What is the value of the expression 5+(20-8) divided by 3 +6

Answers

Answer 1

Answer: $(5+(20-8) )/(3+6 ) = (5+12 )/(9) =(17)/(9)=1(8)/(9)$

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Does anyone know the answer to this ? I need help , missing angles .

Answers

The answer: 135 degrees

-1-4= 5-3x+4x
Please help me! This is kind of confusing, and I don't really understand.

Answers

-1-4=5-3x+4x
3x-4x=5+1+4
-x=10
x=-10
HOPE I HELPED!!!

$-1-4= 5-3x+4x\n-5=5+x\nx=-10$

The distance traveled by a car at a constant rate is proportional to the time spent driving. In the equation d = 45t, d represents the distance (in miles) and t represents the time (in hours).A. What is the constant of proportionality? _____ miles per hour

B. How far will a car travel in 3 hours? _______ miles

Answers

Answer: A. 45 miles per hour

B. 135 miles

Step-by-step explanation:

Given: The distance traveled by a car at a constant rate is proportional to the time spent driving.

In the equation $d=45t$ , d represents the distance (in miles) and t represents the time (in hours).

$\Rightarrow(d)/(t)=45\text{ miles per hour}$

⇒ The constant of proportionality=45 miles per hour.

Also, the distance traveled by car in 1 hour=45 miles

⇒ The distance traveled by car in 3 hours= $3*45=135\text{ miles}$

∴ A car will travel 135 hours in 3 hours.

It looks like the car is traveling 45mph so
A= 45 miles per hour
B: 45x3=135
B=135

What is 1.323 as a percent

Answers

1.323 as a percent is 132.3% because you take the decimal and move it two spaces to the right->

132.3% you have to move two times to the right from the decimal to make it a percent and if u want to make it a decimal than u move two places to the left. U could remember the rule by the drink of Dr.Pepper but its DP my teacher taught me that for a trick

Which graph represents a phase shift of pi/2 units right for the graph ofy = COS X?
A. y = csc x
B. y = sin x
C. y = cos(x+pi/2)
D. y = sec x

Answers

Answer is B y = sin x

Answer:

B. y = sin x

Step-by-step explanation:

A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice, he lost 10 1/4 pounds, and during the second week he lost another 3 1/2 pounds. How much did he weigh at that point?A: 182 1/3 lb
B: 181 1/2 lb
C: 182 5/12 lb
D: 183 2/3 lb

Help please?

Answers

We need to find the weight of a person at a certain period of time.

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

Initial weight of person = $170(2)/(3)$ pounds.

Weight gained = $25(5)/(12)$ pounds

Weight lost = $10(1)/(4)+3(1)/(2)$ pounds

So, weight of the person is

$170(2)/(3)+25(5)/(12)-(10(1)/(4)+3(1)/(2))\n =170+(2)/(3)+25+(5)/(12)-(10+(1)/(4)+3+(1)/(2))\n =195+(8+5)/(12)-13-(1+2)/(4)\n =182+(13)/(12)-(3)/(4)\n =182+(13-3)/(12)\n =182+(10)/(12)\n =182+(1)/(3)=182(1)/(3)$