a. How much energy is needed to raise the temperature of a 75 g sample of aluminum from 22.4°C to 94.6°C?

Answers

Answer 1
Answer: To calculate the energy required to raise the temperature of a substance, you can use the formula:

Q = m * c * ΔT

Where:
Q is the energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in joules per gram-degree Celsius)
ΔT is the change in temperature (in degrees Celsius)

For aluminum, the specific heat capacity is approximately 0.897 J/g°C.

Given:
Mass of aluminum (m) = 75 g
Specific heat capacity of aluminum (c) = 0.897 J/g°C
Change in temperature (ΔT) = 94.6°C - 22.4°C = 72.2°C

Substituting the values into the formula:

Q = 75 g * 0.897 J/g°C * 72.2°C

Calculating the result:

Q = 4846.35 J

Therefore, approximately 4846.35 joules of energy are needed to raise the temperature of a 75 g sample of aluminum from 22.4°C to 94.6°C.
Answer 2
Answer:

Introduction:

Understanding the amount of energy required to change the temperature of a substance is fundamental in many fields, from chemistry and physics to engineering and everyday applications. In this case, we're looking at how much energy it takes to heat a 75 g sample of aluminum.

Specific Heat Capacity of Aluminum:

To determine the energy required, we first need to consider the specific heat capacity of aluminum. The specific heat capacity (c) is a unique property of each material and represents the amount of heat energy needed to raise the temperature of 1 gram of that substance by 1 degree Celsius (or 1 Kelvin). For aluminum, the specific heat capacity (c) is approximately 0.897 J/g°C (joules per gram per degree Celsius).

Mass of the Sample:

The next piece of the puzzle is the mass of the aluminum sample. You mentioned that it's 75 grams, so we'll use that value in our calculations.

Change in Temperature:

We're looking to raise the temperature of the aluminum from 22.4°C to 94.6°C. To find the change in temperature (ΔT), we subtract the initial temperature from the final temperature:

ΔT = 94.6°C - 22.4°C = 72.2°C

Calculating the Energy:

Now, we can use the specific heat capacity formula to calculate the energy (Q) needed to raise the temperature of the aluminum sample:

Q = m * c * ΔT

Where:

Q is the energy in joules (J).

m is the mass of the sample (75 g).

c is the specific heat capacity of aluminum (0.897 J/g°C).

ΔT is the change in temperature (72.2°C).

Plugging in these values:

Q = 75 g * 0.897 J/g°C * 72.2°C

Q ≈ 4863.15 J

Conclusion:

Therefore, approximately 4863.15 joules of energy are needed to raise the temperature of a 75 g sample of aluminum from 22.4°C to 94.6°C. This calculation is essential in various scientific and practical applications, from cooking to materials engineering, and helps us understand the energy requirements for temperature changes in different substances.


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Answers

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What is an ionic bond?

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To know more about an ionic bond, here:

brainly.com/question/977324

#SPJ2

The type of bond that results when one or more valence electrons are transferred from one atom to another is the ionic bond. The answer is number 2. The rest of the choices do not answer the question above.

when 200 grams of water cools from 50 c to 25 c the total amount of heat energy released by the water is?

Answers

Answer : The heat released by the eater is, 2.1* 10^4J[/tex]

Explanation :

Formula used :

Q=m* c* \Delta T

or,

Q=m* c* (T_2-T_1)

where,

Q = heat released = ?

m = mass of water = 200 g

c = specific heat of water = 4.184J/g^oC

T_1 = initial temperature  = 50^oC

T_2 = final temperature  = 25^oC

Now put all the given value in the above formula, we get:

Q=200g* 4.184J/g^oC* (25-50)^oC

Q=20920J=2.1* 10^4J[/tex]

Therefore, the heat released by the eater is, 2.1* 10^4J[/tex]

Specific Heat:
Heat Energy= Mass of substance X Specific Heat X Change in Temp. 
1. change in temp |50-25| = 25
2. specific heat of Water(H2O) = cal/g (Celsius) 1.000
heat energy= 200g X 1.000 X 25
Heat energy = 5000cal