Write a story problem using mixed numbers that need to be scaled up. The problem should
have at least five mixed numbers that will be scaled up. Be sure to show all your work, explain your
steps in your solution (including changing improper fractions to mixed numbers), and write a complete
answer to your problem. Your answer should include units for the mixed numbers, if needed.

Answers

Answer 1

Answer: [Insert generic name here] is trying to bake a yellow cake because [reasons]. This recipe will make one whole cake.

$3(1)/(4)\ cups\ of\ flour\n 2(1)/(2)\ teaspoons\ of\ baking\ soda\n (1)/(2)\ teaspoon\ of\ salt \n 1(3)/(4)\ cups\ of\ sugar \n (2)/(3)\ cup\ of\ butter \n 2\ eggs\n 1(1)/(2)\ teaspoons\ of\ vanilla\ \n 1(1)/(4)\ cups\ of\ milk$

He wants to make three cakes instead of one. How much of each item should be used in the new (scaled-up) recipe?

$3(1)/(4)*3=9(3)/(4)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ cups\ of\ flour\n 2(1)/(2)*2=4(2)/(2)=4+1=5\ \ \ \ \ teaspoons\ of\ baking\ soda\n (1)/(2)*3=(3)/(2)=1(1)/(2)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ teaspoons\ of\ salt \n 1(3)/(4)*3=3(9)/(4)=3+2(1)/(4)=5(1)/(4)\ cups\ of\ sugar$

$(2)/(3)*3=(6)/(3)=2\ \ \ \ \ \ cups\ of\ butter\n 2*3=6 \ \ \ \ \ \ \ \ \ \ \ \ eggs\n 1(1)/(2)*3 = 3(3)/(2) = 4\frac{1}2\ teaspoons\ of\ vanilla\ \n 1(1)/(4)*3=3(3)/(4)\ \ \ \ \ \ \ \ cups\ of\ milk$

I don't know exactly how your teacher wants you to write out the work, but I have it pretty simple there. It's not like math is tailored to a specific process; any sort of reasonable work should do.

Good luck!

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Simplify the following expression.
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You are running at a rate of 6 miles per hour. Write a function that represents the distance d traveled in h hours.
What is 1/10 of 0.04

Sue deposited $3000 in a savings account earning 2% interest over 8 years. What was the total interest Sue earned?

Answers

Original Interest: I = Prt
I = (3000)(0.02)(8)
I = (60)(8)
I = 480

Simple Interest: A = P(1 + rt)
A = 3000(1 + (0.02)(8))
A = 3000(1 + 0.16)
A = 3000(1.16)
A = 3480

Compound Interest: $C = P((1 + r)^(n) - 1)$
$C = 3000(1 - 0.02)^(96) - 1)$
   $C = 3000((0.98)^(96) - 1)$
   $C = 3000(014 - 1)$
   $C = 3000(-0.86)$
   $C = -2580$

Payment Amount: $A = P(r(1 + r)^(n))/((1 + r)^(n) - 1)$
$A = 3000((0.02(1 + 0.02)^(96))/((1 + 0.02)^(96) - 1))$
$A = 3000((0.02(1.02)^(96))/((1.02)^(96) - 1))$
$A = 3000((0.02(6.7))/(6.7 - 1))$
$A = 3000((0.134)/(5.7))$
$A = 3000(0.024)$
$A = 72$

Can someone plz help me Solve this Equation Solve for X

Answers

Answer:

x = 4

Step-by-step explanation:

If two secants are drawn to a circle from one exterior point, then the product of the exterior segment and whole segment is same. i.e 6×(6+x) = 5×(5+x+3)

=> 6x+36 = 5x + 15 +25

=> x = 40-36

=> x = 4

I hope it's the right answer.

Answer:

x = 4

Step-by-step explanation:

Given 2 secants drawn to a circle from an external point, then

The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is

6(6 + x) = 5(5 + x + 3), that is

36 + 6x = 5(8 + x) = 40 + 5x ( subtract 5x from both sides )

36 + x = 40 ( subtract 36 from both sides )

x = 4

The minimum value of 2x + 1 is 13

Answers

Hi Jalansmith133!

$2x+1 = 13 \n \n 2x = 12 \n \n x = 6$

GoodLuck...

Please help what is the answer its a math question find the lcd!!!

Answers

Step-by-step explanation:

sorry I don't now but when I now I will tell you ok but mybe it 12×12×12

Which test point holds true for 2/5x - 1/5>=0 ?

Answers

2/5x >= 1/5 multiple both sides by 5/2
so , x >= 1/2

Fill on the other coordinate for the line 2x-3y=4 (2,)

Answers

For the first coordinate they have given it to you, so plug it in to get the y coordinate.
2x -3y = 4
2 * 2 - 3y = 4
4 - 3y = 4
4 - 4 - 3y = 4 - 4
-3y = 0
-3y/-3 = 0/-3
y = 0
(2, 0)
To find another set of coordinate to form a line, all you have to do is put in an x value that would make the line true.
2x -3y =4
2 * 8 - 3y = 4
16 - 3y = 4
16 - 16 -3y = 4 - 16
-3y = -12
-3y/-3 = -12/-3
y = 4

for this question we have:
(2, y)
and we know:
2x -3y = 4
so the only thing u need is to put 2 for x and find y:
2(2) - 3y = 4
4 - 3y = 4
-3y = 0
y =0 :)))
I hope this is helpful
have a nice day

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Somebody help please ASAP!

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