A playground ball has a diameter of 18 cm. What is the hieght and base of the ball? What is the volume?

Answers

Answer 1

Answer: Well it really depends but since I only know the diameter I'm not sure of the answer but the circumference is 56.52 (Vertical Multiplication).

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Solve 3x + 70 - 7x is greater than or equal to 18

Answers

Okay, let's work this out.

3x+70−7x=3x+70+−7x

Combine Like Terms:=3x+70+−7x=(3x+−7x)+(70)
=−4x+70

Answer -4x+70

I really don't understand what you mean by this, perhaps you wrote the question wrong, but it would be great than 18.

PLEASE HELP. 18 pointsYou design a frame to surround a rectangular photo. The width of the frame is the same on every side as shown. write a polynomial in standard form that represents the combined area of the photo in the frame. find the combined area of the photo in the frame when the width of the frame is 4 inches.

Answers

Length of the rectangular photo = 22 inches

Width of the rectangular photo = 20 inches

Since, width of the frame outside the photo = x inches

Therefore, increase in length and width of the photo with frame = (x + x)

= 2x inches

Length of the photo with frame = (22 + 2x) inches

Width of the photo with frame = (20 + 2x) inches

Combined Area of the photo in the frame = Length × Width

= (22 + 2x)(20 + 2x)

= 22(20 + 2x) + 2x(20 + 2x)

= 440 + 44x + 40x + 4x²

= 4x² + 84x + 440

Therefore, polynomial representing the combined area of the photo in the frame will be (4x² + 84x + 440) square inches.

If width of the frame = 4 inches

Combined area of the photo = 4(4)² + 84(4) + 440

= 840 square inches

Learn more,

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Answer:

A is 4x^2+84x+440 and B=840 square inches

Step-by-step explanation:

A is 4x^2+84x+440 and B=840 square inches

The task for a is to write a polynomial in standard form that represents the combined area of the photo and the frame. First, lets start with the bottom of the picture and frame. On the bottom, you have 2x+ 22 inches. Then the side of the picture and frame is 2x+20 inches. Writing in polynomial form, it would be (2x+22)(2x+20). You would get 4x^2+84x+440 since you are using the FOIL method. Now for part b, we know that the width of the frame(or x) is 4 inches. Now we plug that into the equation. 84x is 84x4. 84x4=336 x^2 is 16. There are four of those as you can see in the equation so 16x4=64

336+64=400 inches Frame= 400 inches

400 inches plus the picture(440 inches) = 840 square inches.

HELP!!! This question has me stumped