Find the GCF of the terms of the polynomial.26x² + 34x^4

A. x²
B. 26x²
C. 2x^4
D. 2x²

Answers

Answer 1
Answer: the answer choice is d because the the greatest exponent is 4 but you cant take 4 exponents out of 2 . Both numbers are divisible by 2 x^(2) which would make the answer 13+17 x^(2) 
Answer 2
Answer: 26x²: 13 · 2 · x · x
34x⁴: 17 · 2 · x · x

GCF: 2x²

26x² + 34⁴
2x²(13) + 2x²(17x²)
2x²(13 + 17x²)

The answer is equal to D.

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The product of two rationalnumber is (-20/40 ).If one ofthe number is (4/5), then the other number is _______

Answers

Answer:

The product of two rationalnumber is (-20/40 ).If one ofthe number is (4/5), then the other number is -5/8

4/5*-5/8 = -20/40

x= the number

4*x/5 =-20/40

4x*40 = -20*5

160x=-100

x=-100/160 = -5/8

A conference room is in the shape of a rectangle. Its floor has a length of (x − 4) meters and a width of (3x − 1) meters. The expression below represents the area of the floor of the room in square meters: (x − 4)(3x − 1) Which of the following simplified expressions represents the area of the floor of the conference room in square meters?

Answers

You have to foil. Times the first two: x(3x). Then times the outer two: x(-1). Then times the inner two: -4(3x). Finally, times the last two: -4(-1). Your equation would be 3x squared - 1x - 12x + 4. Therefore, the simplified answer is 3x^2 (3x to the second power) - 13x + 4.

Answer:

Simplified expressions which represents the area of the floor of the conference room in square meters is:

3x²-13x+4

Step-by-step explanation:

A conference room is in the shape of a rectangle.

Its floor has a length of (x − 4) meters and a width of (3x − 1) meters.

we know that Area of rectangle=Length×Breath

Area of floor of the room=(x-4)(3x-1)

(x-4)(3x-1)=x(3x-1)-4(3x-1) (Distributive property)

               = 3x²-x-12x+4   (Distributive property)

              = 3x²-13x+4   (On combining the like terms)

Hence, simplified expressions which represents the area of the floor of the conference room in square meters is:

3x²-13x+4

Write Standard from
y=-9/5x+3 ??

Answers

Standard\ form:\nax+by=c\n\ny=-(9)/(5)x+3\n\n\boxed{(9)/(5)x+y=3}

Standard form is:      9/5x+y=3

Advance tickets for a school play went on sale. The price of each student ticket was $4 and everyone else paid $5. On the first day, no more than $80 in tickets were sold. Describe and explain the possible values of s, the number of student tickets sold, and e, the number of tickets sold to nonstudents.

Answers

Answer:

sample response:

Step-by-step explanation:

Partial and negative tickets cannot be sold, so the minimum number values of e and s are 0. If s = 0, then e = 16, and if e = 0, then s = 20. Therefore, the values of s are whole numbers from 0 to 20 and the values of e are whole numbers between 0 and 16. The greatest number of student tickets sold was 20 and the greatest number of nonstudent tickets sold was 16.

89 tickets were sold in total.

Write the equation y= 5x-11 in standard form

Answers

-55 =y. I hope that helped

Whats the equation of the line that passes through (3,8) and (6,0)

Answers

To begin this problem, we need to use the two points that we are given to find the slope of the line. Slope is defined as the change in y values divided by the change in x values, or rise/run, and is represented by the variable m.

m = (y1-y2)/(x1-x2) = (8-0)/(3-6) = 8/(-3) = -8/3

Now, we can use the slope and one of the points from our given values to create an equation of the line in point-slope form.

y = m(x-h) + k, where a point on the line is (h,k)

y = -8/3(x - 3) + 8

Now, we can distribute our slope and simplify through addition.

y = -8/3x + 8 + 8

y = -8/3x + 16

Therefore, your answer is y = -8/3x + 16.

Hope this helps!

EQUATION OF A LINE IS Y-Y¹ =m(X-X¹)
WHERE M IS SLOPE
SO
EQUATION OF LINE IS Y-0={(8-0)/(3-6)}[X-6]

¶¶ Y= (-8/3)(X-6)
HERE YOU GO---- {3Y+8X-48=0}

HOPE THIS IS HELPFUL