MATHEMATICS HIGH SCHOOL

Find the volume of the cylinder shown below.12 cm the radius
13 cm the height

Use 3.14 or the calculator value for pi and provide an answer accurate
to the nearest tenth.

Answers

Answer 1
Answer:

The volume of a cylinder is calculated using the following formula:

```

Volume = π * radius^2 * height

```

π (pi) is a mathematical constant that represents the ratio of a circle's circumference to its diameter. It is approximately equal to 3.14.

In this case, the radius of the cylinder is 12 cm and the height of the cylinder is 13 cm. Substituting these values into the formula, we get:

```

Volume = 3.14 * 12^2 * 13

```

```

Volume = 5881.1 cubic centimeters

```

**Answer:**

The volume of the cylinder is **5881.1 cubic centimeters**.

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If BC = 9 and CD = 29, find AC.
38 Squared Root 
3 Radical 29 
38
261

Answers

\Delta ABC\sim\Delta DAC\n\nthen\n\n(|AC|)/(|BC|)=(|CD|)/(|AC|)\n\n|AC|^2=|BC|\cdot|CD|\n\n|AC|^2=9\cdot29\n\n|AC|=√(9\cdot29)\n\n|AC|=3√(29)

Answer:

3/29

Step-by-step explanation:

7 times as much as the sum of 1/3 and 4/5

Answers

7( (1)/(3) + (4)/(5) )

=7( (1(5))/(3(5)) + (4(3))/(5(3)) )

=7( (5)/(15) + (12)/(15) )

=7( (17)/(15))

=(7)/(1) ( (17)/(15))

=(119)/(15)

= 7(14)/(15)≈ 7.93

¹¹⁹/₁₅ or 7¹⁴/₁₅ or 7.93

Further explanation

The Problem:

  • 7 times as much as the sum of (1)/(3) and (4)/(5)
  • Write an expression to match, and then solve it.

The Process:

Here are some early expressions that need attention.

  • one-third is \boxed{(1)/(3)}
  • four-fifth is \boxed{(4)/(5)}
  • the sum of (1)/(3) \ and \ (4)/(5) is \boxed{(1)/(3) + (4)/(5)}

Let us write an expression to match for 7 times as much as the sum of (1)/(3) and (4)/(5)

\boxed{\boxed{ \ 7 * \bigg((1)/(3) + (4)/(5) \bigg) \ }}

Let us calculate the operation in parentheses at first.

\boxed{(1)/(3) + (4)/(5)}

A least common multiple of 3 and 5 is 15. We use to equate the denominator.

\boxed{(1 * 5)/(3 * 5) + (4 * 3)/(5 * 3)}

\boxed{(5)/(15) + (12)/(15)}

\boxed{(17)/(15)}

And now we solve the full expression.

\boxed{ \ = 7 * \bigg((1)/(3) + (4)/(5) \bigg) \ }

\boxed{ \ = 7 * (17)/(15) \ }

We do not cross out 7 and 15 because they both cannot be divided.

\boxed{ \ = (119)/(15) \ }

\boxed{\boxed{ \ = (119)/(15) \ }}

In mixed fraction:

\boxed{ \ (119)/(15) = \ ? \ }

\boxed{ \ = (105)/(15) + (14)/(15) \ }

\boxed{ \ = 7 + (14)/(15) \ }

\boxed{\boxed{ \ = 7(14)/(15) \ }}

In decimal:

\boxed{ \ 7(14)/(15) = \ ? \ }

\boxed{ \ (14)/(15) = 0.93 \ }

\boxed{ \ = 7 + (14)/(15) \ }

\boxed{ \ = 7 + 0.93 \ }

\boxed{\boxed{ \ = 7.93 \ }}

\boxed{\boxed{ \ Thus, \ the \ result \ is \ (119)/(15) \ or \ 7(14)/(15) \ or \ 7.93 \ }}

- - - - - - - - - -

Quick Steps:

\boxed{ \ = 3 * \bigg((1)/(3) + (4)/(5) \bigg) \ }

\boxed{ \ = 3 * \bigg((5 + 12)/(15) \bigg) \ }

\boxed{ \ = 3 * \bigg((17)/(15) \bigg) \ }

\boxed{\boxed{ \ = (119)/(15) \ }}

\boxed{\boxed{ \ = 7(14)/(15) \ }}

\boxed{\boxed{ \ = 7.93 \ }}

Learn more  

  1. 7 copies of the sum of 8 fifths and 4 brainly.com/question/961462
  2. (2)/(3) of the product of (3)/(8) and 16 brainly.com/question/961462
  3. 15 times as much as 1 fifth of 12 is brainly.com/question/348151

Keywords: 7 times, as much as, the sum of 1/3 and 4/5, write an expression to match, and then solve, the result, in mixed fraction, decimal, ¹³/₄ or 3¹/₄ or 3.25

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!What are the factors of the polynomial function?

Use the rational root theorem to determine the factors.

Answers

Answer: (x - 2)(x + 2)(2x + 1)

Step-by-step explanation:

        q                     p

f(x) = 2x³ + x² - 8x - 4

rational root theorem: (p)/(q) = +/- (1, 2, 4)/(1, 2) so the possible roots are: +/- 1, 2, 4, (1)/(2)

Let's try x = 2

2  |   2     1     -8     -4

   |   ↓     4     10     4

       2     5     2      0   remainder is 0 so (x - 2) is a factor

0 = (x - 2)  (2x² + 5x + 2)

0 = (x - 2)  (x + 2)(2x + 1)
Answer: X - 2 ( X + 2) (2 x + 1)

If you divided 48 objects into sets of 7, how many sets of 7 could you make, and how many are left over?

Answers

Answer:

6

Step-by-step explanation:

No. objects in one set = 7

Let there be n set

Then, No. objects in n set = 7*n = 7n

Given that total  no of objects are 48

Thus,

7n = 48

n = 48/7 = (42+6)/7 = 42/7 + 6/7 = 6 + 6/7

n = 6 + 6/7

Thus, there will be 6 set which has 7 objects. fraction means one set is fraction 6/7 but set cannot be in fraction hence negating it.

Now, total objects in 6 sets = 6*7 = 42.

No. of objects left = 48 - 6 = 6

If f(x)=x+3 g(x)=2x+6 find (f+g)(x)

Answers

Answer:

3x + 9

Step-by-step explanation:

For value of (f+g)(x) add two functions up

x + 3 + 2x + 6 = 3x + 9

Tanx cosx = 0i believe you have to use the cancellation method. you turn tanx into sinx/cosx times cos but i dont know where to go from there

Answers

You're almost finished.

(sin/cos) times cos = 0

Look at the left side.  You could write it as (sin x cos) / cos = 0
and simply divide numerator and denominator by the cosine (cancel it).

Then what do you have left ? . . .  sin(x) = 0       Do I need to finish this for you ?
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