PLEASE HELP, I NEED THIS ANSWERED!

Answers

Answer 1

Answer:

Answer:

The sentence that describes the movement of matter and energy in the water cycle is:

C. Energy from sunlight warms the ocean surface and causes water to evaporate.

Explanation:

In the water cycle, energy from sunlight plays a crucial role in causing water to evaporate from the ocean surface. This evaporation process occurs when the sun's energy heats up the water, increasing its temperature. As a result, the water molecules gain enough energy to break free from the liquid state and transform into water vapor, which rises into the atmosphere. This step represents the movement of both matter (water) and energy (sunlight) in the water cycle.

If this answer is not correct I am truly sorry.

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Complete the passage to describe wave interaction of diffracted waves.Diffracted waves of light interact with other waves and interference occurs. When the interference is constructive, this is shown as a band on the screen. When the interference is destructive, this is shown as a band on the screen.
Physics help!! 10ptA small object placed in the gravitational field of a more massive object willA. accelerate toward the more massive object.B. accelerate away from the more massive object.C. move toward the more massive object at a constant speed.D. move away from the more massive object at a constant speed.
John can travel to atlanta 560 miles in 9 hours what is his velocity
Which type of bond will sulfer (S) and nitrogen (N) form?a. metallic bondb. covalent bondc. iconic bond

A friend tosses a baseball out of his second floor window with initial velocity of 4.3m/s(42degrees below the horizontal). The ball starts from a height of 3.9m and you catch the ball 1.4m above the ground.a) Calc the time the ball is in the air (ans. 0.48s)
b)Determine your horisontal distance from window (ans. 1.5 m)
c)Calc the speed of ball as you catch it (ans: 8.2m/s)

I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?

Answers

Answer:

Part a)

$t = 0.48 s$

Part b)

$x = 1.5 m$

Part c)

$v = 8.23 m/s$

Explanation:

As we know that the velocity of ball is

$v = 4.3 m/s$

now the two components of velocity is given as

$v_x = 4.3 cos42 = 3.19 m/s$

$v_y = 4.3 sin42 = 2.88 m/s$

Part a)

now in Y direction we will have

$y = y_o + v_y t + (1)/(2)gt^2$

$1.4 = 3.9 - 2.88 t - 4.9 t^2$

so we have

$t = 0.48 s$

Part b)

Now the distance covered by the ball in horizontal direction is given as

$x = v_x t$

$x = 3.19 * 0.48$

$x = 1.5 m$

Part c)

speed in x direction will always remain the same

so we have

$v_x = 3.19 m/s$

speed in y direction is given as

$v_y = v_i + at$

$v_y = 2.88 + (9.8)(0.48)$

$v_y = 7.58 m/s$

So final speed will be

$v = √(v_x^2 + v_y^2)$

$v = 8.23 m/s$

Suppose the angular separation of two stars is smaller than the angular resolution of your eyes. How will the stars appear to your eyes?

Answers

Answer:

The two stars will look like a single point of light.

Explanation:

When the angular separation is smaller than angular resolution, the eye will not be able to resolve the stars thus they will appear like a point source of light.Angular resolution is one of the limit that our eyes can see. Angular resolution describes how much our eyes can distinguish two things apart which depends on the angle created by the incoming light rays from the two object. A smaller angle, very small angle for light rays to enter the eye thus little or no details for the eye to distinguish.

Final answer:

When two stars are closer together than the angular resolution of our eyes, they appear as a single point of light.

Explanation:

When the angular separation of two stars is smaller than the angular resolution of our eyes, they will appear as a single point of light to our eyes. This is because our eyes cannot distinguish the individual stars due to their close proximity. This is similar to how distant stars appear as pinpoints of light.

Learn more about Angular separation of stars here:

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A road with a positive cross slope is highest __________.

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A road with a positive cross slope is highest in the center of the road.

The roads with Cross slopes are formed to provide the drainage system so that water will run off from the surface. Due to this no water stands on the roads, especially when there is heavy rain it is very useful. It is a very important safety factor.

A 0.09 kg marble sits at rest on the top of a sloping, frictionless track.a. If the slope has a height of 1.5 m, calculate the velocity of the marble at the bottom of
the slope.

Answers

Answer:

Explanation:

Notice that nothing but the mass and height are given, and the mass is not really necessary. It will cancel when we do the problem.

So the potential energy at the top equals the Kinetic energy at the bottom.

PE_top = Ke_bottom

mgh = 1/2 m v^2 Divide by m

mgh/m =1/2 mv^2/m

gh = 1/2 v^2 Multiply both sides by 2

2gh = v^2

Givens

g = 9.81

h = 1.5

Solution

2*9.81 * 1.5 = v^2

29.43 = v^2

v = sqrt(29.43)

v = 5.425

An explosion occurs 340 km away. Given that sound travels at 340 m/s, the time the sound takes to reach you is a. 1 s.
b. 10 s.
c. 100 s.
d. 200 s.
e. more than 200 s.

Answers

(340,000 meters) / (340 meters/sec) = 1,000 seconds

That's more than 200 sec.

first convert 340km into 340,000m, and 340000/340=1000. So the answer is e.

Which is an IUPAC name for a covalent compound

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In naming covalent compound (binary) based in IUPAC naming, we have 4 rules to be followed:

1. The first element of the formula will use the normal name of the given element. for example: CO2 ( Carbon Dioxide), Carbon is the element name of the first element of the formula.

2. The second element is named as if they are treated like an anion but put in mind that these are no ions in a covalent compound but we put -ide on the second element as if it is an anion.

3. Prefixes are used to indicate the number of atom of the elements in the compound. for example: mono- 1 atom, di- 2atoms, tri- 3 atoms and etc

4. Prefix "mono"is never used in naming the first element. For example: Carbon dioxide, there should be no monocarbon dioxide.

An IUPAC name for a covalent compound is ethane. For covalent compounds, IUPAC names are based on the composition and structure of the molecules. Covalent compounds typically consist of nonmetals or a combination of nonmetals and metalloids.

Ethane (C₂H₆) is a covalent compound that consists of two carbon atoms bonded to each other with single bonds, and each carbon atom is also bonded to three hydrogen atoms.

Other examples of IUPAC names for covalent compounds include:

Methane (CH₄)

Propane (C₃H₈)

Ethene (C₂H₄)

Nitrogen dioxide (NO₂)

These names are derived based on the IUPAC rules for naming covalent compounds, which consider the number and types of atoms present in the molecule.

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