If the velocity of a car on a timed test drive on an airfield is given by the function:V= 24t - 3t(squared)
Where v is in m/s and t is in seconds
Starting from rest, the car comes to rest again after 8 seconds. How far has it travelled during that time?
Answers
The graph of the car's speed is a piece of an inverted parabola,
that cuts the time axis at zero and at 8 sec.
The distance the car travels during that 8 seconds is the area
between the parabola and the time axis. If you intend to calculate
it, then I'm afraid you're going to need to integrate the speed function.
V = 24t - 3t²
Distance = integral of (24t - 3t²), evaluated from zero to 8 seconds.
Integral of (24t - 3t²) =
t²/2 - 3t³/3 = 12t² - t³
Evaluated between zero and 8 seconds, the integral is
12(8²) - (8)³ =
768 - 512 = 256 meters .
Related Questions
Which ratio is equivalent to 4 to 5?
Which expressions are completely factored?Choose all answers that are correct. Question 4 options: 18x^4 – 12x^2 = 6x(3x^3 – 2x) 12x^5 + 8x^3 = 2x^3(6x^2 + 4) 20x^3 + 12x^2 = 4x^2(5x + 3) 24x^6 – 18x^5 = 6x^5(4x – 3)
Please help to answer ASAP
Can you help me can you help me
Answers
the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC
base AB = 52 and vertical angle 2x + 34°
For the sine law
(sin 2x)/22 = (sin ADB)/AB
(sin 34°)/30 = (sin BDC)/BC
is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from
(sin ADC)/AB = (sin BDC)/BC
it follows
(sin 2x)/22 = (sin 34°)/30
sin 2x = 22 (sin 34°)/30
2x = asin(22 (sin 34°)/30) ≈ 24.2°
x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1°
0 < x < 12.1°
Answers
Answer:
To determine if 90209 is a perfect square, let's use the long division method:
First, find the closest perfect square below 90209, which is 300^2 = 90000.
Subtract 90000 from 90209, which gives us a remainder of 209.
Since we have a remainder after division, 90209 is not a perfect square.
The remainder obtained through long division is 209.
Final Answer:
90209 is a perfect square, and its square root using the long division method is 301.
Explanation:
To determine if 90209 is a perfect square, we can use the long division method to find its square root.
Step 1: Start by grouping the digits in pairs from right to left: 90, 20, and 9.
Step 2: Find the largest number whose square is less than or equal to 90. In this case, it's 9, as = 81. Write 9 as the first digit of the square root.
Step 3: Subtract 81 from 90, leaving 9 as the remainder.
Step 4: Bring down the next pair of digits, which is 20, and append them to the remainder, making it 920.
Step 5: Find the largest number whose square is less than or equal to 920. It's 30, as = 900. Write 30 as the next digit of the square root.
Step 6: Subtract 900 from 920, leaving 20 as the remainder.
Step 7: Bring down the last pair of digits, which is 09, and append them to the remainder, making it 2009.
Step 8: Find the largest number whose square is less than or equal to 2009. It's 1, as = 1. Write 1 as the final digit of the square root.
Now, we have the square root of 90209 as 301, and since we were able to divide it into perfect square factors without any remainder, we can conclude that 90209 is indeed a perfect square.
Learn more about perfect square
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Answers
It starts down on the left and goes up on the right and intersects the x-axis at x = -2, 2, and 3.
It starts down on the left and goes up on the right and intersects the axis at x = -2, 4, and 3.
It starts up on the left and goes down on the right and intersects the axis at x = -2, 2, and 3.
It starts up on the left and goes down on the right and intersects the axis at x = -2, 4, and 3.
Answers
The 0's of the function are -2, 2, and 3.
The graph starts from the bottom left and it keeps going to the top right.
equation cross x-axis in point x=-2, x=2, x=3
so we can choise from 1 and 3 answers:
It starts down on the left and goes up on the right and intersects the x-axis at x = -2, 2, and 3.
It starts up on the left and goes down on the right and intersects the axis at x = -2, 2, and 3.
coefficient before x³>0 so it go up
so it ís answer 1
Answer:
1. It starts down on the left and goes up on the right and intersects the x-axis at x = -2, 2, and 3
30 pounds on the moon.
If on astronaut weights
25 pounds on the moon,
how much would they
weight on earth?
Answers
Answer:
150 pounds
180/30=6 so whatever other weight you get will have to be a multiple of 6
25*6=150
Step-by-step explanation:
Answer:*80 pounds
Step-by-step explanation:
25 pounds on Earth
4 pounds on the Moon
=
500 pounds on Earth
? pounds on the Moon
Compare the numerators.
25pounds on Earth
4 pounds on the Moon
=
500pounds on Earth
? pounds on the Moon
To get from 25 to 500, multiply by 20. Multiply the numerator and denominator by 20 to find how many pounds the astronaut would weigh on the Moon.
25 pounds on Earth20
4 pounds on the Moon20
=
500 pounds on Earth
80pounds on the Moon
The astronaut would weigh 80 pounds on the Moon.