X^{2} +16xy+63y ^{2}

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Answer 1
Answer: x^(2) +16xy+63y ^(2) \n = x^(2) +16xy+64y ^(2)-y ^(2) \n = (x+8y)^(2)-y ^(2) \n =(x+8y+y)(x+8y-y) \n =(x+9y)(x+7y)

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why do whole numbers raised to an exponent get greater while fractions raised to an exponent get smaller?
Which is bigger 8/10 or 79/100
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The seventh term of an arithmetic sequence is 21, the tenth term is 126. The first term is

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Hi,
a_(10)=a_0+10*r\na_7=a_0+7*r\na_(10)-a_7=3\ \Rightarrow 126-21=3r\ \Rightarrow r=35\na_7=a_0+7*r\ \Rightarrow 21=a_0+7*35\n\Rightarrow a_0=-224\n\Rightarrow a_1=-224+35\n\boxed{a_1=-189}

62+25=25+___ what's the answer? I'm only 2 grade

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Answer: 62

Step-by-step explanation: 25 appears on both sides, so you can cancel them out. This leaves a 62 on the left side, so there also must be a 62 on the right side.

Is 1/4 rational or irrational

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a rational number can be written as a fraction with whole numbers
an irrational cannot be written as a fraction
1/4 is a fraction with whole numbers
(pi is irrational because it never ends and it's fraction form can only be estimated)

1/4 is rational
Any number that you can completely write down with digits ... and a fraction bar or decimal point if necessary ... is rational. 1/4 is the complete number so it's rational. It's as easy as that.

Solve.: -2 1/3 -(-5) A:-7 1/3 B: 2 2/3 C: 3 2/3 D: 3 1/3

Answers

Step-by-step explanation:

-2 1/3 -(-5) can be simplified as follows:

-2 1/3 + 5

= -7/3 + 15/3 (converting mixed numbers to improper fractions)

= 8/3

Therefore, the solution is 8/3, which can also be expressed as 2 2/3.

So, the answer is (B) 2 2/3.

Rewrite 4 as a fraction.

Answers

4 as a fraction is 4/1 or 8/2 or 16/4

Multiplying a number by which of the following would result in a smallest number? 10^-1 10^0 10^1 10^2

Answers

Answer:

To obtained the smallest number multiply the number with  (10)^(-1).

Step-by-step explanation:

Given : (10)^(-1),\ (10)^0,\ (10)^1,\ (10)^2

We have to find when we multiply any number with the given number which number will give the smallest value.

Consider the given numbers,

(10)^(-1),\ (10)^0,\ (10)^1,\ (10)^2

We find the values of each number one by one,

1) consider (10)^(-1), using property of exponents a^(-m)=(1)/(a^m), we have

(10)^(-1)=(1)/(10)=0.1

2) (10)^0 we know any thing to power 0 is always 1.

(10)^0=1

3) (10)^1 is same as itself that is 10.

4) (10)^2 is (10)* 10=100

Thus, To obtained the smallest number multiply the number with  (10)^(-1).

10^-1 would be the smallest answer...

10^-1= .1
10^0= 1
10^1= 10
10^2= 100