What is 85 percent of a 28 year prison sentence?

Answers

Answer 1
Answer:

Answer:

23.8 years

Step-by-step explanation:

85% can be written as 0.85

0.85 * 28 = 23.8 years


Related Questions

Does anyone know this one ????
Need help with 3,4 and 6
How to calculate percentage
Solve the following system using the substitution method.9x + 8y = 15-5x + 12y = -107(x, y) = ( , )
The sum of two numbers is 14. the larger number minus three times the lesser number -2. what is the lesser number?

the length of a rectangle is 3 inches more than its width. if the length of the diagonal is 15 inches, find the dimensions of the rectangle

Answers

L = W + 3

L^2 + W^2 = 15^2
L^2 + W^2 = 225
L^2 + W^2 = 225

(W+3)^2 + W^2 = 225
W^2 + 6W + 9 + W^2 = 225
2 W^2 + 6W = 216
2W^2 + 6W -216 = 0

W = 9
L = 12

Final answer:

The dimensions of the rectangle are determined by setting up and solving a quadratic equation using the Pythagorean theorem, based on the provided conditions; the width of the rectangle is 'w', its length is 'w + 3', and the length of the diagonal is 15 inches.

Explanation:

In this problem, we are exploring the dimensions of a rectangle. Let's represent the width of the rectangle as 'w'. Then its length, according to the problem, is 'w + 3'. Next, we will apply the Pythagorean theorem because we are told the length of the diagonal is 15. In a rectangle, the diagonal, the length, and the width form a right triangle.

Applying the Pythagorean theorem, we get: (w)^2 + (w + 3)^2 = (15)^2. Solving this quadratic equation will give us the values for w and consequently for the length.

Take into account that the unit for these measures is in inches.

Learn more about Rectangle dimensions here:

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What is the most direct use of a compass in geometric constructions?A) to draw congruent angles


B) to draw arcs of a given size



C) to draw perpendicular lines



D) to draw straight lines

Answers

The most direct use of a compass in geometric constructions is to draw arcs of a given size.

What is the compass in geometry?

In geometry, a compass is a tool for drawing circles and arcs.

It consists of two arms, one with a pointed end and the other with a pencil or pen.

We have,

A compass is a tool used for drawing circles and arcs.

By adjusting the distance between the two arms of the compass, it can be used to draw circles and arcs of various sizes.

While a compass can also draw congruent angles and perpendicular lines, these constructions often require additional steps beyond simply drawing an arc of a given size.

Drawing straight lines typically requires using a straightedge, which is a different tool than a compass.

Thus,

The most direct use of a compass in geometric constructions is to draw arcs of a given size.

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(B) To draw arcs of a given size

Find the distance between the points (1, 4) and (-2, -1).

Answers

The distance between the two points is √34

Distance between two points

The formula for calculating the distance between two points is expressed as:

  • D = √(x2-x1)² + (y2-y1)²

Given the coordinate points (1, 4) and (-2, -1). Substitute into the formula to have:

D = √(-1-4)² + (-2-1)²

D = √(-5)² + (-3)²

D = √25 + 9

D = √34

Hence the distance between the two points is √34

Learn more on distance here: brainly.com/question/23848540

Answer:

(3,5)count manually to get(3,5)

Mr. Li records the measures of the lengths of his students’ handprints. The lengths, in centimeters, are shown in the table.14.0 , 11.5 , 12.1 , 16.2 , 13.5 , 14.3 , 16.8
12.4 , 13.7 , 12.0 , 14.7 , 15.2 , 11.9 , 15.6
13.8 , 14.2 , 12.5 , 15.0 , 16.0 , 13.1 , 11.7

If the class creates a histogram of the data in the table, how many students are in the range 12 cm to 13.9 cm?

1) 3
2) 4
3) 7
4) 8

Answers

The correct answer is:

4) 8

Explanation:

We want to find the frequency of this range. To do this, we count how many values fall between 12.0 and 13.9. There are 8 total values that do this, so the answer is 8.

In the given data set, there are 7 values in the given range.

How many students are in the range 12 cm to 13.9 cm?

Here we just need to find the number of values between 12cm and 13.9 cm, from the given table, these are:

12.1 cm, 13.5 cm, 12.4 cm, 13.7 cm, 13.8 cm, 12.5 cm, 13.1 cm

So there are 7 values in the given range, which means that 7 students are in the range of 12cm and 13.9cm.

Then the correct option is the third one.

If you want to learn more about data sets:

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Factor the following expression completely please put A,B,C,D as the answer thanks:)

Answers

64x^6-x^4=x^4(64x^2-1)=x^4\left[(8x)^2-1^2\right]=x^4(8x-1)(8x+1)\n\n\n\na^2-b^2=(a-b)(a+b)
1)x^4(8x-1)^2
=x^4(64x^2-16x+1)
=64x^6-16x^5+x^4

2)(8x^3-x^2)^2
=64x^6-16x^5+x^4

3)x^4(8x-1)(8x+1)
=x^4(64x^2-1)
=64x^6-x^4

4)x^4(64x^2-1)
=64x^6-x^4

a dog weighs 44 pounds and the veterinarian thinks i needs to lose 7 pounds. Milkala wrote the equation x+7 to represent the situation. Kirk wrote the equation 44- x = 7. Which equation is correct? can you write another equation that represents the situation?

Answers

so assuming that you meant that the dog needs to lose 7 pounds
the equation should be
44-7=x
where x represents the dog's ideal weight

x+7 means 7 more pounds
44-x=7 means that 44 minus the ideal weight is 7
this can be reweiten as 44-7=x so this is correct


Kirk is correct
another equation is 44-7=x

Hmmm I don't think either is correct.

So he weighs 44 pounds, and needs to lose 7 pounds

44 - 7 = x

where x is the dog's new weight.