How do you simplify 5^log5x

Answers

Answer 1

Answer: $5^(log_5x)=x;\ D:x\in\mathbb{R^+}\n\n\n\n5^(log_5x)=a\n\nlog_55^(log_5x)=log_5a\n\nlog_5x\cdot log_55=log_5a\n\nlog_5x=log_5a\iff x=a\Rightarrow5^(log_5x)=x$

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What is the product of 379 and 8

Answers

You just take 378 and multiply it by 8 and you get 3032

the product of 379 and 8 is 3032, that other answer was wrong they answered with the sum (addition) not the product (multiplication)

Find the missing side of the triangle. Round to nearest tenth if needed.

Answers

Answer:

6.7

Step-by-step explanation:

6.7 because 3.4 is way to small 7.9 would be close but not the right length and 8.5 is way too long to be on the bottom.

Hope this help stay home stay safe.

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For each minute a race car traveled, the pit crew measured the speed of the car in miles per hour.Which type of graph would best display this information?

A.line plot

B.line graph

C.bar graph

D.histogram

Answers

I would represent that with a line graph.

What is the domain of the following parabola? u-shaped graph that opens down with a vertex of 2, 3

x ≥ 2
x ≤ −1
y ≤ 3

Answers

First we have to understand what the domain is. In a nutshell the domain is the set of all x values that are represented in any given graph. In this case we do not have a graph but we have the vertex. The x value is 2, therefore: x ≥ 2.

I hope this helps, Regards.

What is if g(x,y,z) = x + y and S is the first octant portion of the plane 2x + 3y + z = 6 ?

Answers

The question asks for the value of $I=\int\int_Sx+y\textrm{ }dS$ where $S=\{(x,y,z)\mid2x+3z+y=6,x\ge0,y\ge0,z\ge0\}$ .

First let's look at what that surface looks like.

Letting $y=z=0$ yields $x=3$
Letting $x=z=0$ yields $y=2$
Letting $x=y=0$ yields $z=6$

Therefore $S$ is the area of the triangle defined by the three points $(3,0,0),(0,2,0),(0,0,6)$ .

We can thus reformulate the integral as $I=\int_(z=0)^6\int_(x=0)^(6-z)x+ydxdz$ .

By definition on the plane $y=\frac{6-2x-z}3$ thus $I=\int_(z=0)^6\int_(x=0)^(6-z)x+\frac{6-2x-z}3dxdz=\int_(z=0)^6\int_(x=0)^(6-z)2+\frac x3-\frac z3 dxdz$

$I=\int_(z=0)^6\left[2x+\frac{x^2}6-\frac{zx}3\right]_(x=0)^(6-z)dz=\int_(z=0)^62(6-z)+\frac{(6-z)^2}6-\frac{z(6-z)}3\right]dz$

$I=\int_(z=0)^6\frac{z^2}2-6z+18=\left[\frac{z^ 3}6-3z^2+18z\right]_(z=0)^6=36-108+108$

Hence $\boxed{I=\int\int_Sx+y\textrm{ }dS=36}$

A kids’ movie ticket costs $5.25.Type your answers in the boxes below.

a. One day, 200 kids’ tickets were purchased. What was the total cost of those tickets?

----------------- answer

Answers

Answer:

$1,050

Step-by-step explanation:

Simply multiply the cost per kid ticket and number of kids:

$5.25 x 200 = $1,050

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