An unbalanced force of 25 N, E, is applied to a 12-kg mass. What is the acceleration given to the mass?

Answers

Answer 1

Answer: Newton's second law states: $F=m*a$

F stands for force
m stands for mass
a stands for acceleration

Get a alone.

$(F)/(m)=a$ or $a=(F)/(m)$

Plug in the values you have.

$a=(25N)/(12kg)$

This gives:

$a = 2.5(m)/(s^2)E$

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at a pressure 44 kpa the gas in a cylinder has a volume of 29 liters assuming temperature remains the same,if the volume of the gas is decreased to 4liters what is the new pressure?kpa

Answers

Assuming the gas is ideal, the ideal gas law can be used. To make things simpler, Boyle's law can also be used because it denotes the inverse relationship between pressure and volume at constant temperature. The solution to be used is as follows

P1V1 = P2V2
(44)(29) = P2(4)
P2 = 319 KPa

Explain why solar energy is considered an inexhaustible source of energy

Answers

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of it we use or don't use.

-- The sun is not expected to quit shining on us, or to change its rate of energy
output, at any time within the next several many human lifetimes.

Solar energy is going to keep arriving here, continuously, at the same rate,
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Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12125 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 4.2 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Answers

Answer:

$(Ie)/(lm) = 1.10*10^(-3)$

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

$(Ie)/(lm) = (-N)/((nf-ni))$

$(Ie)/(lm) = (-(-4.2))/((12125 - (8325)))$

$(Ie)/(lm) = 1.10*10^(-3)$

Answer: $1.105* 10^(-3)$

Explanation:

Given

Initial angular speed of engine( $\omega _E$ )=8325 rpm

Final angular speed of engine( $\omega _E_f$ )=12125 rpm

Initial angular speed of Motorcycle( $\omega _M$ )=0 rpm

Final angular speed of engine( $\omega _M_f$ )=4.2 rpm

as there is no external torque therefore angular momentum remains conserved

$I_E\omega _E+I_M\omega _M=I_E\omega _E_f+I_M\omega _M_f$

$I_E\omega _E+=I_E\omega _E_f+I_M\omega _M_f$

$I_E\left ( \omega _E-\omega _E_f\right )=I_M\omega _M_f$

$(I_E)/(I_M)=(\omega _M_f)/(\omega _E-\omega _E_f)$

$(I_E)/(I_M)=(-4.2)/(8325-12125)=0.0011052\approx 1.105* 10^(-3)$

How did Thomson know atoms had an overall neutral charge?He knew there were negative electrons but he came to the conclusion that the rest of the atom was positively charged, why was this? How did he know it would be positively charged?