PLEASE HELP!!!! 1. The stem-and-leaf plot shows weights of dogs, in pounds, in a dog competition.

How many of the dogs weigh at least 50 lb?
PLEASE HELP!!!! 1. The stem-and-leaf plot shows weights of dogs, - 1

Answers

Answer 1
Answer: 1 Dog weighs 50lbs because in the stem and leaf plot it says there is a 50lbs dog and a 55lbs dog.

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Which properties can be used to solve 7y − 15 = −29? Select all that apply. A. Identity Property of Multiplication B. Addition Property of Equality C. Distributive Property D. Inverse Property of Multiplication E. Commutative Property of Addition
3(x - 4) + 6 = 5(x - 1) + 1 solve for x and show work
URGENT!!!!! I NEED HELP AYUDA
(15x-5) 35 Geometry set-up Equation 35+(x-5) X= m/WIN
Solve the system x+y=54 x-5y=0 A. (-45, -9) B.(45, 9) C. (9, 45) D. (45, 9)

What is the value of this expression when c=4 c^3/2

Answers

Answer:

8

Step-by-step explanation:

c ^ 3/2

Let c = 4

4 ^ 3/2

Rewriting 4 as 2^2

2 ^2 ^3/2

We know that a^b^c = a^(b*c)

2 ^(2*3/2)

2 ^3

8

therightansweris8.

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3. Suppose you invest $5,000 in a continuously compounded interest account. After four years,your account balance was $6,230. What interest rate were you earning on this account?
Convert your answer to percent and round your answer to the nearest tenth(one decimal
place).

Answers

Step-by-step explanation:

FV = PV e^(rt)

6230 = 5000 e^(4 r)   <====solve for 'r' = 5.5 %

Which expression gives the x-coordinate of the solution of the system?

Answers

the answer is option b

A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?3

4

6

7

Answers

He needs 5 pounds of cashews

Answer:

ZE ANSWER IS 3

Step-by-step explanation:

How many feet in a rod?



2.5

4.5

8.5

16.5

Answers

1 rod is equal to 16.5 feet

If 4/3x - 1/2 = 0 then x=

Answers

4/3x - 1/2 = 0   Given
4/3x = 1/2   Add 1/2 to both sides
x = 3/8   Multiply each side by 3/4

It is important when doing equations like these to remember that you need to multiply by the reciprocal of the fraction, not divide by it. For example, if another you have 1/2x = 1, you need to multiply by 2/1 or 2, not divide by 1/2.