X^a+b/x^2a. x^b+c/x^2b. xc+a/x^2c​
x^a+b/x^2a. x^b+c/x^2b. xc+a/x^2c​ - 1

Answers

Answer 1
Answer:

Answer:

See the image for the answer... Hope this helps!


Related Questions

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Which tables contain correct pairs of input and output values for the function ? Select all the correct answers. Input (x) -1.6 0.4 2.2 3.7 Output f(x) -5.5 2.5 6.75 10.75 Input (x) -2.7 -1.3 0.8 4.4 Output f(x) -5.25 -1.75 3.5 12.5 Input (x) 1.1 2.4 5.3 6.9 Output f(x) 4.25 7.5 11.75 17.25 Input (x) -2.1 0.9 1.7 3.3 Output f(x) -3.75 3.75 5.75 9.75 Input (x) 2.4 3.5 4.6 5.0 Output f(x) 7.5 10.5 12.5 14

Answers

The right answer for the question that is being asked and shown above is that: 
Input (x) -1.6 0.4 2.2 3.7
Output f(x) -5.5 2.5 6.75 10.75

Input (x) 1.1 2.4 5.3 6.9
Output f(x) 4.25 7.5 11.75 17.25

Input (x) 2.4 3.5 4.6 5.0
Output f(x) 7.5 10.5 12.5 14

Answer:

A,C and E

Step-by-step explanation:

i just took the plato test

What is the volume of the right prism? A.
166 in3

B.
140 in3

C.
64 in3

D.
16 in3

Answers

I saw the image that should have been included in this problem.

It was a rectangular prism. It can also be identified as a right prism because its bases are aligned one directly above the other and its lateral faces are rectangular.

The image has the following measurements:
length = 7 inches
width = 5 inches
height = 4 inches

volume = length * width * height
v = 7 in * 5 in * 4 in
v = 140 in³  Choice B.

360

for me it was 360.

Gabriella is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by (y+3)^2=26(x-2) where x and y are measured in inches. Where should she place the bulb to ensure a perfect beam of light?

Answers

Answer:

Step-by-step explanation:

The answer is C.

Just took the test

Solve the equation for the variable b.
a/b = c

Answers

the answer is a=bc i know I'm correct 
just multiply both sides by b

a=cb

then divide both sides by c
 a/c = b

so b = a/c

Karissa eats 400 bananas per day. using f(x)=400x•422, where x is the amount of time in days, and f(x) is the amount of potassium in karissa's bones in Mg. how much radiation has she built up over 14 days, if there is 0.1 mSv of radiation per 422 milligrams of potassium.equation: f(x)=400x•422

Answers

Answer:

560 mSv of radiation

Step-by-step explanation:

To calculate how much radiation Karissa has built up over 14 days, we need to first calculate the amount of potassium in her bones after 14 days. We can do this using the function f(x):

\sf f(x) = 400x \cdot 422

where x is the amount of time in days, and f(x) is the amount of potassium in Karissa's bones in milligrams.

To calculate the amount of potassium in Karissa's bones after 14 days, we would simply substitute x = 14 into the function:

f(14) = 400 × 14 × 422

f(14) = 2363200 milligrams

Now that we know how much potassium is in Karissa's bones, we can calculate how much radiation she has built up.

We know that there is 0.1 mSv of radiation per 422 milligrams of potassium, so we can simply multiply the amount of potassium in Karissa's bones by 0.1 mSv/422 mg to calculate the amount of radiation she has built up:

\begin{aligned} \textsf{Radiation amount }&= \sf 2363200 milligrams * 0.1 mSv/422 mg \n\n & = \sf 560 mSv \end{aligned}

Therefore, Karissa has built up 560 mSv of radiation over 14 days.

Step-by-step explanation:

Substituting x = 14, we have f(14) = (400)(14)(422) = 2,363,200 mg of Potassium accumulated.

This is equivalent to (2363200)(0.1/422) = 560 mSv of radiation.

Diagonals AC and BD of a rhombus ABCD meet at O . If AC=8cm and BD=6cm , find sin √OCD.

Answers

Due to the symmetry of the rhombus; AC = 2OC and BD = 2OD. Hence, we can say that OC is 4cm and OD is 3cm. Then we can say that sin(OCD) = OC/CD [CD = sqrt(OC^2 + OD^2)].

At the end, did you mean sqrt(sin(ocd)) or sin(sqrt(ocd)). Either way you can find angle OCD by doing arcsin(OC/CD).