What is x for number 14.

Answers

Answer 1

Answer:
It's a right triangle. So

(x²) + (10²) = (7+x)²

x² + 100 = 49 + x² + 14x

That may look ugly, but I'm pretty sure you can handle it from this point.

Wow ! I just noticed that you can subtract x² from each side
and not even have to mess with it again.

Answer 2

Answer:
x^2 $(x+7)^2=x^2+10^2x^2+14x+49=x^2+10014x+49=10014x=51x=3.64$

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And an equation of the line. Write the equation using function notation.Through (-5.-9), parallel to 2x + 5y = 7

Answers

Answer:

F(x) = - 2/5x - 11

Step-by-step explanation:

F(x) = - 2/5x + c

-9 = - 2/5(-5) + c

-9 = 2 + c

- 11= c

F(x) = - 2/5x - 11

What two numbers add up to 1 but multiply to -2

Answers

Negative 1 and positive 2 will add up to 1 and will multiply to -2.

-1 + 2 = 1

-1 * 2 = -2

The two numbers are -1 and 2.

At the movie theatre, child admission is $6.10 and adult admission is $9.20 . On Thursday, three times as many adult tickets as child tickets were sold, for a total sales of $707.70 . How many child tickets were sold that day?

Answers

Answer:

21 child tickets.

Step-by-step explanation:

Let x represent number of adult tickets and y represent number of child tickets.

We have been given that on Thursday, three times as many adult tickets as child tickets were sold. We can represent this information in an equation as:

$x=3y...(1)$

We have been given that at a the movie theater, child admission is $6.10 and adult admission is $9.20.The all tickets were sold for a total of $707.70. We can represent this information in an equation as:

$9.20x+6.10y=707.70...(2)$

Upon substituting equation (1) in equation (2), we will get:

$9.20(3y)+6.10y=707.70$

$27.6y+6.10y=707.70$

$33.7y=707.70$

$(33.7y)/(33.7)=(707.70)/(33.7)$

$y=21$

Therefore, 21 child tickets were sold on Thursday.

Eduardo tiene un terreno cuadrado, su frente está determinado por las coordenadasb (2,3) y (18,3). Si se desea realizar una construcción dentro del terreno, para lo cual se necesita poner una malla a su alrededor. ¿Cuántos metros de malla necesita comprar Eduardo para rodear el terreno completo?

Answers

Answer:

Eduardo necesita 64 metros de malla para cercar el terreno completo.

Step-by-step explanation:

Por Geometría recordamos que un cuadrado es una figura geométrica con cuatro lados de igual longitud y cuatro ángulos internos rectos. Hallamos la longitud del lado frontal por la Ecuación General de la Longitud de un Segmento de Recta:

$l = \sqrt{(x_(B)-x_(A))^(2)+(y_(B)-y_(A))^(2)}$ (Eq. 1)

Donde:

$x_(A)$ , $x_(B)$ - Componentes independientes inicial y final, medidos en metros.

$y_(A)$ , $y_(B)$ - Componentes dependientes inicial y final, medidos en metros.

$l$ - Longitud del segmento de recta, medidos en metros.

Si conocemos que $A(x,y) = (2\,m, 3\,m)$ y $B(x, y) = (18\,m,3\,m)$ , entonces la longitud del segmento de recta es:

$l =\sqrt{(18\,m-2\,m)^(2)+(3\,m-3\,m)^(2)}$

$l = 16\,m$

El metraje requerido para cercar el terreno es el perímetro de ese lugar, es decir, cuatro veces la longitud del lado frontal. Es decir:

$p = 4\cdot l$ (Eq. 2)

Donde $p$ es el perímetro del cuadrado, medido en metros.

Si $l = 16\,m$ , entonces el metraje requerdo para cercar el terreno es:

$p = 4\cdot (16\,m)$

$p = 64\,m$

Eduardo necesita 64 metros de malla para cercar el terreno completo.

What is -6x-4+(2x+-8

Answers

Answer:

-4x+4

Step-by-step explanation:

How many diagnals can you draw from a single vertex of a 35-gon?

Answers

Well let's see. Your -gon has 35 vertexies. You use one of them
to start all the diagnals from. That leaves (35 - 1) = 34 others
that could be the other end of a diagnal.

So there must be 34 possible diagnals.

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