This is given by Force x cos(angle), or Fcos(θ), where θ is the angle. In this case that would be 20cos(30) = 17.32N

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