If the sun rises at 5 am and sets at 6 pm, what is the length of the day? a) 11 hours b) 12 hours c) 13 hours d) 24 hours

Answers

Answer 1
Answer:

Answer:

24 hours

Explanation:


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If you squeeze the bottom of a closed tube of toothpaste, the pressure is increased ____.

Answers

The cap will pop of,THE SEAL WILL BREAK, or the tube will explode.
The cap will pop off and it may fly or hurt somebody.

A substance has a melting point of 0 degrees celsius and a boiling point of 100 degrees celsius. The substance is most likely a.) water
b.) hydrogen
c.) gold
d.) table salt

Answers

The correct answer is A. The parameters laid out here describe water,which has a melting point of 0 degrees Celsius and a boiling point of100 degrees Celsius. These descriptors are not true of any of thealternative answers.

In a motor, the combined effect of electric currents and magnetic forces turn electrical energy into which of the following? A.
a battery

B.
a generator

C.
mechanical energy

D.
electromagnetic energy

Need help
@Akin
@AL2006

Answers

it doesn't turn it into a battery (storatge of energy) or a generator (maker of energy)

it is making it into a type of energy

mechanical or electromagnetic energy

if you look at how a motor works, the electric current passes throught the wire and alternates csueing the motor to spin so I would say electormagnetic

Answer:

C. Mechanical Energy

Explanation:

Took the test

Imagine you are holding an apple. Does this apple have energy?how do you know?

Answers


-- The apple has heat energy.  If its temperature were Absolute Zero,
then the skin on my hand would freeze instantly and fall off.

-- The apple has potential energy, relative to the ground.  If I were to
release it out of my hand, gravity would do work on it and pull it with
some speed to the ground, where it would have the kinetic energy to
break some blades of grass and dig a small crater in the soil.

-- The apple has chemical energy which, if I were to expose it to
human digestion and metabolism by eating it, would change to
glucose, soak into my muscles, and make itself available to me
whenever I need vim and vigor, mental alertness, visual acuity,
and the wherewithal to to escape any unexpected beast that might
in turn set upon me with the intention of converting MY entire person
into food energy for its own use.

Question 4 4. Two blocks A of mass 15kg and B of unknown mass are connected by a light inextensible string on a rough horizontal surface. A constant force of magnitude 120N is applied onto block A at an angle of 30° to the horizontal as shown in the diagram below. The coefficient of kinetic friction for both blocks is 0.2 and the system of blocks accelerates to the right at 2.08m.s2. B Question 5 A 15 kg 30° 4.1. State Newton's Third law of motion in words 4.2. Draw a labelled free-body diagram for block A 4.3. Show that the frictional force acting on block A as it accelerates is 14.7N 4.4. Calculate the mass of block B [18] 120N (2) (5) (5) [16]​

Answers

Answer:

4.1. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. In other words, when one object exerts a force on another object, the second object exerts an equal force in the opposite direction on the first object.

4.2. Here's a labeled free-body diagram for Block A:

```

T (tension in the string)

F (applied force)

──→ (direction of motion)

```

In this diagram, "T" represents the tension in the string, and "F" represents the applied force at an angle of 30° to the horizontal. The arrow indicates the direction of motion.

4.3. To find the frictional force acting on block A as it accelerates, we can use Newton's Second Law:

\[F_{\text{net, A}} = m_A \cdot a\]

Where:

- \(F_{\text{net, A}}\) is the net force acting on block A.

- \(m_A\) is the mass of block A (given as 15 kg).

- \(a\) is the acceleration (given as 2.08 m/s²).

Rearranging the equation to solve for \(F_{\text{net, A}}\):

\[F_{\text{net, A}} = 15 kg \cdot 2.08 m/s² = 31.2 N\]

Now, we need to consider the frictional force, which opposes the motion and acts in the direction opposite to the applied force. So, the frictional force is 31.2 N in the opposite direction of motion, making it:

Frictional force on block A = -31.2 N

However, since you want it in magnitude, it's 31.2 N.

4.4. To calculate the mass of block B, we can use the fact that block A and block B are connected by a string, so they experience the same acceleration. Therefore, we can use the following equation:

\[F_{\text{net, B}} = m_B \cdot a\]

Where:

- \(F_{\text{net, B}}\) is the net force acting on block B, which is the tension in the string.

- \(m_B\) is the mass of block B (unknown).

- \(a\) is the acceleration (given as 2.08 m/s²).

We already calculated that the tension in the string is 31.2 N. Plugging in the values:

\[31.2 N = m_B \cdot 2.08 m/s²\]

Now, solving for \(m_B\):

\[m_B = \frac{31.2 N}{2.08 m/s²} \approx 15 kg\]

So, the mass of block B is approximately 15 kg.

Why would you expect sodium (Na) to react strongly with chlorine (Cl)?1. They both need to lose one electron.
2. They both need to gain one electron.
3. Sodium needs to lose one electron, and chlorine needs to gain one electron.
4. Sodium needs to gain one electron, and chlorine needs to lose one electron.

Answers

Answer: The correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".

Explanation :

The electronic configuration of sodium (Na) is 1s^2\ 2s^2\ 2p^6\ 3s^1. It has only one vacant electron.

While the electronic configuration of chlorine is 1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^5. It has seven valance electrons.

When Na reacts with Cl, Na will lose one electron and this lost electron gets transferred to chlorine. This forms a strong ionic bond.

So, the correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".

3. is the answer, Sodium needs to lose one electron, and chlorine needs to gain one electron. This is because Sodium's row always wants to give away an electron, while Chlorine's row wants to gain an electron.