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Describe the following Algebraic Expression using the Algebraic Vocabulary words. Use all four words in yourdescription. Use complete sentences: 12y + 6-8x - m
Terms, coefficients, variables, constants

Answers

Answer 1
Answer:

Final answer:

The given algebraic expression has terms, coefficients, variables, and constants.


Explanation:

The given algebraic expression is 12y + 6 - 8x - m.

In this expression, terms are the individual parts that are added or subtracted. The terms in this expression are 12y, 6, -8x and -m.

The coefficients are the numbers that multiply the variables. In this expression, the coefficients are 12 and -8.

Variables are the letters that represent unknown values. In this expression, the variables are y and x.

The constants are the numbers without variables. In this expression, the constant is the number 6.


Learn more about Algebraic Expressions here:

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Boris buys candy that costs $7 per pound. He will spend at least $63 on candy. What are the possible numbers of pounds he will buy?

Answers

Answer:

Anything above 9

Step-by-step explanation:

63/7=9

Write the answer and solution ?

Answers

Answer

4. E

use PEMDAS

5. 36+18=54  so C

plug in x

6. 15=5x

x=3 so C

11. B

break the absolute value into pos and neg components

12.D

is not equal to so open circle

2x=14

2x=8

so 4 and 7 with open circles

Step-by-step explanation:

Which statement is represented by the equation 3x +0.6 = 7?A.The product of 3 and x added to 0.6 is equal to 7

B. The sum of x and 0.6 multiplied by 3 is equal to 7

C.The product of 3 times the sum of x and 0.6 is equal to 7

D.The sum of 3 and x multiplied by 0.6 is equal to 7

Answers

The correct answer is A! :)

Answer:the right answer is a

Step-by-step explanation:

ive done this question

hope it helps

Solbe for x : x-1/x+3x+3=0​

Answers

Answer:

x=1/4 or x=-1

Step-by-step explanation:

x−

1

x

+3x+3=0

4x2+3x−1

x

=0

Step 1: Multiply both sides by x.

4x2+3x−1=0

(4x−1)(x+1)=0(Factor left side of equation)

4x−1=0 or x+1=0(Set factors equal to 0)

x=

1

4

or x=−1

Check answers. (Plug them in to make sure they work.)

x=

1

4

(Works in original equation)

x=−1(Works in original equation)

Answer:

x=

1

4

or x=−1

Reuben attached a wire between two poles on a hill as shown which is the closest to x the distance between the two poles

Answers

Answer:

75 ft

Step-by-step explanation:

Here we are given a right angled triangle with a known angle of 20°, length of the hypotenuse to be 80 and we are to find the length of the base x.

For that, we can use the formula for cosine for which we need an angle and the lengths of base and hypotenuse.

cos \alpha =(base)/(hypotenuse)

So putting in the given values to get:

cos 20=(x)/(80) \n\nx= cos 20*80\n\nx=75.17

Therefore, the value of x is the closest to 75 ft.

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the cost to make the can if the metal for the sides will cost $1.25 per 2 cm and the metal for the bottom will cost $2.00 per 2 cm ?

Answers

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=(25)/(\pi r^2)

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=(25)/(\pi r^2)

\therefore C=2\pi r^2+2.5 \pi r * (25)/(\pi r^2)

\Rightarrow C=2\pi r^2+ (62.5)/( r)

Differentiating with respect to r

C'=4\pi r- (62.5)/( r^2)

Again differentiating with respect to r

C''=4\pi + (125)/( r^3)

To find the minimize cost, we set C'=0

4\pi r- (62.5)/( r^2)=0

\Rightarrow 4\pi r=(62.5)/( r^2)

\Rightarrow r^3=(62.5)/( 4\pi)

⇒r=1.71

Now,

\left C''\right|_(x=1.71)=4\pi +(125)/(1.71^3)>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=(25)/(\pi* 1.71^2)

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.
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