What is 75.36 rounded to the nearest cubic unit

Answers

Answer 1
Answer: 75 unit^3
because .36 is less than 0.5 so round down
Answer 2
Answer: 75.00^3
.36 > 0.5
Happy to Help!

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PLEASE  HELP ME I AM FRUSTERATED SOMEONE PLEASE ANSWER THANK U ! I am crying trying cause  no one seems to help me please someone help me thank u!  THE QUESTION :find the expression that is NOT equivalent ,for the problems 9-16 below

Answers

First of all, don't cry. Second of all, try to post a clearer picture because it was a bit tough to see. Third of all, here are the answers:

In row 9, S is wrong because it is 27x+24y, it should be 36x+24y
In row 10, A is wrong because it is 4+20x, it should be 20x
In row 11, G is wrong because it is 15ab, it should be 10a+5b
In row 12, I is wrong because it is 15x+6y, it should be 15x+10y
In row 13, O is wrong because it is 22a+6, it should be 28a
In row 14, T is wrong because it is 14x, it should be 22x
In row 15, K is wrong because it is 15x+y, it should be 15x+3y
In row 16, T is wrong because it is 14n+84m, it should be 12m+14n

Also on another note, this might be intimidating but it is mostly adding/multiplication of variables. So if you don't know them, you might want to double check that you know how to handle variables in the future;)

In one grade of 150 students, the ratio of boys to girls is 2:3. How many boys are in that grade?

Answers

Answer:

The numbers of boys in one grade are 60 .

Step-by-step explanation:

As given

In one grade of 150 students .

The ratio of boys to girls is 2:3.

Let us assume that the scalar multiple of boys and girls be x.

Thus number of boys = 2x

Number of girls = 3x

Than the equations becomes

2x + 3x = 150

5x = 150

x = (150)/(5)

x = 30

Thus number of boys = 2 × 30

                                    = 60

Therefore the numbers of boys in one grade are 60 .


2+3 = 5

150/5 = 30

30*2 = 60

There are 60 boys in that grade.

Using the digits 5,9,4 and 1 make decimals more than 5

Answers

There are exactly 12 different correct answers. They are: 9 (point) (the six possible ways to arrange 5, 4, and 1) . . . . . and . . . . . 5 (point) (the six possible ways to arrange 9, 4, and 1).

True or false :
20÷4x5= 1
10+10÷2=15
6+4×5=50
12_3×2=6
81÷9+2=11

Answers

To solve, you must use order of operations. The acronym used is BEDMAS (brackets, exponents, division/multiplication, addition/subtraction), which is the order you solve in. 

F  20÷4x5
    =5x5
    =25
      
T   10+10÷2
      =10+5
      =15

F    6+4×5
      =6+20
      =26

T   81÷9+2
     =9+2
     =11
False
True
False
True......
( i wish it helps.....)

Write a real-world situation that could be modeled by the equation 500 + 250x = 300x

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An interior angle of a regular polygon is eleven times its exterior Work out the number of sides of the polygon
Thank you x

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I think they answer might be ....... /7