The density of mercury is 13.6 g/mL. What is the volume of a 155-gram sample of mercury?

Answers

Answer 1
Answer:

The volume of a 155-gram sample of mercury is 11.397 mL if the density of mercury is 13.6 g/mL.

What is density?

It is defined as the mass-to-volume ratio. The density indicates the object's density and is represented by the symbol. The density is measured in kilograms per cubic meter.

It is given that:

The density of mercury is 13.6 g/mL.

The mass of the mercury is 155 grams.

As we know,

Volume can be defined as a three-dimensional space enclosed by an object or thing.

The density = mass/volume

13.6 = 155/volume

volume = 155/13.6

volume = 11.397 mL

Thus, the volume of a 155-gram sample of mercury is 11.397 mL if the density of mercury is 13.6 g/mL.

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Answer 2
Answer: You need to use the density formula.

D = (m)/(V) 

DV = m

V = (m)/(D)

V = (155gHg)/(13.6(g)/(mL)Hg)

V = 11.397mL 

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If a bar magnet is cut 3 times resulting in 4 smaller magnet pieces, then each new magnet will have *A.only a N pole

B. only a S pole

C. both a N and S pole

D.neither a N nor a S pole

Answers

Answer:

I guess it was C.both a N and S pole...

Comment if I was wrong.

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this information?

Answers

Answer;

The comparison that would be best is;

They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation;

  • Beryllium (Be) is an element is the periodic table with an atomic number of 4, which means it has 4 protons in the nucleus and also 4 electrons in the energy levels, since the number of protons is equal to the number of electrons.
  • Beryllium has an electron configuration of 2: 2, which means it has two valence electrons, and has two energy levels which means it occupies period two of the periodic table, and group two of the periodic table.
  • Barium (Ba) on the other had, has an atomic number of 56, which means it has 56 protons and 56 electrons. Thus it has an electron configuration of; 2;8;18;18;8;2;  this shows that it has 6 energy levels thus occupies period 6 and is in group two since it has two valence electrons.
The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. the comparison is best supported by this information is that beryllium has a lower atomic radius than Barium

Explain why data from at least three seismic stations are needed to locate an earthquake epicenter

Answers

Each station has a circle made of possible epicenters. When you have atleast 3 epicenters you can narrow it down to 1 epicenter and there's that final point. Each station can detect how far away the epicenter was (by transverve body waves). When you only have one seismic station it's impossible to locate an earthquake epicenter.

The Lamborghini Diablo sports car can accelerate from 0.0 km/hr to 99.2 km/hr in 4.0 seconds. What is the acceleration of this car? Give your answer in units of kilometers per hour/sec.

Answers

The Lamborghini Diablo sports car can accelerate from 0.0 km/hr to 99.2 km/hr in 4.0 seconds. What is the acceleration of this car? Give your answer in units of kilometers per hour/sec. To find the acceleration of the car we have to
1.  
First determine the suitable formula for this word problem. Which is
a.   A=vf-vi/t

Given are: Vf=99.2 km/h Vi= 0.0 km/h T= 4.0sec

Solution:
A= 99.2 km/h – 0.0km/h / 4.0 sec
A = 99.2 km/h / 4 sec
A = 2.8 km/h/sec



Answer:

24.8 km per second

Explanation:

___________is a highly reactive chemical species with one or more unpaired electrons

Answers

Explanation:

A specie with no charge and containing one or more number of unpaired electrons is known as a free radical.

These free radicals tend to attain stable configuration by gaining an electron from another atom. Hence, they fill their outer energy levels.

For example, a free radical of chlorine will readily combine with a hydrogen atom in order to attain stability and it leads to the formation of a new chemical bond between the hydrogen and chlorine atom.

As a result, it will form a hydrogen free radical.

Thus, we can conclude that free radical is a highly reactive chemical species with one or more unpaired electrons.

Final answer:

A free radical is a highly reactive chemical species with one or more unpaired electrons. They actively participate in chemical reactions due to their need to complete their electron shell. These radicals can be both harmful and beneficial, depending on their context.

Explanation:

A free radical is a highly reactive chemical species with one or more unpaired electrons. These species are reactive because they seek to complete their electron shell by forming pairs, making them eager to engage in chemical reactions.

For instance, in combustion processes, free radicals like hydroxyl (OH) play a crucial role. Despite their reputation for causing damage in biological systems, free radicals are also beneficial as they are used by the immune system to neutralize pathogens.

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Use the Pythagorean theorem to answer this question. A paper airplane is thrown westward at a rate of 6 m/s. The wind is blowing at 8 m/s toward the north. What is the actual velocity of the airplane?2 m/s, northwest
10 m/s, northwest
14 m/s, northwest
48 m/s, northwest

Answers

The correct answer to the question is : 10 m/s , northwest.

EXPLANATION:

As per the question, the velocity of wind V = 8 m/s towards north.

      The velocity of the paper airplane is V' = 6 m/s towards west.

We are asked to calculate the actual velocity of the airplane.

By putting Pythagorean theorem, the actual velocity of the airplane is calculated as -

                  V_(net)^2 =\ V^2+V'^2

                ⇒  V_(net)^2=\ 6^2+8^2

                ⇒  V_(net)^2\ =\ 100

                ⇒  V_(net)=\ √(100)\ m/s

                ⇒  V_(net)=\ 10\ m/s  towards northeast.

Hence, the correct answer is 10 m/s , northwest.              

6^2 + 8^2 = 36 + 64 = 100

sqrt(100) = 10 m/s northwest