Solve for x: 2x^2+4x-16+=0

Answers

Answer 1

Answer: $2x^2+4x-16=0\ /:2\n \nx^2+2x-8=0\n \nx^2-2x+4x-8=0\n \nx(x-2)+4(x-2)=0\n \n(x-2)(x+4)=0\ \ \ \Leftrightarrow\ \ \ x-2=0\ \ \ \vee\ \ \ x+4=0\n \n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-4$

Answer 2

Answer: $2x^2+4x-16=0|:2\n x^2+2x-8=0\n \Delta=36\Rightarrow√(\Delta)=6\n x_1=(-b+√(\Delta))/(2a)\ \vee\ x_=(-b-√(\Delta))/(2a)\n x_1=2\ \vee\ x_2=-4$

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Answers

Answer:

12. Hope this helps!!!

Step-by-step explanation:

Solve for x in the equation X^2+2x+ 1 = 17x=-1+ V15
x=-17 17
X=-2+25
x=-12 13

Answers

Answer:

it would be the last answer

Step-by-step explanation:

Could some one please help with question 9b and 11

Answers

9b. a^4 +2a^2-8=0
factorise
(a^2 + 4)(a^2 - 2)=0
we then get two answers from the brackets
a^2=-4
a= sqrt(-4) or 2j
and the second bracket gives us a^2=2
a= sqrt(2)

11. First expand the brackets.
Ax^3 + Bx^2 - x^2 + Bx +Cx + D
then equate the coefficients, this basically means put all the x^3, x^2 etc values together.
so Ax^3=3x^3 so we know that A=3Then put the x^2 together, so Bx^2-x^2=-x^2 and rearranging this gives B=0
Next we do Bx+Cx = 2x and we know that B is 0 so we can get rid of it and know that C = 2.
finally we can see that D = -7

Ally is making a scale diagram of her classroom. She uses a scale factor of 3 centimeters per foot to draw the diagram. The actual length of the classroom is 18 feet, and its width is 20 feet. What is the area of the scale drawing of the classroom?

Answers

Answer: $3240\ cm^2$

Step-by-step explanation:

Given: The actual length of the classroom= 18 feet

The actual width of the classroom= 20 feet

Scale factor =3 centimeters per foot

i.e. 1 foot = 3 cm

Therefore, The length of the classroom in drawing= $3*18=54\ feet$

The width of the classroom in drawing= $3*20=60\ cm$

Now, the area of the scale drawing of the classroom :-

$l* w=54*60=3240\ cm^2$

Hence, the area of the scale drawing of the classroom = $3240\ cm^2$

Answer:

3240 cm. sq. is your answer

4 Algebra problems, can I please get some help? (With steps to solve each one!)

Answers

a) a³b²   c a
------- x -----   ÷ -----
   c²d² ab c²d³

First perform multiplication:

(a³b²c / abc²d²) ÷ a / c²d³

In dividing fractions. Get the reciprocal of the 2nd fraction and multiply it to the 1st fraction.

a/c²d³ is the 2nd fraction. Its reciprocal is c²d³/a

So,
a³b²c c²d³ a³b²c³d³
------------ x   --------- = -------------- = abcd *cancel out like terms
abc²d² a a²bc²d²

b) (6x / 4x -16) ÷ (4x / x² -16)
(6x / 4x-16) × (x²-16 / 4x)
6x(x² - 16) / 4x(4x-16)
6x³ - 96 / 16x² - 64x

c) 3x² - 6x x + 3x² *use distributive property of multiplication
--------------- × -------------
  3x + 1 x² -4x + 4

3x² (x+3x²) - 6x (x + 3x²)   ⇒   3x³ + 9x⁴ - 6x² - 18x³
3x (x² - 4x + 4) + 1(x² -4x +4) ⇒ 3x³ -12x² + 12x + x² -4x + 4

  9x⁴ + 3x³ - 18x³ - 6x²   ⇒   9x⁴ - 15x³ - 6x²
3x³ - 12x² + x² + 12x - 4x + 4   ⇒ 3x³ - 11x² + 8x + 4

d) 2x² - 10x + 12 2 + x
---------------------- × -----------
x² - 4   3 - x

2(2x² - 10x + 12) + x (2x² - 10x + 12) ⇒ 4x² - 20x + 24 + 2x³ -10x² + 12x
3(x² - 4) - x(x² -4) 3x² - 12 - x³ + 4x

2x³ + 4x² - 10x² - 20x + 12x + 24 ⇒ 2x³ - 6x² - 8x + 24
-x³ + 3x² + 4x - 12 -x³ + 3x² + 4x - 12

I NEED HELP ASAP!!!Question: Which equation applies the associative property of multiplication?

Answers

i’m not 100% but from what i know i think it’s (C.)

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