MATHEMATICS HIGH SCHOOL

Which equation represents a line that intersects the line 2y − 4x = 3?A. -2y + 4x = 1
B. 3y − 6x = 6.5
C. y − 2x = 3
D. -2y − 4x = 3

Answers

Answer 1
Answer: Convert all the equations to slope-intercept form:

\hbox{the given line:} \n 2y-4x=3 \ \ \ |+4x \n2y=4x+3 \ \ \ |/ 2 \ny=2x+(3)/(2) \n \nA. \n-2y+4x=1 \ \ \ |-4x \n-2y=-4x+1 \ \ \ |/ (-2) \ny=2x-(1)/(2) \n \nB. \n3y-6x=6.5 \ \ \ |+6x \n3y=6x+6.5 \ \ \ |/ 3 \ny=2x+(6.5)/(3)

C. \ny-2x=3 \ \ \ |+2x \ny=2x+3 \n \nD. \n-2y-4x=3 \ \ \ |+4x \n-2y=4x+3 \ \ \ \|/ (-2) \ny=-2x-(3)/(2)

If two lines have the same slope, they're parallel and don't intersect.
The slope of the given line is 2.
The slopes of lines A, B and C are also equal to 2, so they are all parallel.
The slope of line D is -2, so it intersects the given line.
The answer is D.

Related Questions

What is an equation of the line that passes through the points (3,1)is parallel to the line 2X+3Y=24?
Plz help on matching i don't have the t-84 calculator so i cant do it
A snorkeler dives for a shell on a reef. After entering the water, the diver descends 11/3 feet in one second. Write an equation that models the diver's position with respect to time.
Question 12 of 22What is sin 60°? O A. OB. O C. 1 O D. 2 1 - √2 OE 1/1/20 OF. √3
Which of the following values are solutions to the inequality -5 ≤ x + 5? A) -7 B) -10 C) -3

Write 5.2 as the quotient of two integers A...11/3
B...21/5
C...26/5
D...51/10

Answers

Answer:

C) (26)/(5) = 5.2.

Step-by-step explanation:

Given : Number 5.2

To find : write 5.2 as the quotient of two integers.

Solution : We have given Number 5.2

For  (11)/(3) = 3.666.

For  (21)/(5) = 4.2.

For  (26)/(5) = 5.2.

For  (51)/(10) = 5.1.

So, 5.2 is quotient of 26 and 5 integers.

Therefore, C) (26)/(5) = 5.2.
it would be C because what i did A. 11 divided by 3=3.666666666666666666 
B.21 divided by 5=4.2  C. 26 divided by 5= 5.2 D. 51 divided by 10=5.1 we want 5.2 and C = 5.2

A physics lab group was conducting an experiment to determine the length of a spring when different objects of varying weight were hung from it. After testing ten different objects, the group calculated the following linear regression where x is the weight of the object in ounces and h(x) is the length of the spring in centimeters: h(x)= 2.3x+15.5. What does y-intercept of this equation indicate about the relationship between object weight and the length of the spring?1) When there is no object on the spring, its length is 2.3 cm
2) When there is no object on the spring, its length 15.5 cm
3) For every ounce of weight, the spring length increases by 2.3 cm
4) For every ounce of weight, the spring length increases by 1535 cm

Answers

2). The length of the spring is 15.5 cm, and that's how it hangs
when there's no weight on it.

In the equation, 'x' is the weight of the object. If there's no object, then
x = 0 and h(x) = 15.5 .
15.5 is the answer
man...that was pretty hard

If point (a,b) lies on the graph y=f(x), the graph of f^-1 (x) must contain point:

Answers

By the definition of inverse function,the point (a,b) lies on the graph \bold{y= f(x).} So, (b,a) must be lies on the graph of \bold{y=f^(-1) (x)}.

Given:

Point (a,b) lies on the graph y= f(x).

Find:

The graph of  \bold{y=f^(-1) (x)} must contain that point.

As per the definition of inverse function, if two one-to-one functions f(x) and g(x). If (f∘g)(x)=x and (g∘f)(x)=x. Then, we say that f(x) and g(x) are inverses of each other.

\bold{f=\{ (x,y):x\epsilon R,y\epsilon R\}}

Then, its inverse is defined as

\bold{f^(-1) =\{ (y,x):x\epsilon R,y\epsilon R\}}

Therefore, we have to interchange x and y-coordinate of the points which lies on the function f to get f⁻¹.

Thus, the point (a,b) lies on the graph y= f(x). So, (b,a) must be lies on the graph of y=f^(-1) (x).

For more details, prefer this link :

brainly.com/question/10300045

Given:

Point (a,b) lies on the graph y=f(x).

To find:

The point which is must be lies on the graph of y=f^(-1)(x).

Solution:

According to the definition of an inverse function, if a function is defined as

f=\{(x,y):x\in R,y\in R\}

then, its inverse is defined as

f^(-1)=\{(y,x):x\in R,y\in R\}

It means, we have to interchange x and y-coordinate of the points which lies on the function f to get f⁻¹.

We have a point (a,b) lies on the graph y=f(x). So, (b,a) must be lies on the graph of y=f^(-1)(x).

Therefore, the correct option is (1).

Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x).

Answers

Substitute the two functions according to a given condition of function:
f(x) - g(x) = 3x² + x - 3 - (x² - 5x + 1)
= 3x² + x - 3 - x² + 5x - 1
= 2x² + 6x - 4  or  2(x² + 3x - 2)
f(x) - g(x) = 3x² + x - 3 - (x² - 5x + 1)
f(x) - g(x) = 3x² + x - 3 - x² + 5x - 1
f(x) - g(x) = 3x² - x² + x + 5x - 3 - 1
f(x) - g(x) = 2x² + 6x - 4

All four sided polygons are quadrilaterals

Answers

This is a true statement (:

A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The point (-7, ______) lies on this circle.How would I do this?

Answers

circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=\sqrt{(x2-x1)^(2)+(y2-y1)^(2)}
points (-3,2) and (1,5)
D=\sqrt{(1-(-3))^(2)+(5-2)^(2)}
D=\sqrt{(4)^(2)+(3)^(2)}
D=√(16+9)
D=√(25)
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle



radius=5 units
the points (-7,5) and (-7,1) lie on this circle
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