Give the significant figures of 0.011cm

Answers

Answer 1

Answer:

Answer:

0.011 has 2 significant figures

Explanation:

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Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is 4.5 × 10^-4. Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is
4.5 × 10^-4.

Answers

HNO2 =====> H+ + NO2-
Initial concentration = 0.311
C = -x,x,x
E = 0.311-x,x,x

KNO2 ====>K+ + NO2-
Initial concentration = 0.189
C= -0.189,0.189,0.189
E = 0,0.189,0.189

34. Many bicycles have generators that have a light that can be powered without a battery.Instead of a battery, a magnet and a coil of wire are used to make an electric current flow. The
setup shown below models how a bicycle generator functions to produce light. Currently, no
electric current is flowing through the circuit shown.
What needs to happen to cause an electric current to flow through the circuit?
A. The magnet needs to be in constant motion.
B. A bigger light bulb needs to be used.
C. The magnet's north pole needs to point up.
D. A smaller wire needs to be used.

Answers

A the magnet needs to be in motion

In order to observe a property of a substance, the substance must interact with another substance, such as when gasoline burns or when sodium metal reacts with water.

Answers

Observing a property of a substance can be done through experiments. Most of these experiments are done by a chemical reaction. A chemical reaction involves two substances interacting with each other. However, not all property of a substance can only be observed through a reaction. Like melting experiment, freezing point determination and boiling point determination, only heat is added or is removed to the substance in order to see that certain property.

answer:

chemial

Explanation:

chemical reactions include the reactivity of an object. physical properties do not include reactivity and electrical and thermal properties are not reactivity either

Cations are formed by _____. gaining protons losing protons gaining electrons losing electrons

Answers

Cations are formed by losing electrons in the valence shell of atoms. There are more protons than electron ions making the atom more positive.

An anion has gained electrons and therefore has more electrons than protons. It has a negative charge.

An example if this doesn't make too much sense.

Charged Atoms: If electrons are removed from an atom, that atom becomes positively charged because it has more positive charge carriers (protons) than negative charge carriers (electrons)

These types of charged atoms are called positive ions or, cations. DEPENDING ON THE CIRCUMSTANCES, the removed electrons can remain free or they may attach themselves to another atom that can accept extra electrons. If this occurs, a negatively charged ion, or anion, is created.

I hope I made this clear enough for anyone who needed help on this. Hope this helps!!! Have a great day :)))

How do you draw a bohr diagram for a boron ion? Some backgorund info: (of boron atom)
Atomic no- 5
Mass no- 11
Cation

Answers

Because Boron likes to lose 3 electrons when it undergoes ionization, we draw a boron ion like a helium atom, with just 2 electrons in the first shell, and 0 in the second

it's core charge would be +3

Explanation:

it's core charge would be +3

Explanation:

Calculate the molecular weight of a dibasic acid.0.56gm of which is required 250ml of N/20 sodium hydroxide solution for neutralization.

Answers

Answer: The molecular weight of the dibasic acid is 89.6 g/mol

Explanation:

Normality is defined as the amount of solute expressed in the number of gram equivalents present per liter of solution. The units of normality are eq/L. The formula used to calculate normality:

$\text{Normality}=\frac{\text{Given mass of solute}* 1000}{\text{Equivalent mass of solute}* \text{Volume of solution (mL)}}$ ....(1)