Convert to vertex form.
y=2x^2+14x-4

Answers

Answer 1

Answer: $y=2x^2+14x-4\n\na=2;\ b=14;\ c=-4\n\nvertex\ form:y=a(x-h)^2+k\n\nwhere:h=(-b)/(2a)\ and\ k=(-(b^2-4ac))/(4a)\n\nh=-(-14)/(2\cdot2)=-(7)/(2)\n\nk=(-(14^2-4\cdot2\cdot(-4)))/(4\cdot2)=(-(196+32))/(8)=(-228)/(8)=-(57)/(2)\n\n\nAnswer:y=2(x+(7)/(2))^2-(57)/(2)$

Answer 2

Answer: $To \ convert \ the \ standard \ form \ y = ax^2 + bx + c \ of \ a \ function \ into \ vertex \n \nform \ y = a(x - h)^2 + k \n \n Here \ the \ point \ (h, k) \ is \ called \ as \ vertex \n \n h=(-b)/(2a) , \ \ \ \ k= c - (b^2)/(4a)$

$y=2x^2+14x-4 \n \na=2 ,\ b=14 , \ c=-4 \n \n h=(-14)/(2*2)=-(14)/(4)=-3.5 \n \nk= -4 - (14^2)/(4\cdot 2)=-4-(196)/(8)=-4-24.5=-28.5 \n \n y=2(x+3.5)^2 -28.5$

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Can you guys help me out with number 13

Answers

$r=1.6w+2\n 1.6w=r-2\n w=0.625r-1.25 \Rightarrow D$

Multiplies to -0.72 and adds to 0.6

Answers

Multiplies to -0.72 = - 0.6 * (1.2).

Adds to 0.6 =

-0.6 + (1.2) = 1.2 - 0.6 = 0.6.

Hence the two numbers are -0.6 and 1.2.

What substitution should be used to rewrite 6(x + 5)2 + 5(x + 5) – 4 = 0 as a quadratic equation? u = (x + 5) u = (x – 5) u = (x + 5)2 u = (x – 5)2

Answers

6(x+5)² + 5(x+5)-4 = 0

(x+5)(x+5) = x(x+5)+5(x+5) = x² + 5x + 5x + 25 = x² + 10x + 25

6(x²+10x+25) + 5(x+5) - 4 = 0
6x² + 60x + 150 + 5x + 25 - 4 = 0
6x² + 60x + 5x + 150 + 25 - 4 = 0
6x² + 65x + 171 = 0

u = (x + 5)

Answer:

A: u = (x + 5)

Edg 2020

Which of the following is a solution of z^5 = 1 + √3 i? 5√2 (cos150° + isin150°)
5√2 (cos156° + isin156°)
5√2 (cos174° + isin174°)
5√2 (cos204° + isin204°)

Please show me how to work it out.

Answers

Answer:

Option 2 is right

Step-by-step explanation:

Given that

$z^5=1+√(3) i$

We can write this in polar form with modulus and radius

$|z^5|= √(1+3) =2\ntan of Angle t =√(3) \n$

Hence angle = 60 degrees and

$|z^5|= 2(cos60+isin60)$

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360

Using Demoivre theorem we get 5th root would be

5th root of 2 multiplied by 1/5 th of 60, 420, 780,....

$z= \sqrt[5]{2} (cos12+isin12)\nz=\sqrt[5]{2} (cos84+isin84)\n\nz=\sqrt[5]{2} (cos156+isin156)\n\nz=\sqrt[5]{2} (cos228+isin228)\n\nz=\sqrt[5]{2} (cos300+isin300)\n$

Out of these only 2nd option suits our answer

Hence answer is Option 2.

Forty-two people at a Fourth of July picnic equally shared a watermelon that weighed x pounds. What was the weight of each piece of watermelon shared at the picnic? a x/42
b 42/x
c 42x
d x * 42
this broke my head

Answers

Forty-two people at a Fourth of July picnic equally shared a watermelon that weighed x pounds. What was the weight of each piece of watermelon shared at the picnic?

a x/42

Which of the following girls will have the greatest percent of change in height if they each grow 3 inches over the summer?Girl Current Height
Ann 60 inches
Betty 62 inches
Carol 64 inches
Diana 66 inches

Answers

If you would like to know which of the girls will have the greatest percent of change in height, you can calculate this using the following steps:

x% of 60 inches is 63 inches
x% * 60 = 63
x/100 * 60 = 63
x = 63 * 100 / 60 = 105% ... 5%

y% * 62 = 65
y/100 * 62 = 65
y = 65 * 100 / 62 = 104.84% ... 4.84%

w% * 64 = 67
w/100 * 64 = 67
w = 67 * 100 / 64 = 104.69% ... 4.69%

z% * 66 = 69
z/100 * 66 = 69
z = 69 * 100 / 66 = 104.55% ... 4.55%

The correct result would be Ann (60 inches).

Answer:

ann 60 inches

Step-by-step explanation:

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