Calculate the length of the circumference of a circle with diameter of 9.2cm?

Answers

Answer 1
Answer: All u need to do for curcumference is multiply the diameter by pi.
So you get 28.9 cm
Answer 2
Answer: Circumference=2 x pi x r
Diameter= 2 x pi
Circumference= 9.2 x pi
9.2 x 3.14 = 28.888 cm

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The graph shows two lines, A and B:A graph is shown with x- and y-axes labeled from 0 to 6 at increments of 1. A straight line labeled A joins the ordered pair 3, 0 and the ordered pair 0, 6. Another straight line labeled B joins the ordered pair 0, 0 and the ordered pair 5, 5. Based on the graph, which statement is correct about the solution to the system of equations for lines A and B? A (0, 6) is the solution to both lines A and B. B(0, 6) is the solution to line B but not to line C(2, 2) is the solution to both lines A and B. D (2, 2) is the solution to line A but not to line
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Factor 2x2 + 11x + 15 symbolically , in time plz thank you

Answers


hi,

 2x^2+11x+15=(x+3)(2x+5)  <<<ANSWER 

Hope that helps...

What is the slope of the line passing through the points (-3, 4) and (2, - 1)? A -1B 1
C 3/5
D - 5/3​

Answers

Answer:

A

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y_(2)-y_(1)  )/(x_(2)-x_(1)  )

with (x₁, y₁ ) = (- 3, 4 ) and (x₂, y₂ ) = (2, - 1 )

m = (-1-4)/(2-(-3)) = (-5)/(2+3) = (-5)/(5) = - 1 → A

. A textbook company states that the average time a student needs to take a quiz from its book is 30 minutes with a standard deviation of 3 minutes. A teacher using the book is not sure that this is correct for her classes and wants to check. She collects data on 10 random students and finds that the average time to take the quiz was only 25 minutes. As a result, the teacher performs a two-tailed hypothesis test with a significance level of 5%. Which conclusion is valid based on the results of the test? A. Her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company stated.B. The teacher should pick up all unfinished quizzes at 25 minutes because her students are so much faster than average.

C. The teacher does not have enough information to make a conclusion about the average time on the test.

D. Her students, on average, do take the 30 minutes as the textbook company stated.

Answers

Answer:

A. Her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company stated.

Step-by-step explanation:

This is a normal distribution problem with a two-tailed hypothesis test. This characteristics helps to determine the hypothesis, which is the first step in a hypothesis test.

So, the null hypothesis would be: H_(o) : u=30 min..

The alternative hypothesis would be: H_(a) : u\neq 30min.

In this problem, we don't use inequality relations because the teacher performed a two-tailed test, which only have to options, equal or not equal.

In second place, we have to determine the significance level, which is 5%, this means that the two tales rejecting zones must be equal to 5%, that is, 2.5% for each tale. This significance level is a percentage that refers to the probability of the null hypothesis to reach that zone, as you can see, it's a low probability, so if the null hypothesis reaches that zone, it means that the data has significance, it's reliable.

Now, we have to calculate the z-score, which is gonna tell us if the null hypothesis can reach the rejecting zone or not. The equation to find z-value is: Z = (x - u)/((o)/(√(n) ) ); where x is the sample mean, u is the population mean, o is the standard deviation and n is the sample.

Replacing all values:

Z = (25-30)/((3)/(√(10) ) ) = (-5)/(0.95) =-5.26.

Hence, the z-value is -5.26, which is located in the left side of the population mean. Now, we have to use the z-table to know if the null hypothesis is rejected or accepted.

So, according to the table the probability value (p-value), for a 5% of significance level, is 0.0001. But, this is a two-tailed test, so the p-value is actually 0.0001(2) = 0.0002.

Therefore, the p-value is way lower than the level of significance 0.05, we must reject the null hypothesis, which means that there's no enough evidence to accept it. So, according with the test, the students don't take 30 minutes on the quiz, the correct answer is A.

Answer:

A. is the correct answer

Step-by-step explanation:

Hope that this helps. Peace and Love

What is the unit rate of 6.50

Answers

i most likely think it is 3
2.50 ur welcome! hope this helps

Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <7, 2>, v = <21, 6>

Answers

Vectors are orthogonal if their dot product is equal to zero:
u · v = 7· 21 + 2 · 6 = 147 + 12 = 159 ≠ 0
Vectors are parallel if the angle between them is 0°, or cos ( u, v ) = 1
cos  ( u, v ) = ( u · v ) / ( | u | · | v | ) =
= 159 / (√(7² + 2²) · √(21² + 6²) ) =
= 159 / ( √ (49 + 4 ) · √ ( 441 + 36 ) ) = 
= 159 / (√53 · √477 ) = 159 / 159 = 1
Answer : The vectors u and v are parallel. 

Answer:

Parallel

Step-by-step explanation:

orthogonal: dot product of u times v= 0 degrees

utimesv= 7x21+2x6=147+12=159

Parallel: cos (u,v)=1

cos (u,v)=(u·v)/ IuI·IvI

cos (u,v)= 159/ (sqrt 7^2+2^2)·(sqrt 21^2 +6^2)

159/(sqrt 49+4) ·(sqrt 441+36)

159/(sqrt 53)·(sqrt 477)=

159/159

=1; therefore it is parallel

Solve: 3(2x - 5) = 6x - 15
A) 0
B) 1
C) 20
D) infinitely many solutions

Answers

Based on the calculations, the value of x is equal to: D) infinitely many solutions.

Given the following data:

  • 3(2x - 5) = 6x - 15

How to determine a solution.

In this exercise, you're required to solve for a solution that satisfies the given equation. Thus, we would simplify the equation and find the value of x as follows:

Opening the bracket, we have:

6x - 15= 6x - 15

Next, we would rearrange the equation by collecting like terms:

6x-6x=-15+15\n\n0=0

Read more on equations here: brainly.com/question/13170908

If you would like to solve 3(2x - 5) = 6x - 15, you can do this using the following steps:

3(2x - 5) = 6x - 15
3 * 2x - 3 * 5 = 6x - 15
6x - 15 = 6x - 15
0 = 0

The correct result would be D) infinitely many solutions.