MATHEMATICS MIDDLE SCHOOL

3 times as much as the sum of 3-4 and 2-6.

Answers

Answer 1

Answer:

¹³/₄ or 3¹/₄ or 3.25

Further explanation

The Problem:

3 times as much as the sum of $(3)/(4)$ and $(2)/(6)$
Write an expression to match, and then solve.

The Process:

Here are some early expressions that need attention.

three-quarter is $\boxed{(3)/(4)}$
two-sixth is $\boxed{(2)/(6)}$
the sum of $(3)/(4) \ and \ (2)/(6)$ is $\boxed{(3)/(4) + (2)/(6)}$

Let us write an expression to match for3 times as much as the sum of $(3)/(4)$ and $(2)/(6)$

$\boxed{\boxed{ \ 3 * \bigg((3)/(4) + (2)/(6) \bigg) \ }}$

Let us calculate the operation in parentheses at first.

$(3)/(4) + (2)/(6)$

A least common multiple of 4 and 6 is 12. We use to equate the denominator.

$(3 * 3)/(4 * 3) + (2 * 2)/(6 * 2)$

$(9)/(12) + (4)/(12)$

$(13)/(12)$

And now we solve the full expression.

$\boxed{ \ = 3 * \bigg((3)/(4) + (2)/(6) \bigg) \ }$

$\boxed{ \ = 3 * (13)/(12) \ }$

We cross out 3 and 12 because they both can be divided.

$\boxed{ \ = 1 * 1(13)/(4) \ }$

$\boxed{\boxed{ \ = (13)/(4) \ }}$

In mixed fraction:

$\boxed{ \ (13)/(4) = \ ? \ }$

$\boxed{ \ = (12)/(4) + (1)/(4) \ }$

$\boxed{ \ = 3 + (1)/(4) \ }$

$\boxed{\boxed{ \ = 3(1)/(4) \ }}$

In decimal:

$\boxed{ \ 3(1)/(4) = \ ? \ }$

$\boxed{ \ = 3(1 * 25)/(4 * 25) \ }$

$\boxed{ \ = 3(25)/(100) \ }$

$\boxed{\boxed{ \ = 3.25 \ }}$

$\boxed{\boxed{ \ Thus, \ the \ result \ is \ (13)/(4) \ or \ 3(1)/(4) \ or \ 3.25 \ }}$

- - - - - - - - - -

Quick Steps:

Simplify $\boxed{(2)/(6) = (1)/(3)}$

$\boxed{ \ = 3 * \bigg((3)/(4) + (2)/(6) \bigg) \ }$

$\boxed{ \ = 3 * \bigg((3)/(4) + (1)/(3) \bigg) \ }$

$\boxed{ \ = 3 * \bigg((3 * 3)/(4 * 3) + (1 * 4)/(3 * 4) \bigg) \ }$

$\boxed{ \ = 3 * \bigg((9)/(12) + (4)/(12) \bigg) \ }$

$\boxed{ \ = 3 * (13)/(12) \ }$

$\boxed{\boxed{ \ = (13)/(4) \ }}$

$\boxed{\boxed{ \ = 3(1)/(4) \ }}$

$\boxed{\boxed{ \ = 3.25 \ }}$

Learn more

7 copies of the sum of 8 fifths and 4 brainly.com/question/961462
tex]\frac{2}{3}[/tex] of the product of $(3)/(8)$ and 16 brainly.com/question/961462
15 times as much as 1 fifth of 12 is brainly.com/question/348151

Keywords: 3 times, as much as, the sum of 3/4 and 2/6, write an expression to match, and then solve, the result, in mixed fraction, decimal, ¹³/₄ or 3¹/₄ or 3.25

Answer 2

Answer: 2 - 3 = -1 2 - 6 = -4 -4 + -1 = -5 -5 x 3 = ?

