MATHEMATICS HIGH SCHOOL

Solve for "z"
6=z/5.9

Answers

Answer 1

Answer: $6=(z)/(5.9) \ \ / *5.9 \n \n5.9\cdot 6=(z)/(\not5.9^1) \cdot \not5.9^1 \n \n35.4 = z$

Answer 2

Answer:

Hello there!

$6=(z)/(5.9) \n$

Multiply both sides by 5.9 to get rid of the denominator:

35.4=z

And that's our final answer.Hope that helps you!

~Just a felicitous girlie

#HaveAnAwesomeDay

$SilentNature :)$

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A pyramid has cross-sectional, taken parallel to its base that are?

Answers

They are similar.

sorry for reporting you by accident

Answer this: Solve for X
IMAGE below!

Answers

Answer:

x =22.5

Step-by-step explanation:

x+3x = 90

x and 3x are complementary so they add to 90 degrees

Combine like terms

4x =90

Divide each side by 4

4x/4 = 90/4

x =22.5

answer: x = 22.5

explanation:

as the 3x and x are on a straight line with the angle of 90° we know that

3x +x = 90

4x = 90

x = 22.5

Can yall help meee please

Answers

Answer:

$jupiters \: mass \: is \: approximatelty \: \n \boxed{{6 * 10}^(3) \: kg} \: times, \: \n more \: than \: mercurys \: mass$

Step-by-step explanation:

$............................................................... \n in \: other \: to \: get \: right \: ans \to \n you \: divide \: mass \: of \: jupiter \: by \: the \: mass \n \: of \: mercury : \: so \to \n ............................................................... \n jupiters \: mass = 1.898 { * 10}^(27) \: kg \n mercurys \: mass =3.3 * {10}^(23) \: kg \n their \: mass \: ratio \: is : \n = \frac{1.898 { * 10}^(27)}{3.3 * {10}^(23)} = 0.5751515152 * {10}^(4) = \n \boxed{5,751.515152} \n hence \: jupiters \: mass \: is \: approximatelty \: \n {6 * 10}^(3) \: times \: more \: than \: mercurys \: mass$

6x103 because it explains that it’s 6 times but 10 in 3 times.

67.935 in expanded form in fraction form after the decimal

Answers

Hello,

67.935=67+935/1000=67+187/200 = 67|187/200
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What is 0.24 as a fraction in lowest terms

Answers

The only answer for 0.24 as a fraction is 6/25

Using the following data, calculate the mean absolute deviation: 10 7 1 6 7 9 8 10 2 5

What is the mean absolute deviation for these data?
2
2.4
6.5
7