Form a polynomial f(x) with real coefficients having the given degree and zeros. a) f(x) = x^3 - 5x^2 + x + 5 b) f(x) = x^3 - 5x^2 + x - 5 c) f(x) = x^3 + 5x + x - 5 d) f(x) = x + 5x^2 - x + 5

Answers

Answer 1

Answer:

Answer:

what is math

Step-by-step explanation:

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Which best describes the range of the function f(x) = 2/3(6)x after it has been reflected over the x-axis?A. all real numbers B. all real numbers less than 0 C. all real numbers greater than 0 D. all real numbers less than or equal to 0

What is the inverse of the function f(x) = x +3?A. h(x) =1/3 x + 3
B. h(x) = 1/3x – 3
C. h(x) = x – 3
D. h(x) = x + 3

Answers

Answer:

Option C is correct that is h(x)=x-3

Step-by-step explanation:

We have been given a function:

$f(x)=x=3$

$\text{let y}=f(x)$

$y=x+3$

$x=y-3$

Hence, $f^(-1)y=y-3$

Therefore, $f^(-1)x=x-3$

Hence, Option C is correct that is h(x)=x-3

f(x) = x + 3
y = x + 3
x = y - 3

Inverse is h(x) = x - 3

solve the equation in factoral form

(x+3)(x-2/5=0

Answers

$(x+3)(x-(2 )/(5))=0 \n \nx+3 =0 \ \ \vee \ \ x-(2)/(5)=0\n \nx = -3 \ \ \vee \ \ x=(2)/(5)$

Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?A. tan A = sin A/sin C
B. cos A = tan (90-A)/sin (90-C)
C. sin C = cos A/tan C
D. cos A = tan C
E. sin C = cos (90-C)/tan A

Answers

First, note that $m\angle A+m\angle C=90^(\circ).$ Then

$m\angle A=90^(\circ)-m\angle C \text{ and } m\angle C=90^(\circ)-m\angle A.$

Consider all options:

$\tan A=(\sin A)/(\sin C)$

By the definition,

$\tan A=(BC)/(AB),\n \n\sin A=(BC)/(AC),\n \n\sin C=(AB)/(AC).$

Now

$(\sin A)/(\sin C)=((BC)/(AC))/((AB)/(AC))=(BC)/(AB)=\tan A.$

Option A is true.

$\cos A=(\tan (90^(\circ)-A))/(\sin (90^(\circ)-C)).$

By the definition,

$\cos A=(AB)/(AC),\n \n\tan (90^(\circ)-A)=(\sin(90^(\circ)-A))/(\cos(90^(\circ)-A))=(\sin C)/(\cos C)=((AB)/(AC))/((BC)/(AC))=(AB)/(BC),\n \n\sin (90^(\circ)-C)=\sin A=(BC)/(AC).$

Then

$(\tan (90^(\circ)-A))/(\sin (90^(\circ)-C))=((AB)/(BC))/((BC)/(AC))=(AB\cdot AC)/(BC^2)\neq (AB)/(AC).$

Option B is false.

$\sin C = (\cos A)/(\tan C).$

By the definition,

$\sin C=(AB)/(AC),\n \n\cos A=(AB)/(AC),\n \n\tan C=(AB)/(BC).$

Now

$(\cos A)/(\tan C)=((AB)/(AC))/((AB)/(BC))=(BC)/(AC)\neq \sin C.$

Option C is false.

$\cos A=\tan C.$

By the definition,

$\cos A=(AB)/(AC),\n \n\tan C=(AB)/(BC).$

As you can see $\cos A\neq \tan C$ and option D is not true.

$\sin C = (\cos(90^(\circ)-C))/(\tan A).$

By the definition,

$\sin C=(AB)/(AC),\n \n\cos (90^(\circ)-C)=\cos A=(AB)/(AC),\n \n\tan A=(BC)/(AB).$

Then

$(\cos(90^(\circ)-C))/(\tan A)=((AB)/(AC))/((BC)/(AB))=(AB^2)/(AC\cdot BC)\neq \sin C.$

This option is false.

The right anwer is option A.
tan A = sin A / sin C
sin C = sin A / tan A = sin A / (sin A / cos A) = cos A
sin C = cos A

Please help! The answer choiuces are :
Positive
Negative
Absolute
Parabola

Answers

Answer:

Parabola

Step-by-step explanation:

This is what it looks like:

Franco bought two shirts at a local store. The regular price for each shirt was r dollars. The store charged Franco the regular price for the first shirt and gave him a 75% discount on the second shirt. He was charged 6% sales tax on the entire purchase. Which of the following expressions gives the total, in dollars, Franco paid, including sales tax? (HOA 01 & HOA 06)

Answers

Answer:

The answer is 1.325 dollars if you need explanation I'll tell u in comments,good luck

How do you divide can someone plz tell me

Answers

Just divide
Like 4:2=2

Its pretty easy lets say 2:4 How many times does 2 go into 4 two times see easy

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