Which story problem could be solved using the given equation?1/4 × 3/5 = m

Responses

A There is 35 of a box of dog treats in the cupboard. Jill’s dog eats 14 of a box of treats in a week. How many weeks of treats are left in the box for Jill’s dog?

B There is , fraction 3 over 5 end fraction, , of a box of dog treats in the cupboard. Jill’s dog eats , fraction 1 over 4 end fraction, of a box of treats in a week. How many weeks of treats are left in the box for Jill’s dog?

C Christie hiked 14 mile on the trail. Jackie hiked 35 mile farther than Christie. How far, in miles, did Jackie hike on the trail?
Christie hiked , fraction 1 over 4 end fraction, , mile on the trail. Jackie hiked , fraction 3 over 5 end fraction, , mile farther than Christie. How far, in miles, did Jackie hike on the trail?

D Shawn made a poster that has a width of 14 meter and a length of 35 meter. What is the perimeter, of Shawn’s poster?
Shawn made a poster that has a width of , fraction 1 over 4 end fraction, , meter and a length of , fraction 3 over 5 end fraction, , meter. What is the perimeter, of Shawn’s poster?

E In Sophie’s doll collection, 35 of the dolls are in their original boxes. Sophie plans to donate 14 of the dolls in these boxes to charity. How much of her doll collection will Sophie donate to charity?

Answers

Answer 1

Answer:

Answer: The story problem that could be solved using the given equation is E. In Sophie’s doll collection, 35 of the dolls are in their original boxes. Sophie plans to donate 14 of the dolls in these boxes to charity. How much of her doll collection will Sophie donate to charity?

To solve this problem, we can multiply the fractions 1/4 and 3/5 to find the fraction of the doll collection that Sophie will donate. Using the equation 1/4 × 3/5 = m, we can simplify the fractions by multiplying the numerators and denominators:

m = (1 × 3) / (4 × 5) m = 3 / 20

Therefore, Sophie will donate 3/20 of her doll collection to charity. This fraction can also be written as a decimal or a percentage:

m = 3 / 20 m = 0.15 m = 15%

I hope this helps!

Related Questions

324 is the same as the sum of 144 and v
Help please! Thanks
A soccer player boasts that he is able to kick a ball past 100 yards on 5 consecutive tries. You know that he's usually able to kick that distance 20% ofthe time. You create a model of how he kicks and run a simulation based on it, using (0 - 1) to represent his successes at kicking past 100 yards. 56421 88976 54893 20015 46504 98746 13210 77410 How many consecutive kicks past yards does the model show for the player? A. 3 B. 2 C. 0 D. 1
Is -2 or 4 a root of the equation x^2-2x=8?
Benito spent $1837 to operate his car last year. Some of these expenses are listed below. Benito's only other expense was for gasoline. If he drove 7600 miles, what was the average cost of the gasoline per mile?

Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66

Answers

The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.

Answer:

42nd term is 111

Step-by-step explanation:

$a_1=-12,a_(27)=66$

Now, Using formula of nth term of an A.P. we have :

$a_n=a+(n-1)* d\n\text{Take n=27}\n\implies a_(27)=-12+(27-1)* d\n\implies 66=-12+26\cdot d\n\implies 26\cdot d = 78\n\implies d = 3$

Now, first term a = -12 , n = 42 and d = 3

So, 42nd term is :

$a_(42)=-12+(42-1)* 3\n\implies a_(42)=-12+41* 3\n\implies a_(42)=-12+123\n\bf\implies a_(42)=111$

Hence, 42nd term is 111

The reciprocal of of 1 over 5

Answers

The reciprocal of 1/5 is: 5/1 or just 5.

To get the reciprocal of a fraction, it basically just means to flip the numbers. If you're dealing with a whole number (such as 5 in this case), you would divide 1 by the number, making it 1/5.

A new car is purchased for 15500 dollars. The value of the car depreciates at 7.5% per year. What will the value of the car be, to the nearest cent, after 6 years?