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Answer:

정말 고맙습니다!!!!!

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What’s 9 + 10 = 21
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What 2 numbers multiply to be -14 and add to be -3

Answers

xy = -14
x + y = -3

xy = -14
(xy)/(x) = (-14)/(x)
y = (-14)/(x)

x + y = -3
x + (-14)/(x) = -3
(x^(2))/(x) + (-14)/(x) = -3
(x^(2) - 14)/(x) = -3
x^(2) - 14 = -3x
x^(2) + 3x - 14 = 0
x = \frac{-(3) \± \sqrt{(3)^(2) - 4(1)(-14)}}{2(1)}
x = (-3 \± √(9 + 56))/(2)
x = (-3 \± √(65))/(2)
x = (-3 \± 8.06)/(2)
x = -1.5 \± 4.03
x = -1.5 + 4.03    or    x = -1.5 - 4.03
x = 2.53    or    x = -5.53

        x + y = -3
   2.53 + y = -3
 - 2.53         - 2.53
              y = -5.53
        (x, y) = (2.53, -5.53)
         
         x + y = -3
  -5.53 + y = -3
+ 5.53         + 5.53
              y = 2.53
        (x, y) = (-5.53, 2.53)

The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.

Answer:

number one is corout

Step-by-step explanation

Ed has 5 coins all of which are quarters and pennies in all they worth 53 cent how many of each kind of coins does Ed have​

Answers

Answer:

1 Coin is a quarter and thats 25c then another coin is also a quarter and thats 50c so he has 3 pennis which makes it 5 coins and that gives you 53c

Step-by-step explanation:

Answer:

2 quarters and 3 pennies

Step-by-step explanation:

1 quarter= 25 cents

1 penny= 1 cent

if it were 1 quarter and 4 pennies, it would equal 29 cents, which is too little. if it were 3 quarters and 2 pennies, it would equal 77 cents, which is too much. But 2 quarters and 3 pennies equal exactly 53 cents.

An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. This similar to the current problem as you have to consider the 25 mph tailwind and headwind. Plane on outbound trip of 4 hours with 25 mph tailwind and return trip of 5 hours with 25 mph headwind Let r = the rate or speed of the airplane in still air. Let d = the distance a. Write a system of equations for the airplane. One equation will be for the outbound trip with tailwind of 25 mph. The second equation will be for the return trip with headwind of 25 mph.
b. Solve the system of equations for the speed of the airplane in still air.

Answers

Answer:

r  = 225 Mil/h     speed of the airplane in still air

Step-by-step explanation:

Then:

d  is traveled distance   and r  the speed of the airplane in still air

so the first equation is for a 4 hours trip

as  d = v*t

d  =  4 *  ( r  + 25)    (1)          the speed of tail wind  (25 mil/h)

Second equation the trip back in 5 hours

d  =  5  * ( r  - 25 )    (2)

So we got a system of two equation and two unknown variables  d  and

r

We solve it by subtitution

from equation (1)     d  =  4r  + 100

plugging in equation 2

4r  + 100  = 5r -  125    ⇒   -r  =  -225     ⇒    r  = 225 Mil/h

And distance is :

d  =  4*r  +  100         ⇒ d  =  4 * ( 225)  +  100

d  =  900 +   100

d  = 1000 miles

What is 8/32 is simplest form

Answers

(8)/(32)=(8:2)/(32:2)=(4)/(16)=(4:2)/(16:2)=(2)/(8)=(2:2)/(8:2)=\boxed{(1)/(4)}
8/32 is 1/4 in its simplists form as 8 is the highest number that divdes the top and bottom

The average rate of change of f(x) is given by the formula f(7)-f(3)/4 . Over what interval does this formula give the average rate of change for f(x)?The answer choices are
A. [4,7]
B. [-7,3]
C. [3,7]
D. [3,4]

Answers

Answer:

Option C is correct

[3,7]

Step-by-step explanation:

Average rate of change(A(x)) of f(x) over an interval [a, b] is given by:

A(x) = (f(b)-f(a))/(b-a)

As per the statement:

The average rate of change of f(x) is given by the formula:

A(x) = (f(7)-f(3))/(4)

we can write this as:

A(x) = (f(7)-f(3))/(7-3)

By definition, we have

b = 7 and a = 3

⇒interval = [3, 7]

Therefore, the interval does this formula give the average rate of change for f(x) is,  [3,7]

Answer:

the answer is c


Step-by-step explanation: