a bottle contains 12 red marbles and 8 blue marbles. A marble is chosen at random and not replaced. Then a second marble is chosen at random. Determine the probability that the two marbles are not the same color.

Answers

Answer 1
Answer: P(A)= (12)/(20) \cdot (8)/(19) + (8)/(20) \cdot (12)/(19)= (12\cdot8)/(20\cdot19) \cdot2=(12\cdot4)/(5\cdot19)= (48)/(95)

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Blue beads are 5 millimeters long and red beads are 10 millimeters long. How long is the basic bead pattern (brrrr b) in millimeters?​

Answers

Answer:

50

Step-by-step explanation:

  • blue=5
  • r⁴=40
  • B=5
  • totally of 50milimeters

Answer: 50 millimeters

mrs susan bought 1/8 8m of curtain choth she used 3/5 m to make a curtain for the living room window how many meters of choth we're not use ​

Answers

Answer:

(19)/(40)

Step-by-step explanation:

The computation of the meters of cloth that were not use is shown below:

= Used for making a curtain - purchase of curtain cloth

= (3)/(5) - (1)/(8)\n\n= (24 - 5)/(40)  \n\n= (19)/(40)

Hence, the meters of cloth that was not used is (19)/(40)

Find a solution to the inequality x > 7.

Answers

you must isolate the x in order you must divide both of each sides of the inequality  by the other variable or coefficients.
Here, x > 7 itself is a solution. It represents x must be less than the 7

Hope this helps!

4x²-32=0 by any method

Answers

4x²=32

x²=32/4

x²=8

x=√8

LOOK, 25 POINTS Y'ALLthis is a logic-math combo question that was from my 5th grade math book (singapore math). just for fun. I never solved it on my own. MUST SHOW ALL WORK

there are 4 single digit whole numbers represented by A, B, C, D. They are all different numbers.

when you multiply ABCD with D, you get DCBA

solve for the values of A,B,C, and D

(note: if A=2,B=3,C=4,D=5 then ABCD=2,345, but that is not the solution)

Show all work and do not copy

Answers

To start, ABCD(D)=DCBA means that D×A=D because they're all single digit numbers and since nothing carries over to make DCBA a 5 digit number A must be 1. If A is 1 for ABCD(D)=DCBA that would mean D^2 is a number ending in 1 so the only possibility for D is 9. Since D is 9, D×B has to be less than 10 because we know nothing carries over to the D×A (9×1) so B has to be 0. So far we have 10*9(9)=9*01 and since D×D (9×9) is 81 we need a number divisible by 9 that ends with 2 to add to the 8 digit which the only possibility is 72 from 8×9. SO A=1, B=0, C=8, D=9
1089(9)=9801

Graph the inequalityz < 6
over the restricted domain
z =w
(the set of whole numbers).

Answers

whole numbers is positive counting numbers including zero
0,1,2,3,4,5,6,7,8, etc

z<6
0,1,2,3,4,5 are the solution set
so just have those numbers