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What is 3.5/9 as a fraction

Answers

3.5 / 9

(35 / 10) /9

35 / 10 ÷ 9

35 / 10 × 1/9

35 / 90

5 into 35 is 7, and 5 into 90 is 18

7 / 18

So it is 35 / 90 or 7 / 18.

Macy walked and jogged a total of 4 1/9 miles in Central Park today. If she jogged a distance of 2 2/3 miles, how many miles did Macy walk?

Answers

6 7/9 of a mile is what she walked

A farmer wants to fence a section of land for a horse pasture. Fencing costs $27 per yard. How much will it cost to fence the pasture?

Answers

find the perimeter of the fence multiply by 27$ I'd give the answer but it's missing information

Answer:

what is it

Step-by-step explanation:

Which expression represents the polynomial −2x2−4x4+8x+x5−2x3 rewritten in descending order? A- −2x2−4x4+8x+x5−2x3
B- −4x4−2x2+8x+x5−2x3
C- −4x4−2x3−2x2+8x+x5
D- x5−4x4−2x3−2x2+8x
E- 8x+x5−2x2−2x3−4x4

Answers

For this case we have the following polynomial:

$P (x) = - 2x ^ 2-4x ^ 4 + 8x + x ^ 5-2x ^ 3$

By definition, a polynomial in its standard form is given by:

$f (x) = ax ^ n ... + bx ^ i + ... cx ^ 3 + dx ^ 2 + ex + f$

Where:

a, b, c, d, e, f: They are the coefficients of each term of the polynomial.

x: It is the variable

n, i, 3,2,1,0: They are the exponents of each term of the polynomial, where n is the exponent of greater degree.

In this case they ask us to order the given polynomial, in a descending way, that is, from greater to lesser degree.

So, we have:

$P (x) = x ^ 5-4x ^ 4-2x ^ 3-2x ^ 2 + 8x$

Thus, the polynomial in its descending form is given by:

$P (x) = x ^ 5-4x ^ 4-2x ^ 3-2x ^ 2 + 8x$

Answer:

Option D

Answer:

option D

Step-by-step explanation:

What is the relationship between angle 1 and angle 5

Answers

Answer:

○ b Corresponding Angles

Step-by-step explanation:

These two angles are a mirror,so they correspond.

I am joyous to assist you anytime.

Final answer:

Angle 1 and angle 5 are alternate interior angles with the same measure.

Explanation:

Angle 1 and angle 5 are alternate interior angles formed by a transversal line intersecting two parallel lines. Alternate interior angles are equal in measure, which means that angle 1 and angle 5 have the same measure. This relationship holds true regardless of the specific measurements of angle 1 and angle 5.

Learn more about Angles here:

brainly.com/question/33354646

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Six groups of students sell 162 balloons at the school carnival there are 3 students in each group if each student sells the same number of balloons how many. Balloons dose each student sell ?

Answers

so, there are six groups of 3 students each. This means that there are 18 students in total.

Each of these students sells the same about of balloons: so we can divide the total number of sold balloons; 162 by 18:

$(162)/(18)= (81)/(9)=9$

which means that each student sold 9 balloons!!!

Each student sell $\boxed{9{\text{ balloons}}}$ if there are six groups of 3 students.

Further Explanation:

Explanation:

Six groups of students sell 162 balloons at the school carnival.

There are 3 students in each group.

Each student sells the same number of balloons.

The total number of students can be obtained as follows,

$\begin{aligned}{\text{Number of students}} &= 3 * 6 \n&= 18 \n\end{aligned}$

Number of balloons each student sell can be obtained as follows,

$\begin{aligned}{\text{Number of balloon}} &= \frac{{162}}{{18}}\n&= 9\n\end{aligned}$

Each student sell $\boxed{9{\text{ balloons}}}$ if there are six groups of 3 students.

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Fraction and Ratio

Keywords: six groups, groups, students, sell, six, 162 balloons, school, carnival, 3 students, each group, school carnival, same, number of balloons, student sell, many balloons, 3 students in a group.

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