MATHEMATICS HIGH SCHOOL

D/4 -7 =-12 $d/4 -7 =-12$

Answers

Answer 1

Answer:

Answer:

jhvb

Step-by-step explanation:

jkbh

Related Questions

A quality-control center finds that 2 out of 250 toy trains are defective. How many trains would they expect to be defective in a batch of 10,000?A.80 B.40 C.250 D.125
Convert 129/7 into a mixed number
Select the correct answer.The elimination method is ideal for solving this system of equations. By which number must you multiply the second equation to eliminate they variable, and what is the solution for this system?x+3y= 422x - y = 14OA. Multiply the second equation by-3. The solution is x= 12, y=9.OB. Multiply the second equation by -2. The solution is x = 12, y=10.OC. Multiply the second equation by 2. The solution is x = 15, y = 9.OD. Multiply the second equation by 3. The solution is x = 12, y = 10.
A certain alloy contains 5.25% copper. How much copper is there in a piece weighing 200 pounds?
An alloy weighing 40 lbs. is 10% tin. The alloy was made by mixing a 15% tin alloy and a 8% tin alloy. How many pounds of each alloy (to the nearest tenth) were used to make the 10% alloy?lbs. of the 15% alloy and lbs. of the 8% alloy.

17. Find all the real fourth roots of 0.0001.

Answers

3. 0.1778, -0.1778 Are you sure that you don't mean the fourth root of 0.0001?That would be 0.1, -0.1

Find the unit rate: 6 yards of fabric for $8.10

Answers

Answer:

$1.35 per yard

Step-by-step explanation:

$8.10/6=$1.35

Answer:

$1.35

Step-by-step explanation:

$8.10 divided by 6

The ratio table below shows the number of miles Shondra drove in a car for certain amounts of time during a road trip. Driving Distance Hours Driven Miles Driven 1 60 2 120 3 180 4 ? If Shondra traveled the same number of miles each hour, how many miles did she travel in 4 hours? The first to answer i will put you as brainlyest

Answers

If Shondra traveled the same number of miles each hour during her road trip, we can calculate the miles she traveled in 4 hours by simply multiplying the miles she traveled in 1 hour by 4:

Miles Driven in 1 Hour = 60 miles

Miles Driven in 4 Hours = 60 miles/hour * 4 hours = 240 miles

So, Shondra traveled 240 miles in 4 hours.

Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing, and the end behavior when the following changes are made. Make sure to account for even and odd functions.When f(x) becomes f(x) − 3
When f(x) becomes −2 ⋅ f(x)

Answers

First of all, let's review the definition of some concepts.

Even and odd functions:

A function is said to be even if its graph is symmetric with respect to the $y-axis$ , that is:

$y=f(x) \ is \ \mathbf{even} \ if, \ for \ each \ x \ in \ the \ domain \ of \ f, \n f(-x)=f(x)$

On the other hand, a function is said to be odd if its graph is symmetric with respect to the origin, that is:

$y=f(x) \ is \ \mathbf{odd} \ if, \ for \ each \ x \ in \ the \ domain \ of \ f, \n f(-x)=-f(x)$

Analyzing each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When $f(x)$ becomes $f(x)-3$

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function $f(x)$ into:

$f(x)-3$

We know that the graph $f(x)$ intersects the y-axis when $x=0$ , therefore:

$y=f(0) \ is \ the \ y-intercept \ of \ f$

So:

$y=f(0)-3 \ is \ the \ new \ y-intercept$

So the y-intercept of $f(x)-3$ is three units less than the y-intercept of $f(x)$

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function $f(x)-3$ increases and decreases in the same intervals of $f(x)$

1.3 The end behavior when the following changes are made.

The function is shifted three units downward, so each point of $f(x)-3$ has the same x-coordinate but the output is three units less than the output of $f(x)$ . Thus, each point will be sketched as:

$For \ y=f(x): \n P(x_(0),f(x_(0))) \n \n For \ y=f(x)-3: \n P(x_(0),f(x_(0))-3)$

FOR ODD FUNCTIONS:

2. When $f(x)$ becomes $f(x)-3$

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is three units less. So the graph is shifted three units downward again.

An example is shown in Figure 1. The graph in blue is the function:

$y=f(x)=x^3-x$

and the function in red is:

$y=f(x)-3=x^3-x-3$

This function is odd, so you can see that:

$y-intercept \ of \ f(x)=0 \n y-intercept \ of \ f(x)-3=-3$

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of $f(x)$

In Figure 1 you can see that both functions increase and decrease at the same intervals.

2.3 The end behavior when the following changes are made.

It happens the same, the output is three units less than the output of $f(x)$ . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When $f(x)$ becomes $-2.f(x)$

3.1 Effects on the y-intercept

As we know the graph $f(x)$ intersects the y-axis when $x=0$ , therefore:

$y=f(0) \ is \ the \ y-intercept \ again$

And:

$y=-2f(0) \ is \ the \ new \ y-intercept$

So the new y-intercept is the negative of the previous intercept multiplied by 2.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function $f(x)$ increases, the function $-2f(x)$ decreases. On the other hand, in the intervals when the function $f(x)$ decreases, the function $-2f(x)$ increases.

3.3 The end behavior when the following changes are made.

Each point of the function $-2f(x)$ has the same x-coordinate just as the function $f(x)$ and the y-coordinate is the negative of the previous coordinate multiplied by 2, that is:

$For \ y=f(x): \n P(x_(0),f(x_(0))) \n \n For \ y=-2f(x): \n P(x_(0),-2f(x_(0)))$

FOR ODD FUNCTIONS:

4. When $f(x)$ becomes $-2f(x)$

See example in Figure 2

$y=f(x)=x^3-x$

and the function in red is:

$y=-2f(x)=-2(x^3-x)$

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept multiplied by 2.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function $f(x)$ increases, the function $-2f(x)$ decreases. On the other hand, in the intervals when the function $f(x)$ decreases, the function $-2f(x)$ increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function $-2f(x)$ has the same x-coordinate just as the function $f(x)$ and the y-coordinate is the negative of the previous coordinate multiplied by 2.

The y-intercept of  is  .
Of course, it is 3 less than  , the y-intercept of  .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.

is the mirror image of  stretched along the y-direction.
The y-intercept, the value of  for  , iswhich is  times the y-intercept of  .Because of the negative factor/mirror-like graph, the intervals where  increases are the intervals where  decreases, and vice versa.
The end behavior is similarly reversed.
If  then  .
If  then  .
If  then  .
The same goes for the other end, as  tends to  .
All of the above applies equally to any function, polynomial or not, odd, even, or neither odd not even.
Of course, if polynomial functions are understood to have a non-zero degree,  never happens for a polynomial function.

–3(t − 17) = 6 whats the answer

Answers

Answer:

t = 15

–3(t − 17) = 6

Step-by-step explanation:

1. Distribute the –3 to the terms inside the parentheses:

–3 * t + 3 * 17 = 6

2. Simplify:

–3t + 51 = 6

3. Next, we want to isolate the variable t by getting rid of the constant term. To do this, we can subtract 51 from both sides of the equation:

–3t + 51 - 51 = 6 - 51

This simplifies to:

–3t = -45

4. Now, to solve for t, we need to isolate the variable. Since –3t means –3 times t, we can divide both sides of the equation by –3:

–3t / –3 = -45 / –3

This simplifies to:

t = 15

So, the solution to the equation –3(t − 17) = 6 is t = 15.

Last one for the day :)
Find the slope of the line

Answers

Line pass to points: (-5;0) and (0;-5)

So:

$\left|\begin{array}{ccc}x&y&1\n-5&0&1\n0&-5&1\end{array}\right|=0\n \n 25+5y+5x=0\n \n 5+y+x=0\n y=-x-5\n \n slope=-1 \ \ \(coeficient \ of \$

For each unit of progress toward the right ... as 'x' increases ...
the line drops one unit.

Its slope is -1.

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